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Integer_TRS_Innermost 2019-03-21 04.53 pair #429994937
details
property
value
status
complete
benchmark
10.itrs
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n136.star.cs.uiowa.edu
space
Mixed_ITRS_2014
run statistics
property
value
solver
Ctrl
configuration
Itrs
runtime (wallclock)
0.274169 seconds
cpu usage
0.279241
user time
0.157691
system time
0.12155
max virtual memory
113176.0
max residence set size
8652.0
stage attributes
key
value
starexec-result
YES
output
0.00/0.27 YES 0.00/0.27 0.00/0.27 DP problem for innermost termination. 0.00/0.27 P = 0.00/0.27 eval#(x) -> eval#(x / 2) [x > 0 && not(x = 0) && x % 2 = 0] 0.00/0.27 eval#(I0) -> eval#(I0 - 1) [I0 > 0 && not(I0 = 0) && I0 % 2 > 0] 0.00/0.27 R = 0.00/0.27 eval(x) -> eval(x / 2) [x > 0 && not(x = 0) && x % 2 = 0] 0.00/0.27 eval(I0) -> eval(I0 - 1) [I0 > 0 && not(I0 = 0) && I0 % 2 > 0] 0.00/0.27 0.00/0.27 We use the reverse value criterion with the projection function NU: 0.00/0.27 NU[eval#(z1)] = z1 0.00/0.27 0.00/0.27 This gives the following inequalities: 0.00/0.27 x > 0 && not(x = 0) && x % 2 = 0 ==> x > x / 2 with x >= 0 0.00/0.27 I0 > 0 && not(I0 = 0) && I0 % 2 > 0 ==> I0 > I0 - 1 with I0 >= 0 0.00/0.27 0.00/0.27 All dependency pairs are strictly oriented, so the entire dependency pair problem may be removed. 0.00/3.25 EOF
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