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Higher_Order_Rewriting_Union_Beta 2019-03-28 22.10 pair #432270385
details
property
value
status
complete
benchmark
h11.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n136.star.cs.uiowa.edu
space
Hamana_Kikuchi_18
run statistics
property
value
solver
Wanda 2.1c
configuration
default
runtime (wallclock)
0.0954489 seconds
cpu usage
0.095592
user time
0.073729
system time
0.021863
max virtual memory
113176.0
max residence set size
5488.0
stage attributes
key
value
starexec-result
YES
output
0.00/0.09 YES 0.00/0.09 We consider the system theBenchmark. 0.00/0.09 0.00/0.09 Alphabet: 0.00/0.09 0.00/0.09 0 : [] --> N 0.00/0.09 rec : [] --> (N -> (N -> B) -> N -> B) -> B -> N -> B 0.00/0.09 0.00/0.09 Rules: 0.00/0.09 0.00/0.09 rec f (g 0) => g 0.00/0.09 0.00/0.09 Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. 0.00/0.09 0.00/0.09 We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: 0.00/0.09 0.00/0.09 Alphabet: 0.00/0.09 0.00/0.09 0 : [] --> N 0.00/0.09 rec : [N -> (N -> B) -> N -> B * B] --> N -> B 0.00/0.09 ~AP1 : [N -> B * N] --> B 0.00/0.09 0.00/0.09 Rules: 0.00/0.09 0.00/0.09 rec(F, ~AP1(G, 0)) => G 0.00/0.09 ~AP1(F, X) => F X 0.00/0.09 0.00/0.09 We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [Kop13]). 0.00/0.09 0.00/0.09 In order to do so, we start by eta-expanding the system, which gives: 0.00/0.09 0.00/0.09 rec(F, ~AP1(G, 0), X) => G X 0.00/0.09 ~AP1(F, X) => F X 0.00/0.09 0.00/0.09 We thus obtain the following dependency pair problem (P_0, R_0, static, formative): 0.00/0.09 0.00/0.09 Dependency Pairs P_0: 0.00/0.09 0.00/0.09 0.00/0.09 Rules R_0: 0.00/0.09 0.00/0.09 rec(F, ~AP1(G, 0), X) => G X 0.00/0.09 ~AP1(F, X) => F X 0.00/0.09 0.00/0.09 Thus, the original system is terminating if (P_0, R_0, static, formative) is finite. 0.00/0.09 0.00/0.09 We consider the dependency pair problem (P_0, R_0, static, formative). 0.00/0.09 0.00/0.09 We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: 0.00/0.09 0.00/0.09 0.00/0.09 This graph has no strongly connected components. By [Kop12, Thm. 7.31], this implies finiteness of the dependency pair problem. 0.00/0.09 0.00/0.09 As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. 0.00/0.09 0.00/0.09 0.00/0.09 +++ Citations +++ 0.00/0.09 0.00/0.09 [Kop11] C. Kop. Simplifying Algebraic Functional Systems. In Proceedings of CAI 2011, volume 6742 of LNCS. 201--215, Springer, 2011. 0.00/0.09 [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. 0.00/0.09 [Kop13] C. Kop. Static Dependency Pairs with Accessibility. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/static.pdf, 2013. 0.00/0.09 [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009. 0.00/0.09 EOF
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