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TRS_Conditional 2019-03-28 22.59 pair #432272616
details
property
value
status
complete
benchmark
389.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n070.star.cs.uiowa.edu
space
COPS
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
40.198 seconds
cpu usage
40.1706
user time
38.5799
system time
1.59067
max virtual memory
1403172.0
max residence set size
307064.0
stage attributes
key
value
starexec-result
NO
output
40.04/40.19 NO 40.04/40.19 40.04/40.19 Problem 1: 40.04/40.19 40.04/40.19 (VAR v_NonEmpty:S x:S z:S) 40.04/40.19 (RULES 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 ) 40.04/40.19 40.04/40.19 Problem 1: 40.04/40.19 Valid CTRS Processor: 40.04/40.19 -> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 -> The system is a deterministic 3-CTRS. 40.04/40.19 40.04/40.19 Problem 1: 40.04/40.19 40.04/40.19 Dependency Pairs Processor: 40.04/40.19 40.04/40.19 Conditional Termination Problem 1: 40.04/40.19 -> Pairs: 40.04/40.19 A -> A 40.04/40.19 A -> F(a) 40.04/40.19 -> QPairs: 40.04/40.19 Empty 40.04/40.19 -> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 40.04/40.19 Conditional Termination Problem 2: 40.04/40.19 -> Pairs: 40.04/40.19 F(x:S) -> F(x:S) 40.04/40.19 -> QPairs: 40.04/40.19 Empty 40.04/40.19 -> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 40.04/40.19 Problem 1: 40.04/40.19 40.04/40.19 SCC Processor: 40.04/40.19 -> Pairs: 40.04/40.19 A -> A 40.04/40.19 A -> F(a) 40.04/40.19 -> QPairs: 40.04/40.19 Empty 40.04/40.19 -> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 ->Strongly Connected Components: 40.04/40.19 ->->Cycle: 40.04/40.19 ->->-> Pairs: 40.04/40.19 A -> A 40.04/40.19 -> QPairs: 40.04/40.19 Empty 40.04/40.19 ->->-> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 40.04/40.19 Problem 1: 40.04/40.19 40.04/40.19 Infinite Processor: 40.04/40.19 -> Pairs: 40.04/40.19 A -> A 40.04/40.19 -> QPairs: 40.04/40.19 Empty 40.04/40.19 -> Rules: 40.04/40.19 a -> f(a) 40.04/40.19 f(x:S) -> b | f(x:S) ->* z:S, x:S ->* z:S 40.04/40.19 -> Pairs in cycle: 40.04/40.19 A -> A 40.04/40.19 40.04/40.19 The problem is infinite. 40.04/40.19 EOF
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