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C_Integer 2019-03-28 22.15 pair #432272293
details
property
value
status
complete
benchmark
ChenFlurMukhopadhyay-SAS2012-Ex2.10_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n056.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.49391 seconds
cpu usage
4.68826
user time
4.42669
system time
0.261572
max virtual memory
1.9010392E7
max residence set size
397156.0
stage attributes
key
value
starexec-result
YES
output
4.53/2.46 YES 4.53/2.46 proof of /export/starexec/sandbox/benchmark/theBenchmark.c 4.53/2.46 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.53/2.46 4.53/2.46 4.53/2.46 Termination of the given C Problem could be proven: 4.53/2.46 4.53/2.46 (0) C Problem 4.53/2.46 (1) CToIRSProof [EQUIVALENT, 0 ms] 4.53/2.46 (2) IntTRS 4.53/2.46 (3) TerminationGraphProcessor [SOUND, 54 ms] 4.53/2.46 (4) IntTRS 4.53/2.46 (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] 4.53/2.46 (6) IntTRS 4.53/2.46 (7) PolynomialOrderProcessor [EQUIVALENT, 0 ms] 4.53/2.46 (8) YES 4.53/2.46 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (0) 4.53/2.46 Obligation: 4.53/2.46 c file /export/starexec/sandbox/benchmark/theBenchmark.c 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (1) CToIRSProof (EQUIVALENT) 4.53/2.46 Parsed C Integer Program as IRS. 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (2) 4.53/2.46 Obligation: 4.53/2.46 Rules: 4.53/2.46 f1(x, y) -> f2(x_1, y) :|: TRUE 4.53/2.46 f2(x1, x2) -> f3(x1, x3) :|: TRUE 4.53/2.46 f4(x4, x5) -> f5(arith, x5) :|: TRUE && arith = x4 + x5 4.53/2.46 f5(x14, x15) -> f6(x14, x16) :|: TRUE && x16 = x15 - 1 4.53/2.46 f3(x8, x9) -> f4(x8, x9) :|: x8 > 0 && x9 < 0 4.53/2.46 f6(x10, x11) -> f3(x10, x11) :|: TRUE 4.53/2.46 f3(x12, x13) -> f7(x12, x13) :|: x12 <= 0 4.53/2.46 f3(x17, x18) -> f7(x17, x18) :|: x18 >= 0 4.53/2.46 Start term: f1(x, y) 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (3) TerminationGraphProcessor (SOUND) 4.53/2.46 Constructed the termination graph and obtained one non-trivial SCC. 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (4) 4.53/2.46 Obligation: 4.53/2.46 Rules: 4.53/2.46 f3(x8, x9) -> f4(x8, x9) :|: x8 > 0 && x9 < 0 4.53/2.46 f6(x10, x11) -> f3(x10, x11) :|: TRUE 4.53/2.46 f5(x14, x15) -> f6(x14, x16) :|: TRUE && x16 = x15 - 1 4.53/2.46 f4(x4, x5) -> f5(arith, x5) :|: TRUE && arith = x4 + x5 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (5) IntTRSCompressionProof (EQUIVALENT) 4.53/2.46 Compressed rules. 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (6) 4.53/2.46 Obligation: 4.53/2.46 Rules: 4.53/2.46 f5(x14:0, x15:0) -> f5(x14:0 + (x15:0 - 1), x15:0 - 1) :|: x14:0 > 0 && x15:0 < 1 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (7) PolynomialOrderProcessor (EQUIVALENT) 4.53/2.46 Found the following polynomial interpretation: 4.53/2.46 [f5(x, x1)] = x 4.53/2.46 4.53/2.46 The following rules are decreasing: 4.53/2.46 f5(x14:0, x15:0) -> f5(x14:0 + (x15:0 - 1), x15:0 - 1) :|: x14:0 > 0 && x15:0 < 1 4.53/2.46 The following rules are bounded: 4.53/2.46 f5(x14:0, x15:0) -> f5(x14:0 + (x15:0 - 1), x15:0 - 1) :|: x14:0 > 0 && x15:0 < 1 4.53/2.46 4.53/2.46 ---------------------------------------- 4.53/2.46 4.53/2.46 (8) 4.53/2.46 YES 4.66/2.49 EOF
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