details

property	value
status	complete
benchmark	Ex1_Zan97_GM.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n045.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.66045 seconds
cpu usage	3.40457
user time	3.23832
system time	0.166254
max virtual memory	1.8277356E7
max residence set size	229364.0

stage attributes

key	value
starexec-result	YES

output

3.03/1.60 YES 3.33/1.62 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.33/1.62 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.33/1.62 3.33/1.62 3.33/1.62 Termination w.r.t. Q of the given QTRS could be proven: 3.33/1.62 3.33/1.62 (0) QTRS 3.33/1.62 (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] 3.33/1.62 (2) YES 3.33/1.62 3.33/1.62 3.33/1.62 ---------------------------------------- 3.33/1.62 3.33/1.62 (0) 3.33/1.62 Obligation: 3.33/1.62 Q restricted rewrite system: 3.33/1.62 The TRS R consists of the following rules: 3.33/1.62 3.33/1.62 a__g(X) -> a__h(X) 3.33/1.62 a__c -> d 3.33/1.62 a__h(d) -> a__g(c) 3.33/1.62 mark(g(X)) -> a__g(X) 3.33/1.62 mark(h(X)) -> a__h(X) 3.33/1.62 mark(c) -> a__c 3.33/1.62 mark(d) -> d 3.33/1.62 a__g(X) -> g(X) 3.33/1.62 a__h(X) -> h(X) 3.33/1.62 a__c -> c 3.33/1.62 3.33/1.62 The set Q consists of the following terms: 3.33/1.62 3.33/1.62 a__g(x0) 3.33/1.62 a__c 3.33/1.62 mark(g(x0)) 3.33/1.62 mark(h(x0)) 3.33/1.62 mark(c) 3.33/1.62 mark(d) 3.33/1.62 a__h(x0) 3.33/1.62 3.33/1.62 3.33/1.62 ---------------------------------------- 3.33/1.62 3.33/1.62 (1) RFCMatchBoundsTRSProof (EQUIVALENT) 3.33/1.62 Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 4. This implies Q-termination of R. 3.33/1.62 The following rules were used to construct the certificate: 3.33/1.62 3.33/1.62 a__g(X) -> a__h(X) 3.33/1.62 a__c -> d 3.33/1.62 a__h(d) -> a__g(c) 3.33/1.62 mark(g(X)) -> a__g(X) 3.33/1.62 mark(h(X)) -> a__h(X) 3.33/1.62 mark(c) -> a__c 3.33/1.62 mark(d) -> d 3.33/1.62 a__g(X) -> g(X) 3.33/1.62 a__h(X) -> h(X) 3.33/1.62 a__c -> c 3.33/1.62 3.33/1.62 The certificate found is represented by the following graph. 3.33/1.62 The certificate consists of the following enumerated nodes: 3.33/1.62 1, 2, 3, 4 3.33/1.62 3.33/1.62 Node 1 is start node and node 2 is final node. 3.33/1.62 3.33/1.62 Those nodes are connected through the following edges: 3.33/1.62 3.33/1.62 * 1 to 2 labelled a__h_1(0), d(0), a__g_1(0), a__c(0), g_1(0), h_1(0), c(0), h_1(1), a__h_1(1), g_1(1), d(1), c(1), h_1(2)* 1 to 3 labelled a__g_1(0), a__h_1(1), g_1(1), h_1(2)* 1 to 1 labelled a__g_1(1), a__h_1(2), g_1(2), h_1(3)* 1 to 4 labelled a__g_1(2), a__h_1(3), g_1(3), h_1(4)* 2 to 2 labelled #_1(0)* 3 to 2 labelled c(0)* 4 to 2 labelled c(2) 3.33/1.62 3.33/1.62 3.33/1.62 ---------------------------------------- 3.33/1.62 3.33/1.62 (2) 3.33/1.62 YES 3.33/1.66 EOF popout

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all output return to TRS_Innermost 2019-03-28 22.12