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TRS_Conditional 2019-03-28 22.59 pair #432272656
details
property
value
status
complete
benchmark
ohl190.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n122.star.cs.uiowa.edu
space
Mixed_CTRS_2014
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.0327881 seconds
cpu usage
0.027622
user time
0.009802
system time
0.01782
max virtual memory
113132.0
max residence set size
4760.0
stage attributes
key
value
starexec-result
YES
output
0.00/0.02 YES 0.00/0.02 0.00/0.02 Problem 1: 0.00/0.02 0.00/0.02 (VAR v_NonEmpty:S) 0.00/0.02 (RULES 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 ) 0.00/0.02 0.00/0.02 Problem 1: 0.00/0.02 Valid CTRS Processor: 0.00/0.02 -> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 -> The system is a deterministic 3-CTRS. 0.00/0.02 0.00/0.02 Problem 1: 0.00/0.02 0.00/0.02 Dependency Pairs Processor: 0.00/0.02 0.00/0.02 Conditional Termination Problem 1: 0.00/0.02 -> Pairs: 0.00/0.02 F(b) -> A 0.00/0.02 F(b) -> F(a) 0.00/0.02 -> QPairs: 0.00/0.02 Empty 0.00/0.02 -> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 0.00/0.02 Conditional Termination Problem 2: 0.00/0.02 -> Pairs: 0.00/0.02 A -> B 0.00/0.02 -> QPairs: 0.00/0.02 Empty 0.00/0.02 -> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 0.00/0.02 0.00/0.02 The problem is decomposed in 2 subproblems. 0.00/0.02 0.00/0.02 Problem 1.1: 0.00/0.02 0.00/0.02 SCC Processor: 0.00/0.02 -> Pairs: 0.00/0.02 F(b) -> A 0.00/0.02 F(b) -> F(a) 0.00/0.02 -> QPairs: 0.00/0.02 Empty 0.00/0.02 -> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 ->Strongly Connected Components: 0.00/0.02 ->->Cycle: 0.00/0.02 ->->-> Pairs: 0.00/0.02 F(b) -> F(a) 0.00/0.02 -> QPairs: 0.00/0.02 Empty 0.00/0.02 ->->-> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 0.00/0.02 Problem 1.1: 0.00/0.02 0.00/0.02 Reduction Triple Processor: 0.00/0.02 -> Pairs: 0.00/0.02 F(b) -> F(a) 0.00/0.02 -> QPairs: 0.00/0.02 Empty 0.00/0.02 -> Rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 f(b) -> f(a) 0.00/0.02 -> Usable rules: 0.00/0.02 a -> c | b ->* c 0.00/0.02 b -> c 0.00/0.02 ->Interpretation type: 0.00/0.02 Linear 0.00/0.02 ->Coefficients: 0.00/0.02 Natural Numbers 0.00/0.02 ->Dimension: 0.00/0.02 1 0.00/0.02 ->Bound: 0.00/0.02 2 0.00/0.02 ->Interpretation: 0.00/0.02 0.00/0.02 [a] = 1 0.00/0.02 [b] = 2 0.00/0.02 [f](X) = 0 0.00/0.02 [c] = 0 0.00/0.02 [fSNonEmpty] = 0 0.00/0.02 [A] = 0
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