details

property	value
status	complete
benchmark	ChenFlurMukhopadhyay-SAS2012-Ex1.04_true-termination.c
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n086.star.cs.uiowa.edu
space	Stroeder_15

run statistics

property	value
solver	AProVE
configuration	c
runtime (wallclock)	1.98562 seconds
cpu usage	4.67426
user time	4.39723
system time	0.277028
max virtual memory	1.8975952E7
max residence set size	380812.0

stage attributes

key	value
starexec-result	YES

output

4.33/1.94 YES 4.33/1.95 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 4.33/1.95 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.33/1.95 4.33/1.95 4.33/1.95 Termination of the given C Problem could be proven: 4.33/1.95 4.33/1.95 (0) C Problem 4.33/1.95 (1) CToIRSProof [EQUIVALENT, 0 ms] 4.33/1.95 (2) IntTRS 4.33/1.95 (3) TerminationGraphProcessor [SOUND, 29 ms] 4.33/1.95 (4) IntTRS 4.33/1.95 (5) IntTRSCompressionProof [EQUIVALENT, 12 ms] 4.33/1.95 (6) IntTRS 4.33/1.95 (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] 4.33/1.95 (8) IntTRS 4.33/1.95 (9) PolynomialOrderProcessor [EQUIVALENT, 0 ms] 4.33/1.95 (10) YES 4.33/1.95 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (0) 4.33/1.95 Obligation: 4.33/1.95 c file /export/starexec/sandbox/benchmark/theBenchmark.c 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (1) CToIRSProof (EQUIVALENT) 4.33/1.95 Parsed C Integer Program as IRS. 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (2) 4.33/1.95 Obligation: 4.33/1.95 Rules: 4.33/1.95 f1(x, oldx) -> f2(x_1, oldx) :|: TRUE 4.33/1.95 f3(x1, x2) -> f4(x1, x1) :|: TRUE 4.33/1.95 f4(x3, x4) -> f5(x5, x4) :|: TRUE 4.33/1.95 f2(x6, x7) -> f3(x6, x7) :|: x6 > 1 && 2 * x6 <= x7 4.33/1.95 f5(x8, x9) -> f2(x8, x9) :|: TRUE 4.33/1.95 f2(x10, x11) -> f6(x10, x11) :|: x10 <= 1 4.33/1.95 f2(x12, x13) -> f6(x12, x13) :|: 2 * x12 > x13 4.33/1.95 Start term: f1(x, oldx) 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (3) TerminationGraphProcessor (SOUND) 4.33/1.95 Constructed the termination graph and obtained one non-trivial SCC. 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (4) 4.33/1.95 Obligation: 4.33/1.95 Rules: 4.33/1.95 f2(x6, x7) -> f3(x6, x7) :|: x6 > 1 && 2 * x6 <= x7 4.33/1.95 f5(x8, x9) -> f2(x8, x9) :|: TRUE 4.33/1.95 f4(x3, x4) -> f5(x5, x4) :|: TRUE 4.33/1.95 f3(x1, x2) -> f4(x1, x1) :|: TRUE 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (5) IntTRSCompressionProof (EQUIVALENT) 4.33/1.95 Compressed rules. 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (6) 4.33/1.95 Obligation: 4.33/1.95 Rules: 4.33/1.95 f4(x3:0, x4:0) -> f4(x5:0, x5:0) :|: x5:0 > 1 && x4:0 >= 2 * x5:0 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) 4.33/1.95 Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: 4.33/1.95 4.33/1.95 f4(x1, x2) -> f4(x2) 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (8) 4.33/1.95 Obligation: 4.33/1.95 Rules: 4.33/1.95 f4(x4:0) -> f4(x5:0) :|: x5:0 > 1 && x4:0 >= 2 * x5:0 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (9) PolynomialOrderProcessor (EQUIVALENT) 4.33/1.95 Found the following polynomial interpretation: 4.33/1.95 [f4(x)] = x 4.33/1.95 4.33/1.95 The following rules are decreasing: 4.33/1.95 f4(x4:0) -> f4(x5:0) :|: x5:0 > 1 && x4:0 >= 2 * x5:0 4.33/1.95 The following rules are bounded: 4.33/1.95 f4(x4:0) -> f4(x5:0) :|: x5:0 > 1 && x4:0 >= 2 * x5:0 4.33/1.95 4.33/1.95 ---------------------------------------- 4.33/1.95 4.33/1.95 (10) 4.33/1.95 YES 4.64/1.98 EOF popout

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all output return to C_Integer 2019-03-28 22.15