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Higher_Order_Rewriting_Union_Beta 2019-03-28 22.10 pair #432270469
details
property
value
status
complete
benchmark
h53.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n075.star.cs.uiowa.edu
space
Hamana_Kikuchi_18
run statistics
property
value
solver
Wanda 2.1c
configuration
default
runtime (wallclock)
11.491 seconds
cpu usage
11.4907
user time
11.291
system time
0.199734
max virtual memory
237328.0
max residence set size
120672.0
stage attributes
key
value
starexec-result
YES
output
11.40/11.44 YES 11.43/11.48 We consider the system theBenchmark. 11.43/11.48 11.43/11.48 Alphabet: 11.43/11.48 11.43/11.48 cons : [a * alist] --> alist 11.43/11.48 foldl : [a -> a -> a * a * alist] --> a 11.43/11.48 nil : [] --> alist 11.43/11.48 xap : [a -> a -> a * a] --> a -> a 11.43/11.48 yap : [a -> a * a] --> a 11.43/11.48 11.43/11.48 Rules: 11.43/11.48 11.43/11.48 foldl(/\x./\y.yap(xap(f, x), y), z, nil) => z 11.43/11.48 foldl(/\x./\y.yap(xap(f, x), y), z, cons(u, v)) => foldl(/\w./\x'.yap(xap(f, w), x'), yap(xap(f, z), u), v) 11.43/11.48 xap(f, x) => f x 11.43/11.48 yap(f, x) => f x 11.43/11.48 11.43/11.48 This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). 11.43/11.48 11.43/11.48 Symbol xap is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: 11.43/11.48 11.43/11.48 Alphabet: 11.43/11.48 11.43/11.48 cons : [a * alist] --> alist 11.43/11.48 foldl : [a -> a -> a * a * alist] --> a 11.43/11.48 nil : [] --> alist 11.43/11.48 yap : [a -> a * a] --> a 11.43/11.48 11.43/11.48 Rules: 11.43/11.48 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, nil) => X 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, cons(Y, Z)) => foldl(/\z./\u.yap(F(z), u), yap(F(X), Y), Z) 11.43/11.48 yap(F, X) => F X 11.43/11.48 11.43/11.48 We use rule removal, following [Kop12, Theorem 2.23]. 11.43/11.48 11.43/11.48 This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): 11.43/11.48 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, nil) >? X 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >? foldl(/\z./\u.yap(F(z), u), yap(F(X), Y), Z) 11.43/11.48 yap(F, X) >? F X 11.43/11.48 11.43/11.48 We use a recursive path ordering as defined in [Kop12, Chapter 5]. 11.43/11.48 11.43/11.48 Argument functions: 11.43/11.48 11.43/11.48 [[foldl(x_1, x_2, x_3)]] = foldl(x_3, x_1, x_2) 11.43/11.48 11.43/11.48 We choose Lex = {foldl} and Mul = {@_{o -> o}, cons, nil, yap}, and the following precedence: cons > nil > foldl > yap > @_{o -> o} 11.43/11.48 11.43/11.48 Taking the argument function into account, and fixing the greater / greater equal choices, the constraints can be denoted as follows: 11.43/11.48 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, nil) >= X 11.43/11.48 foldl(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldl(/\x./\y.yap(F(x), y), yap(F(X), Y), Z) 11.43/11.48 yap(F, X) > @_{o -> o}(F, X) 11.43/11.48 11.43/11.48 With these choices, we have: 11.43/11.48 11.43/11.48 1] foldl(/\x./\y.yap(F(x), y), X, nil) >= X because [2], by (Star) 11.43/11.48 2] foldl*(/\x./\y.yap(F(x), y), X, nil) >= X because [3], by (Select) 11.43/11.48 3] X >= X by (Meta) 11.43/11.48 11.43/11.48 4] foldl(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldl(/\x./\y.yap(F(x), y), yap(F(X), Y), Z) because [5], by (Star) 11.43/11.48 5] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldl(/\x./\y.yap(F(x), y), yap(F(X), Y), Z) because [6], [9], [19] and [29], by (Stat) 11.43/11.48 6] cons(Y, Z) > Z because [7], by definition 11.43/11.48 7] cons*(Y, Z) >= Z because [8], by (Select) 11.43/11.48 8] Z >= Z by (Meta) 11.43/11.48 9] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= /\x./\y.yap(F(x), y) because [10], by (F-Abs) 11.43/11.48 10] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z) >= /\x.yap(F(z), x) because [11], by (F-Abs) 11.43/11.48 11] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z, u) >= yap(F(z), u) because foldl > yap, [12] and [17], by (Copy) 11.43/11.48 12] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z, u) >= F(z) because [13], by (Select) 11.43/11.48 13] /\x.yap(F(foldl*(/\y./\v.yap(F(y), v), X, cons(Y, Z), z, u)), x) >= F(z) because [14], by (Eta)[Kop13:2] 11.43/11.48 14] F(foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z, u)) >= F(z) because [15], by (Meta) 11.43/11.48 15] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z, u) >= z because [16], by (Select) 11.43/11.48 16] z >= z by (Var) 11.43/11.48 17] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z), z, u) >= u because [18], by (Select) 11.43/11.48 18] u >= u by (Var) 11.43/11.48 19] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(X), Y) because foldl > yap, [20] and [25], by (Copy) 11.43/11.48 20] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= F(X) because [21], by (Select) 11.43/11.48 21] /\x.yap(F(foldl*(/\y./\v.yap(F(y), v), X, cons(Y, Z))), x) >= F(X) because [22], by (Eta)[Kop13:2] 11.43/11.48 22] F(foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z))) >= F(X) because [23], by (Meta) 11.43/11.48 23] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= X because [24], by (Select) 11.43/11.48 24] X >= X by (Meta) 11.43/11.48 25] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= Y because [26], by (Select) 11.43/11.48 26] cons(Y, Z) >= Y because [27], by (Star) 11.43/11.48 27] cons*(Y, Z) >= Y because [28], by (Select) 11.43/11.48 28] Y >= Y by (Meta) 11.43/11.48 29] foldl*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= Z because [30], by (Select) 11.43/11.48 30] cons(Y, Z) >= Z because [7], by (Star) 11.43/11.48 11.43/11.48 31] yap(F, X) > @_{o -> o}(F, X) because [32], by definition 11.43/11.48 32] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [33] and [35], by (Copy) 11.43/11.48 33] yap*(F, X) >= F because [34], by (Select) 11.43/11.48 34] F >= F by (Meta) 11.43/11.48 35] yap*(F, X) >= X because [36], by (Select) 11.43/11.48 36] X >= X by (Meta) 11.43/11.48 11.43/11.48 We can thus remove the following rules: 11.43/11.48
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