TRS_Innermost 2019-03-28 22.12 pair #432271064

details

property	value
status	complete
benchmark	Ex18_Luc06_L.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n094.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.64915 seconds
cpu usage	3.3596
user time	3.19698
system time	0.162625
max virtual memory	1.8477048E7
max residence set size	238600.0

stage attributes

key	value
starexec-result	YES

output

3.12/1.59	YES
3.12/1.60	proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
3.12/1.60	# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty
3.12/1.60	
3.12/1.60	
3.12/1.60	Termination w.r.t. Q of the given QTRS could be proven:
3.12/1.60	
3.12/1.60	(0) QTRS
3.12/1.60	(1) QTRS Reverse [EQUIVALENT, 0 ms]
3.12/1.60	(2) QTRS
3.12/1.60	(3) QTRSRoofMatchBoundsTAProof [EQUIVALENT, 0 ms]
3.12/1.60	(4) YES
3.12/1.60	
3.12/1.60	
3.12/1.60	----------------------------------------
3.12/1.60	
3.12/1.60	(0)
3.12/1.60	Obligation:
3.12/1.60	Q restricted rewrite system:
3.12/1.60	The TRS R consists of the following rules:
3.12/1.60	
3.12/1.60	   f(f(a)) -> f(g)
3.12/1.60	
3.12/1.60	The set Q consists of the following terms:
3.12/1.60	
3.12/1.60	   f(f(a))
3.12/1.60	
3.12/1.60	
3.12/1.60	----------------------------------------
3.12/1.60	
3.12/1.60	(1) QTRS Reverse (EQUIVALENT)
3.12/1.60	We applied the QTRS Reverse Processor [REVERSE].
3.12/1.60	----------------------------------------
3.12/1.60	
3.12/1.60	(2)
3.12/1.60	Obligation:
3.12/1.60	Q restricted rewrite system:
3.12/1.60	The TRS R consists of the following rules:
3.12/1.60	
3.12/1.60	   a'(f(f(x))) -> g'(f(x))
3.12/1.60	
3.12/1.60	Q is empty.
3.12/1.60	
3.12/1.60	----------------------------------------
3.12/1.60	
3.12/1.60	(3) QTRSRoofMatchBoundsTAProof (EQUIVALENT)
3.12/1.60	The TRS R could be shown to be Match-Bounded [TAB_LEFTLINEAR,TAB_NONLEFTLINEAR] by  1. Therefore it terminates.
3.12/1.60	
3.12/1.60	The compatible tree automaton used to show the Match-Boundedness is represented by: 
3.12/1.60	final states : [0, 1, 2]
3.12/1.60	transitions: 
3.12/1.60	a'0(0) -> 0
3.12/1.60	a'0(1) -> 0
3.12/1.60	a'0(2) -> 0
3.12/1.60	f0(0) -> 1
3.12/1.60	f0(1) -> 1
3.12/1.60	f0(2) -> 1
3.12/1.60	g'0(0) -> 2
3.12/1.60	g'0(1) -> 2
3.12/1.60	g'0(2) -> 2
3.12/1.60	f1(0) -> 3
3.12/1.60	g'1(3) -> 0
3.12/1.60	f1(1) -> 3
3.12/1.60	f1(2) -> 3
3.12/1.60	
3.12/1.60	----------------------------------------
3.12/1.60	
3.12/1.60	(4)
3.12/1.60	YES
3.34/1.64	EOF

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