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C_Integer 2019-03-28 22.15 pair #432271570
details
property
value
status
complete
benchmark
DivMinus.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n158.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
1.99155 seconds
cpu usage
4.64809
user time
4.38426
system time
0.263827
max virtual memory
1.897698E7
max residence set size
400992.0
stage attributes
key
value
starexec-result
YES
output
4.45/1.94 YES 4.45/1.96 proof of /export/starexec/sandbox2/benchmark/theBenchmark.c 4.45/1.96 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.45/1.96 4.45/1.96 4.45/1.96 Termination of the given C Problem could be proven: 4.45/1.96 4.45/1.96 (0) C Problem 4.45/1.96 (1) CToIRSProof [EQUIVALENT, 0 ms] 4.45/1.96 (2) IntTRS 4.45/1.96 (3) TerminationGraphProcessor [SOUND, 50 ms] 4.45/1.96 (4) IntTRS 4.45/1.96 (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] 4.45/1.96 (6) IntTRS 4.45/1.96 (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] 4.45/1.96 (8) IntTRS 4.45/1.96 (9) PolynomialOrderProcessor [EQUIVALENT, 1 ms] 4.45/1.96 (10) YES 4.45/1.96 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (0) 4.45/1.96 Obligation: 4.45/1.96 c file /export/starexec/sandbox2/benchmark/theBenchmark.c 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (1) CToIRSProof (EQUIVALENT) 4.45/1.96 Parsed C Integer Program as IRS. 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (2) 4.45/1.96 Obligation: 4.45/1.96 Rules: 4.45/1.96 f1(x, y, res) -> f2(x_1, y, res) :|: TRUE 4.45/1.96 f2(x1, x2, x3) -> f3(x1, x4, x3) :|: TRUE 4.45/1.96 f3(x5, x6, x7) -> f4(x5, x6, 0) :|: TRUE 4.45/1.96 f5(x8, x9, x10) -> f6(arith, x9, x10) :|: TRUE && arith = x8 - x9 4.45/1.96 f6(x23, x24, x25) -> f7(x23, x24, x26) :|: TRUE && x26 = x25 + 1 4.45/1.96 f4(x14, x15, x16) -> f5(x14, x15, x16) :|: x14 >= x15 && x15 > 0 4.45/1.96 f7(x17, x18, x19) -> f4(x17, x18, x19) :|: TRUE 4.45/1.96 f4(x20, x21, x22) -> f8(x20, x21, x22) :|: x20 < x21 4.45/1.96 f4(x27, x28, x29) -> f8(x27, x28, x29) :|: x28 <= 0 4.45/1.96 Start term: f1(x, y, res) 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (3) TerminationGraphProcessor (SOUND) 4.45/1.96 Constructed the termination graph and obtained one non-trivial SCC. 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (4) 4.45/1.96 Obligation: 4.45/1.96 Rules: 4.45/1.96 f4(x14, x15, x16) -> f5(x14, x15, x16) :|: x14 >= x15 && x15 > 0 4.45/1.96 f7(x17, x18, x19) -> f4(x17, x18, x19) :|: TRUE 4.45/1.96 f6(x23, x24, x25) -> f7(x23, x24, x26) :|: TRUE && x26 = x25 + 1 4.45/1.96 f5(x8, x9, x10) -> f6(arith, x9, x10) :|: TRUE && arith = x8 - x9 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (5) IntTRSCompressionProof (EQUIVALENT) 4.45/1.96 Compressed rules. 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (6) 4.45/1.96 Obligation: 4.45/1.96 Rules: 4.45/1.96 f6(x23:0, x24:0, x25:0) -> f6(x23:0 - x24:0, x24:0, x25:0 + 1) :|: x24:0 <= x23:0 && x24:0 > 0 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) 4.45/1.96 Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: 4.45/1.96 4.45/1.96 f6(x1, x2, x3) -> f6(x1, x2) 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (8) 4.45/1.96 Obligation: 4.45/1.96 Rules: 4.45/1.96 f6(x23:0, x24:0) -> f6(x23:0 - x24:0, x24:0) :|: x24:0 <= x23:0 && x24:0 > 0 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (9) PolynomialOrderProcessor (EQUIVALENT) 4.45/1.96 Found the following polynomial interpretation: 4.45/1.96 [f6(x, x1)] = x 4.45/1.96 4.45/1.96 The following rules are decreasing: 4.45/1.96 f6(x23:0, x24:0) -> f6(x23:0 - x24:0, x24:0) :|: x24:0 <= x23:0 && x24:0 > 0 4.45/1.96 The following rules are bounded: 4.45/1.96 f6(x23:0, x24:0) -> f6(x23:0 - x24:0, x24:0) :|: x24:0 <= x23:0 && x24:0 > 0 4.45/1.96 4.45/1.96 ---------------------------------------- 4.45/1.96 4.45/1.96 (10) 4.45/1.96 YES
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