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Integer_TRS_Innermost 2019-03-21 04.53 pair #429995145
details
property
value
status
complete
benchmark
round.itrs
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n019.star.cs.uiowa.edu
space
Mixed_ITRS_2014
run statistics
property
value
solver
Ctrl
configuration
Itrs
runtime (wallclock)
0.154026 seconds
cpu usage
0.157155
user time
0.093145
system time
0.06401
max virtual memory
113176.0
max residence set size
7768.0
stage attributes
key
value
starexec-result
MAYBE
output
0.00/0.15 MAYBE 0.00/0.15 0.00/0.15 DP problem for innermost termination. 0.00/0.15 P = 0.00/0.15 f#(I1, y) -> f#(I1, round(I1)) [I1 >= 1 && y = I1 - 1] 0.00/0.15 f#(I1, y) -> round#(I1) [I1 >= 1 && y = I1 - 1] 0.00/0.15 R = 0.00/0.15 round(x) -> x + 1 0.00/0.15 round(I0) -> I0 0.00/0.15 f(I1, y) -> f(I1, round(I1)) [I1 >= 1 && y = I1 - 1] 0.00/0.15 0.00/0.15 The dependency graph for this problem is: 0.00/0.15 0 -> 0, 1 0.00/0.15 1 -> 0.00/0.15 Where: 0.00/0.15 0) f#(I1, y) -> f#(I1, round(I1)) [I1 >= 1 && y = I1 - 1] 0.00/0.15 1) f#(I1, y) -> round#(I1) [I1 >= 1 && y = I1 - 1] 0.00/0.15 0.00/0.15 We have the following SCCs. 0.00/0.15 { 0 } 0.00/0.15 0.00/0.15 DP problem for innermost termination. 0.00/0.15 P = 0.00/0.15 f#(I1, y) -> f#(I1, round(I1)) [I1 >= 1 && y = I1 - 1] 0.00/0.15 R = 0.00/0.15 round(x) -> x + 1 0.00/0.15 round(I0) -> I0 0.00/0.15 f(I1, y) -> f(I1, round(I1)) [I1 >= 1 && y = I1 - 1] 0.00/0.15 0.00/3.13 EOF
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return to Integer_TRS_Innermost 2019-03-21 04.53