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TRS_Conditional 2019-03-28 22.59 pair #432272568
details
property
value
status
complete
benchmark
325.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
COPS
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.019654 seconds
cpu usage
0.020149
user time
0.008679
system time
0.01147
max virtual memory
113176.0
max residence set size
6644.0
stage attributes
key
value
starexec-result
YES
output
0.00/0.01 YES 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 (VAR v_NonEmpty:S x:S) 0.00/0.01 (RULES 0.00/0.01 a -> c 0.00/0.01 a -> d 0.00/0.01 b -> c 0.00/0.01 b -> d 0.00/0.01 c -> e 0.00/0.01 c -> e' 0.00/0.01 c -> l 0.00/0.01 d -> m 0.00/0.01 f(x:S) -> x:S | x:S ->* e, x:S ->* e' 0.00/0.01 g(d,x:S,x:S) -> A 0.00/0.01 h(x:S,x:S) -> g(x:S,x:S,f(k)) 0.00/0.01 k -> l 0.00/0.01 k -> m 0.00/0.01 ) 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 Valid CTRS Processor: 0.00/0.01 -> Rules: 0.00/0.01 a -> c 0.00/0.01 a -> d 0.00/0.01 b -> c 0.00/0.01 b -> d 0.00/0.01 c -> e 0.00/0.01 c -> e' 0.00/0.01 c -> l 0.00/0.01 d -> m 0.00/0.01 f(x:S) -> x:S | x:S ->* e, x:S ->* e' 0.00/0.01 g(d,x:S,x:S) -> A 0.00/0.01 h(x:S,x:S) -> g(x:S,x:S,f(k)) 0.00/0.01 k -> l 0.00/0.01 k -> m 0.00/0.01 -> The system is a deterministic 3-CTRS. 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Dependency Pairs Processor: 0.00/0.01 0.00/0.01 Conditional Termination Problem 1: 0.00/0.01 -> Pairs: 0.00/0.01 a# -> C 0.00/0.01 a# -> D 0.00/0.01 B -> C 0.00/0.01 B -> D 0.00/0.01 H(x:S,x:S) -> F(k) 0.00/0.01 H(x:S,x:S) -> G(x:S,x:S,f(k)) 0.00/0.01 H(x:S,x:S) -> K 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 a -> c 0.00/0.01 a -> d 0.00/0.01 b -> c 0.00/0.01 b -> d 0.00/0.01 c -> e 0.00/0.01 c -> e' 0.00/0.01 c -> l 0.00/0.01 d -> m 0.00/0.01 f(x:S) -> x:S | x:S ->* e, x:S ->* e' 0.00/0.01 g(d,x:S,x:S) -> A 0.00/0.01 h(x:S,x:S) -> g(x:S,x:S,f(k)) 0.00/0.01 k -> l 0.00/0.01 k -> m 0.00/0.01 0.00/0.01 Conditional Termination Problem 2: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> QPairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 a -> c 0.00/0.01 a -> d 0.00/0.01 b -> c 0.00/0.01 b -> d 0.00/0.01 c -> e 0.00/0.01 c -> e' 0.00/0.01 c -> l 0.00/0.01 d -> m 0.00/0.01 f(x:S) -> x:S | x:S ->* e, x:S ->* e' 0.00/0.01 g(d,x:S,x:S) -> A 0.00/0.01 h(x:S,x:S) -> g(x:S,x:S,f(k)) 0.00/0.01 k -> l 0.00/0.01 k -> m 0.00/0.01 0.00/0.01 0.00/0.01 The problem is decomposed in 2 subproblems. 0.00/0.01 0.00/0.01 Problem 1.1: 0.00/0.01 0.00/0.01 SCC Processor: 0.00/0.01 -> Pairs: 0.00/0.01 a# -> C 0.00/0.01 a# -> D 0.00/0.01 B -> C 0.00/0.01 B -> D
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