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C_Integer 2019-03-28 22.15 pair #432271519
details
property
value
status
complete
benchmark
svcomp_b.02.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n102.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.08207 seconds
cpu usage
4.97154
user time
4.68662
system time
0.284917
max virtual memory
1.877626E7
max residence set size
388564.0
stage attributes
key
value
starexec-result
YES
output
4.71/2.02 YES 4.90/2.03 proof of /export/starexec/sandbox2/benchmark/theBenchmark.c 4.90/2.03 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.90/2.03 4.90/2.03 4.90/2.03 Termination of the given C Problem could be proven: 4.90/2.03 4.90/2.03 (0) C Problem 4.90/2.03 (1) CToIRSProof [EQUIVALENT, 0 ms] 4.90/2.03 (2) IntTRS 4.90/2.03 (3) TerminationGraphProcessor [SOUND, 54 ms] 4.90/2.03 (4) IntTRS 4.90/2.03 (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] 4.90/2.03 (6) IntTRS 4.90/2.03 (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] 4.90/2.03 (8) IntTRS 4.90/2.03 (9) PolynomialOrderProcessor [EQUIVALENT, 1 ms] 4.90/2.03 (10) YES 4.90/2.03 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (0) 4.90/2.03 Obligation: 4.90/2.03 c file /export/starexec/sandbox2/benchmark/theBenchmark.c 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (1) CToIRSProof (EQUIVALENT) 4.90/2.03 Parsed C Integer Program as IRS. 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (2) 4.90/2.03 Obligation: 4.90/2.03 Rules: 4.90/2.03 f1(c, x, y) -> f2(c, x_1, y) :|: TRUE 4.90/2.03 f2(x1, x2, x3) -> f3(x1, x2, x4) :|: TRUE 4.90/2.03 f3(x5, x6, x7) -> f4(0, x6, x7) :|: TRUE 4.90/2.03 f5(x8, x9, x10) -> f6(x8, arith, x10) :|: TRUE && arith = x9 - 1 4.90/2.03 f6(x26, x27, x28) -> f7(x26, x27, x29) :|: TRUE && x29 = x28 + 1 4.90/2.03 f7(x30, x31, x32) -> f8(x33, x31, x32) :|: TRUE && x33 = x30 + 1 4.90/2.03 f4(x17, x18, x19) -> f5(x17, x18, x19) :|: x18 > x19 4.90/2.03 f8(x20, x21, x22) -> f4(x20, x21, x22) :|: TRUE 4.90/2.03 f4(x23, x24, x25) -> f9(x23, x24, x25) :|: x24 <= x25 4.90/2.03 Start term: f1(c, x, y) 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (3) TerminationGraphProcessor (SOUND) 4.90/2.03 Constructed the termination graph and obtained one non-trivial SCC. 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (4) 4.90/2.03 Obligation: 4.90/2.03 Rules: 4.90/2.03 f4(x17, x18, x19) -> f5(x17, x18, x19) :|: x18 > x19 4.90/2.03 f8(x20, x21, x22) -> f4(x20, x21, x22) :|: TRUE 4.90/2.03 f7(x30, x31, x32) -> f8(x33, x31, x32) :|: TRUE && x33 = x30 + 1 4.90/2.03 f6(x26, x27, x28) -> f7(x26, x27, x29) :|: TRUE && x29 = x28 + 1 4.90/2.03 f5(x8, x9, x10) -> f6(x8, arith, x10) :|: TRUE && arith = x9 - 1 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (5) IntTRSCompressionProof (EQUIVALENT) 4.90/2.03 Compressed rules. 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (6) 4.90/2.03 Obligation: 4.90/2.03 Rules: 4.90/2.03 f6(x26:0, x27:0, x28:0) -> f6(x26:0 + 1, x27:0 - 1, x28:0 + 1) :|: x28:0 + 1 < x27:0 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) 4.90/2.03 Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: 4.90/2.03 4.90/2.03 f6(x1, x2, x3) -> f6(x2, x3) 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (8) 4.90/2.03 Obligation: 4.90/2.03 Rules: 4.90/2.03 f6(x27:0, x28:0) -> f6(x27:0 - 1, x28:0 + 1) :|: x28:0 + 1 < x27:0 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (9) PolynomialOrderProcessor (EQUIVALENT) 4.90/2.03 Found the following polynomial interpretation: 4.90/2.03 [f6(x, x1)] = -1 + x - x1 4.90/2.03 4.90/2.03 The following rules are decreasing: 4.90/2.03 f6(x27:0, x28:0) -> f6(x27:0 - 1, x28:0 + 1) :|: x28:0 + 1 < x27:0 4.90/2.03 The following rules are bounded: 4.90/2.03 f6(x27:0, x28:0) -> f6(x27:0 - 1, x28:0 + 1) :|: x28:0 + 1 < x27:0 4.90/2.03 4.90/2.03 ---------------------------------------- 4.90/2.03 4.90/2.03 (10)
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