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TRS_Equational 2019-03-21 05.09 pair #429997312
details
property
value
status
complete
benchmark
YWHM14_4.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
Mixed_AC
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.87421 seconds
cpu usage
4.05914
user time
3.9017
system time
0.157441
max virtual memory
1.8275288E7
max residence set size
293248.0
stage attributes
key
value
starexec-result
YES
output
3.98/1.83 YES 3.98/1.84 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.98/1.84 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.98/1.84 3.98/1.84 3.98/1.84 Termination of the given ETRS could be proven: 3.98/1.84 3.98/1.84 (0) ETRS 3.98/1.84 (1) EDirectTerminationProof [EQUIVALENT, 200 ms] 3.98/1.84 (2) YES 3.98/1.84 3.98/1.84 3.98/1.84 ---------------------------------------- 3.98/1.84 3.98/1.84 (0) 3.98/1.84 Obligation: 3.98/1.84 Equational rewrite system: 3.98/1.84 The TRS R consists of the following rules: 3.98/1.84 3.98/1.84 ac1(a, ac2(b, c)) -> ac1(b, f(ac2(a, c))) 3.98/1.84 ac2(a, ac1(b, c)) -> ac2(b, f(ac1(a, c))) 3.98/1.84 3.98/1.84 The set E consists of the following equations: 3.98/1.84 3.98/1.84 ac1(x, y) == ac1(y, x) 3.98/1.84 ac2(x, y) == ac2(y, x) 3.98/1.84 ac1(ac1(x, y), z) == ac1(x, ac1(y, z)) 3.98/1.84 ac2(ac2(x, y), z) == ac2(x, ac2(y, z)) 3.98/1.84 3.98/1.84 3.98/1.84 ---------------------------------------- 3.98/1.84 3.98/1.84 (1) EDirectTerminationProof (EQUIVALENT) 3.98/1.84 We use [DA_FALKE] with the following order to prove termination. 3.98/1.84 3.98/1.84 Precedence: 3.98/1.84 ac1_2 > b > a > c 3.98/1.84 ac1_2 > f_1 3.98/1.84 ac2_2 > f_1 3.98/1.84 3.98/1.84 3.98/1.84 Status: 3.98/1.84 ac1_2: flat status 3.98/1.84 ac2_2: flat status 3.98/1.84 3.98/1.84 3.98/1.84 3.98/1.84 ---------------------------------------- 3.98/1.84 3.98/1.84 (2) 3.98/1.84 YES 3.98/1.87 EOF
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