details

property	value
status	complete
benchmark	Et2-rec.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n090.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	0.696863 seconds
cpu usage	0.709033
user time	0.387688
system time	0.321345
max virtual memory	124872.0
max residence set size	8516.0

stage attributes

key	value
starexec-result	MAYBE

output

0.66/0.69 MAYBE 0.66/0.69 0.66/0.69 DP problem for innermost termination. 0.66/0.69 P = 0.66/0.69 init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.66/0.69 f2#(I0, I1, I2, I3) -> f2#(I4, I5, I2, I3 + 1) [0 <= I1 - 1 /\ 0 <= I2 - 1 /\ -1 <= I3 - 1 /\ I3 <= I2 - 1 /\ I3 + 1 <= I2 /\ -1 <= y1 - 1 /\ I0 - 1 - y1 = I4 /\ I0 - 1 - y1 = I5] 0.66/0.69 f2#(I6, I7, I8, I9) -> f2#(I6 - 1, I6 - 1, I8, I9) [0 <= I7 - 1 /\ I8 <= I9 /\ I6 - 1 <= I6 - 1 /\ -1 <= I8 - 1] 0.66/0.69 f1#(I10, I11, I12, I13) -> f2#(I14, I15, I11, 2) [0 <= I10 - 1 /\ -1 <= I14 - 1 /\ 1 <= I11 - 1 /\ -1 <= I15 - 1] 0.66/0.69 f1#(I16, I17, I18, I19) -> f2#(I20, 0, 1, 1) [1 = I17 /\ -1 <= I20 - 1 /\ 0 <= I16 - 1] 0.66/0.69 f1#(I21, I22, I23, I24) -> f2#(0, 0, 0, 0) [0 = I22 /\ 0 <= I21 - 1] 0.66/0.69 R = 0.66/0.69 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.66/0.69 f2(I0, I1, I2, I3) -> f2(I4, I5, I2, I3 + 1) [0 <= I1 - 1 /\ 0 <= I2 - 1 /\ -1 <= I3 - 1 /\ I3 <= I2 - 1 /\ I3 + 1 <= I2 /\ -1 <= y1 - 1 /\ I0 - 1 - y1 = I4 /\ I0 - 1 - y1 = I5] 0.66/0.69 f2(I6, I7, I8, I9) -> f2(I6 - 1, I6 - 1, I8, I9) [0 <= I7 - 1 /\ I8 <= I9 /\ I6 - 1 <= I6 - 1 /\ -1 <= I8 - 1] 0.66/0.69 f1(I10, I11, I12, I13) -> f2(I14, I15, I11, 2) [0 <= I10 - 1 /\ -1 <= I14 - 1 /\ 1 <= I11 - 1 /\ -1 <= I15 - 1] 0.66/0.69 f1(I16, I17, I18, I19) -> f2(I20, 0, 1, 1) [1 = I17 /\ -1 <= I20 - 1 /\ 0 <= I16 - 1] 0.66/0.69 f1(I21, I22, I23, I24) -> f2(0, 0, 0, 0) [0 = I22 /\ 0 <= I21 - 1] 0.66/0.69 0.66/0.69 The dependency graph for this problem is: 0.66/0.69 0 -> 3, 4, 5 0.66/0.69 1 -> 1, 2 0.66/0.69 2 -> 2 0.66/0.69 3 -> 1, 2 0.66/0.69 4 -> 0.66/0.69 5 -> 0.66/0.69 Where: 0.66/0.69 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 0.66/0.69 1) f2#(I0, I1, I2, I3) -> f2#(I4, I5, I2, I3 + 1) [0 <= I1 - 1 /\ 0 <= I2 - 1 /\ -1 <= I3 - 1 /\ I3 <= I2 - 1 /\ I3 + 1 <= I2 /\ -1 <= y1 - 1 /\ I0 - 1 - y1 = I4 /\ I0 - 1 - y1 = I5] 0.66/0.69 2) f2#(I6, I7, I8, I9) -> f2#(I6 - 1, I6 - 1, I8, I9) [0 <= I7 - 1 /\ I8 <= I9 /\ I6 - 1 <= I6 - 1 /\ -1 <= I8 - 1] 0.66/0.69 3) f1#(I10, I11, I12, I13) -> f2#(I14, I15, I11, 2) [0 <= I10 - 1 /\ -1 <= I14 - 1 /\ 1 <= I11 - 1 /\ -1 <= I15 - 1] 0.66/0.69 4) f1#(I16, I17, I18, I19) -> f2#(I20, 0, 1, 1) [1 = I17 /\ -1 <= I20 - 1 /\ 0 <= I16 - 1] 0.66/0.69 5) f1#(I21, I22, I23, I24) -> f2#(0, 0, 0, 0) [0 = I22 /\ 0 <= I21 - 1] 0.66/0.69 0.66/0.69 We have the following SCCs. 0.66/0.69 { 1 } 0.66/0.69 { 2 } 0.66/0.69 0.66/0.69 DP problem for innermost termination. 0.66/0.69 P = 0.66/0.69 f2#(I6, I7, I8, I9) -> f2#(I6 - 1, I6 - 1, I8, I9) [0 <= I7 - 1 /\ I8 <= I9 /\ I6 - 1 <= I6 - 1 /\ -1 <= I8 - 1] 0.66/0.69 R = 0.66/0.69 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 0.66/0.69 f2(I0, I1, I2, I3) -> f2(I4, I5, I2, I3 + 1) [0 <= I1 - 1 /\ 0 <= I2 - 1 /\ -1 <= I3 - 1 /\ I3 <= I2 - 1 /\ I3 + 1 <= I2 /\ -1 <= y1 - 1 /\ I0 - 1 - y1 = I4 /\ I0 - 1 - y1 = I5] 0.66/0.69 f2(I6, I7, I8, I9) -> f2(I6 - 1, I6 - 1, I8, I9) [0 <= I7 - 1 /\ I8 <= I9 /\ I6 - 1 <= I6 - 1 /\ -1 <= I8 - 1] 0.66/0.69 f1(I10, I11, I12, I13) -> f2(I14, I15, I11, 2) [0 <= I10 - 1 /\ -1 <= I14 - 1 /\ 1 <= I11 - 1 /\ -1 <= I15 - 1] 0.66/0.69 f1(I16, I17, I18, I19) -> f2(I20, 0, 1, 1) [1 = I17 /\ -1 <= I20 - 1 /\ 0 <= I16 - 1] 0.66/0.69 f1(I21, I22, I23, I24) -> f2(0, 0, 0, 0) [0 = I22 /\ 0 <= I21 - 1] 0.66/0.69 0.66/3.67 EOF popout

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job log

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54