details

property	value
status	complete
benchmark	403.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n078.star.cs.uiowa.edu
space	COPS

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.0160769 seconds
cpu usage	0.016601
user time	0.008119
system time	0.008482
max virtual memory	113176.0
max residence set size	4300.0

stage attributes

key	value
starexec-result	YES

output

0.00/0.01 YES 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 (VAR v_NonEmpty:S x:S) 0.00/0.01 (RULES 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 ) 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 Valid CTRS Processor: 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 -> The system is a deterministic 3-CTRS. 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Dependency Pairs Processor: 0.00/0.01 0.00/0.01 Conditional Termination Problem 1: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 0.00/0.01 Conditional Termination Problem 2: 0.00/0.01 -> Pairs: 0.00/0.01 E(s(x:S)) -> E(x:S) 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 0.00/0.01 0.00/0.01 The problem is decomposed in 2 subproblems. 0.00/0.01 0.00/0.01 Problem 1.1: 0.00/0.01 0.00/0.01 SCC Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 ->Strongly Connected Components: 0.00/0.01 There is no strongly connected component 0.00/0.01 0.00/0.01 The problem is finite. 0.00/0.01 0.00/0.01 Problem 1.2: 0.00/0.01 0.00/0.01 SCC Processor: 0.00/0.01 -> Pairs: 0.00/0.01 E(s(x:S)) -> E(x:S) 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 ->Strongly Connected Components: 0.00/0.01 ->->Cycle: 0.00/0.01 ->->-> Pairs: 0.00/0.01 E(s(x:S)) -> E(x:S) 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 ->->-> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 0.00/0.01 Problem 1.2: 0.00/0.01 0.00/0.01 Conditional Subterm Processor: 0.00/0.01 -> Pairs: 0.00/0.01 E(s(x:S)) -> E(x:S) 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 e(0) -> ttrue 0.00/0.01 e(s(x:S)) -> ffalse | e(x:S) ->* ttrue 0.00/0.01 e(s(x:S)) -> ttrue | e(x:S) ->* ffalse 0.00/0.01 ->Projection: 0.00/0.01 pi(E) = 1 0.00/0.01 0.00/0.01 Problem 1.2: 0.00/0.01 popout

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job log

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actions

all output return to TRS_Conditional 2019-03-28 22.59