details

property	value
status	complete
benchmark	AC29.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n152.star.cs.uiowa.edu
space	Mixed_AC_and_C

run statistics

property	value
solver	muterm 5.18
configuration	default
runtime (wallclock)	0.352854 seconds
cpu usage	0.386565
user time	0.20622
system time	0.180345
max virtual memory	433796.0
max residence set size	5384.0

stage attributes

key	value
starexec-result	YES

output

0.34/0.35 YES 0.34/0.35 0.34/0.35 Problem 1: 0.34/0.35 0.34/0.35 (VAR X Y Z x y) 0.34/0.35 (THEORY 0.34/0.35 (AC app) 0.34/0.35 (C max')) 0.34/0.35 (RULES 0.34/0.35 1 -> s(0) 0.34/0.35 2 -> s(1) 0.34/0.35 3 -> s(2) 0.34/0.35 4 -> s(3) 0.34/0.35 5 -> s(4) 0.34/0.35 6 -> s(5) 0.34/0.35 7 -> s(6) 0.34/0.35 8 -> s(7) 0.34/0.35 9 -> s(8) 0.34/0.35 app(empty,X) -> X 0.34/0.35 max(app(singl(x),Y)) -> max2(x,Y) 0.34/0.35 max(singl(x)) -> x 0.34/0.35 max'(0,x) -> x 0.34/0.35 max'(s(x),s(y)) -> s(max'(x,y)) 0.34/0.35 max2(x,app(singl(y),Z)) -> max2(max'(x,y),Z) 0.34/0.35 max2(x,empty) -> x 0.34/0.35 max2(x,singl(y)) -> max'(x,y) 0.34/0.35 ) 0.34/0.35 0.34/0.35 Problem 1: 0.34/0.35 0.34/0.35 Reduction Order Processor: 0.34/0.35 -> Rules: 0.34/0.35 1 -> s(0) 0.34/0.35 2 -> s(1) 0.34/0.35 3 -> s(2) 0.34/0.35 4 -> s(3) 0.34/0.35 5 -> s(4) 0.34/0.35 6 -> s(5) 0.34/0.35 7 -> s(6) 0.34/0.35 8 -> s(7) 0.34/0.35 9 -> s(8) 0.34/0.35 app(empty,X) -> X 0.34/0.35 max(app(singl(x),Y)) -> max2(x,Y) 0.34/0.35 max(singl(x)) -> x 0.34/0.35 max'(0,x) -> x 0.34/0.35 max'(s(x),s(y)) -> s(max'(x,y)) 0.34/0.35 max2(x,app(singl(y),Z)) -> max2(max'(x,y),Z) 0.34/0.35 max2(x,empty) -> x 0.34/0.35 max2(x,singl(y)) -> max'(x,y) 0.34/0.35 ->Interpretation type: 0.34/0.35 Linear 0.34/0.35 ->Coefficients: 0.34/0.35 Natural Numbers 0.34/0.35 ->Dimension: 0.34/0.35 1 0.34/0.35 ->Bound: 0.34/0.35 2 0.34/0.35 ->Interpretation: 0.34/0.35 0.34/0.35 [1] = 2 0.34/0.35 [2] = 2 0.34/0.35 [3] = 2 0.34/0.35 [4] = 2 0.34/0.35 [5] = 2 0.34/0.35 [6] = 2 0.34/0.35 [7] = 2 0.34/0.35 [8] = 2 0.34/0.35 [9] = 2 0.34/0.35 [app](X1,X2) = X1 + X2 0.34/0.35 [max](X) = 2.X + 1 0.34/0.35 [max'](X1,X2) = X1 + X2 0.34/0.35 [max2](X1,X2) = 2.X1 + 2.X2 + 2 0.34/0.35 [0] = 1 0.34/0.35 [empty] = 0 0.34/0.35 [s](X) = X 0.34/0.35 [singl](X) = X + 2 0.34/0.35 0.34/0.35 Problem 1: 0.34/0.35 0.34/0.35 Reduction Order Processor: 0.34/0.35 -> Rules: 0.34/0.35 2 -> s(1) 0.34/0.35 3 -> s(2) 0.34/0.35 4 -> s(3) 0.34/0.35 5 -> s(4) 0.34/0.35 6 -> s(5) 0.34/0.35 7 -> s(6) 0.34/0.35 8 -> s(7) 0.34/0.35 9 -> s(8) 0.34/0.35 app(empty,X) -> X 0.34/0.35 max(app(singl(x),Y)) -> max2(x,Y) 0.34/0.35 max(singl(x)) -> x 0.34/0.35 max'(0,x) -> x 0.34/0.35 max'(s(x),s(y)) -> s(max'(x,y)) 0.34/0.35 max2(x,app(singl(y),Z)) -> max2(max'(x,y),Z) 0.34/0.35 max2(x,empty) -> x 0.34/0.35 max2(x,singl(y)) -> max'(x,y) 0.34/0.35 ->Interpretation type: 0.34/0.35 Linear 0.34/0.35 ->Coefficients: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS_Equational 2019-03-21 05.09