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TRS_Innermost 2019-03-28 22.12 pair #432271435
details
property
value
status
complete
benchmark
#4.30a.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n105.star.cs.uiowa.edu
space
AG01_innermost
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
20.2157 seconds
cpu usage
20.1832
user time
17.2493
system time
2.93389
max virtual memory
598900.0
max residence set size
5932.0
stage attributes
key
value
starexec-result
YES
output
20.15/20.21 YES 20.15/20.21 20.15/20.21 Problem 1: 20.15/20.21 20.15/20.21 (VAR v_NonEmpty:S x:S y:S) 20.15/20.21 (RULES 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 ) 20.15/20.21 (STRATEGY INNERMOST) 20.15/20.21 20.15/20.21 Problem 1: 20.15/20.21 20.15/20.21 Dependency Pairs Processor: 20.15/20.21 -> Pairs: 20.15/20.21 LE(s(x:S),s(y:S)) -> LE(x:S,y:S) 20.15/20.21 MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) 20.15/20.21 QUOT(s(x:S),s(y:S)) -> MINUS(s(x:S),s(y:S)) 20.15/20.21 QUOT(s(x:S),s(y:S)) -> QUOT(minus(s(x:S),s(y:S)),s(y:S)) 20.15/20.21 -> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 20.15/20.21 Problem 1: 20.15/20.21 20.15/20.21 SCC Processor: 20.15/20.21 -> Pairs: 20.15/20.21 LE(s(x:S),s(y:S)) -> LE(x:S,y:S) 20.15/20.21 MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) 20.15/20.21 QUOT(s(x:S),s(y:S)) -> MINUS(s(x:S),s(y:S)) 20.15/20.21 QUOT(s(x:S),s(y:S)) -> QUOT(minus(s(x:S),s(y:S)),s(y:S)) 20.15/20.21 -> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 ->Strongly Connected Components: 20.15/20.21 ->->Cycle: 20.15/20.21 ->->-> Pairs: 20.15/20.21 MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) 20.15/20.21 ->->-> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 ->->Cycle: 20.15/20.21 ->->-> Pairs: 20.15/20.21 QUOT(s(x:S),s(y:S)) -> QUOT(minus(s(x:S),s(y:S)),s(y:S)) 20.15/20.21 ->->-> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 ->->Cycle: 20.15/20.21 ->->-> Pairs: 20.15/20.21 LE(s(x:S),s(y:S)) -> LE(x:S,y:S) 20.15/20.21 ->->-> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S))) 20.15/20.21 20.15/20.21 20.15/20.21 The problem is decomposed in 3 subproblems. 20.15/20.21 20.15/20.21 Problem 1.1: 20.15/20.21 20.15/20.21 Subterm Processor: 20.15/20.21 -> Pairs: 20.15/20.21 MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) 20.15/20.21 -> Rules: 20.15/20.21 le(0,y:S) -> ttrue 20.15/20.21 le(s(x:S),0) -> ffalse 20.15/20.21 le(s(x:S),s(y:S)) -> le(x:S,y:S) 20.15/20.21 minus(s(x:S),s(y:S)) -> minus(x:S,y:S) 20.15/20.21 minus(x:S,0) -> x:S 20.15/20.21 quot(0,s(y:S)) -> 0 20.15/20.21 quot(s(x:S),s(y:S)) -> s(quot(minus(s(x:S),s(y:S)),s(y:S)))
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