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C_Integer 2019-03-28 22.15 pair #432271723
details
property
value
status
complete
benchmark
svcomp_a.09_assume.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n133.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
1.96788 seconds
cpu usage
4.93754
user time
4.64537
system time
0.292165
max virtual memory
1.8876008E7
max residence set size
401904.0
stage attributes
key
value
starexec-result
YES
output
4.75/1.93 YES 4.75/1.94 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 4.75/1.94 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.75/1.94 4.75/1.94 4.75/1.94 Termination of the given C Problem could be proven: 4.75/1.94 4.75/1.94 (0) C Problem 4.75/1.94 (1) CToIRSProof [EQUIVALENT, 0 ms] 4.75/1.94 (2) IntTRS 4.75/1.94 (3) TerminationGraphProcessor [SOUND, 47 ms] 4.75/1.94 (4) IntTRS 4.75/1.94 (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] 4.75/1.94 (6) IntTRS 4.75/1.94 (7) RankingReductionPairProof [EQUIVALENT, 0 ms] 4.75/1.94 (8) YES 4.75/1.94 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (0) 4.75/1.94 Obligation: 4.75/1.94 c file /export/starexec/sandbox/benchmark/theBenchmark.c 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (1) CToIRSProof (EQUIVALENT) 4.75/1.94 Parsed C Integer Program as IRS. 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (2) 4.75/1.94 Obligation: 4.75/1.94 Rules: 4.75/1.94 f1(x, y, z) -> f2(x_1, y, z) :|: TRUE 4.75/1.94 f2(x1, x2, x3) -> f3(x1, x4, x3) :|: TRUE 4.75/1.94 f3(x5, x6, x7) -> f4(x5, x6, x8) :|: TRUE 4.75/1.94 f5(x9, x10, x11) -> f6(x9, x10, arith) :|: TRUE && arith = x11 + x10 4.75/1.94 f4(x12, x13, x14) -> f5(x12, x13, x14) :|: x13 > 0 && x12 >= x14 4.75/1.94 f6(x15, x16, x17) -> f4(x15, x16, x17) :|: TRUE 4.75/1.94 f4(x18, x19, x20) -> f7(x18, x19, x20) :|: x19 <= 0 4.75/1.94 f4(x21, x22, x23) -> f7(x21, x22, x23) :|: x21 < x23 4.75/1.94 Start term: f1(x, y, z) 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (3) TerminationGraphProcessor (SOUND) 4.75/1.94 Constructed the termination graph and obtained one non-trivial SCC. 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (4) 4.75/1.94 Obligation: 4.75/1.94 Rules: 4.75/1.94 f4(x12, x13, x14) -> f5(x12, x13, x14) :|: x13 > 0 && x12 >= x14 4.75/1.94 f6(x15, x16, x17) -> f4(x15, x16, x17) :|: TRUE 4.75/1.94 f5(x9, x10, x11) -> f6(x9, x10, arith) :|: TRUE && arith = x11 + x10 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (5) IntTRSCompressionProof (EQUIVALENT) 4.75/1.94 Compressed rules. 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (6) 4.75/1.94 Obligation: 4.75/1.94 Rules: 4.75/1.94 f6(x15:0, x16:0, x17:0) -> f6(x15:0, x16:0, x17:0 + x16:0) :|: x16:0 > 0 && x17:0 <= x15:0 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (7) RankingReductionPairProof (EQUIVALENT) 4.75/1.94 Interpretation: 4.75/1.94 [ f6 ] = -1*f6_3 + f6_1 4.75/1.94 4.75/1.94 The following rules are decreasing: 4.75/1.94 f6(x15:0, x16:0, x17:0) -> f6(x15:0, x16:0, x17:0 + x16:0) :|: x16:0 > 0 && x17:0 <= x15:0 4.75/1.94 4.75/1.94 The following rules are bounded: 4.75/1.94 f6(x15:0, x16:0, x17:0) -> f6(x15:0, x16:0, x17:0 + x16:0) :|: x16:0 > 0 && x17:0 <= x15:0 4.75/1.94 4.75/1.94 4.75/1.94 ---------------------------------------- 4.75/1.94 4.75/1.94 (8) 4.75/1.94 YES 4.75/1.96 EOF
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