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C_Integer 2019-03-28 22.15 pair #432272152
details
property
value
status
complete
benchmark
ChenFlurMukhopadhyay-SAS2012-Fig1_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n056.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.84528 seconds
cpu usage
7.84201
user time
7.4151
system time
0.426917
max virtual memory
1.9803008E7
max residence set size
607216.0
stage attributes
key
value
starexec-result
YES
output
7.55/2.79 YES 7.55/2.80 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 7.55/2.80 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 7.55/2.80 7.55/2.80 7.55/2.80 Termination of the given C Problem could be proven: 7.55/2.80 7.55/2.80 (0) C Problem 7.55/2.80 (1) CToIRSProof [EQUIVALENT, 0 ms] 7.55/2.80 (2) IntTRS 7.55/2.80 (3) TerminationGraphProcessor [SOUND, 53 ms] 7.55/2.80 (4) IntTRS 7.55/2.80 (5) IntTRSCompressionProof [EQUIVALENT, 25 ms] 7.55/2.80 (6) IntTRS 7.55/2.80 (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] 7.55/2.80 (8) IntTRS 7.55/2.80 (9) TerminationGraphProcessor [EQUIVALENT, 0 ms] 7.55/2.80 (10) IntTRS 7.55/2.80 (11) IntTRSCompressionProof [EQUIVALENT, 0 ms] 7.55/2.80 (12) IntTRS 7.55/2.80 (13) RankingReductionPairProof [EQUIVALENT, 5 ms] 7.55/2.80 (14) YES 7.55/2.80 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (0) 7.55/2.80 Obligation: 7.55/2.80 c file /export/starexec/sandbox/benchmark/theBenchmark.c 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (1) CToIRSProof (EQUIVALENT) 7.55/2.80 Parsed C Integer Program as IRS. 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (2) 7.55/2.80 Obligation: 7.55/2.80 Rules: 7.55/2.80 f1(x, y, z) -> f2(x_1, y, z) :|: TRUE 7.55/2.80 f2(x1, x2, x3) -> f3(x1, x4, x3) :|: TRUE 7.55/2.80 f3(x5, x6, x7) -> f4(x5, x6, x8) :|: TRUE 7.55/2.80 f5(x9, x10, x11) -> f6(arith, x10, x11) :|: TRUE && arith = x9 + x10 7.55/2.80 f6(x12, x13, x14) -> f7(x12, x14, x14) :|: TRUE 7.55/2.80 f7(x27, x28, x29) -> f8(x27, x28, x30) :|: TRUE && x30 = 0 - x29 - 1 7.55/2.80 f4(x18, x19, x20) -> f5(x18, x19, x20) :|: x18 > 0 7.55/2.80 f8(x21, x22, x23) -> f4(x21, x22, x23) :|: TRUE 7.55/2.80 f4(x24, x25, x26) -> f9(x24, x25, x26) :|: x24 <= 0 7.55/2.80 Start term: f1(x, y, z) 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (3) TerminationGraphProcessor (SOUND) 7.55/2.80 Constructed the termination graph and obtained one non-trivial SCC. 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (4) 7.55/2.80 Obligation: 7.55/2.80 Rules: 7.55/2.80 f4(x18, x19, x20) -> f5(x18, x19, x20) :|: x18 > 0 7.55/2.80 f8(x21, x22, x23) -> f4(x21, x22, x23) :|: TRUE 7.55/2.80 f7(x27, x28, x29) -> f8(x27, x28, x30) :|: TRUE && x30 = 0 - x29 - 1 7.55/2.80 f6(x12, x13, x14) -> f7(x12, x14, x14) :|: TRUE 7.55/2.80 f5(x9, x10, x11) -> f6(arith, x10, x11) :|: TRUE && arith = x9 + x10 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (5) IntTRSCompressionProof (EQUIVALENT) 7.55/2.80 Compressed rules. 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (6) 7.55/2.80 Obligation: 7.55/2.80 Rules: 7.55/2.80 f6(x12:0, x13:0, x14:0) -> f6(x12:0 + x14:0, x14:0, 0 - x14:0 - 1) :|: x12:0 > 0 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) 7.55/2.80 Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: 7.55/2.80 7.55/2.80 f6(x1, x2, x3) -> f6(x1, x3) 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (8) 7.55/2.80 Obligation: 7.55/2.80 Rules: 7.55/2.80 f6(x12:0, x14:0) -> f6(x12:0 + x14:0, 0 - x14:0 - 1) :|: x12:0 > 0 7.55/2.80 7.55/2.80 ---------------------------------------- 7.55/2.80 7.55/2.80 (9) TerminationGraphProcessor (EQUIVALENT) 7.55/2.80 Constructed the termination graph and obtained one non-trivial SCC. 7.55/2.80 7.55/2.80 f6(x12:0, x14:0) -> f6(x12:0 + x14:0, 0 - x14:0 - 1) :|: x12:0 > 0 7.55/2.80 has been transformed into 7.55/2.80 f6(x12:0, x14:0) -> f6(x12:0 + x14:0, 0 - x14:0 - 1) :|: x12:0 > 0 && x4 > 0. 7.55/2.80 7.55/2.80
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