details

property	value
status	complete
benchmark	Queen.jar-obl-10.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n161.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	3.94199 seconds
cpu usage	3.67266
user time	1.86344
system time	1.80922
max virtual memory	723476.0
max residence set size	8672.0

stage attributes

key	value
starexec-result	MAYBE

output

3.55/3.93 MAYBE 3.55/3.93 3.55/3.93 DP problem for innermost termination. 3.55/3.93 P = 3.55/3.93 init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 3.55/3.93 f7#(I0, I1, I2) -> f6#(1, I1 + 1, I0) [0 = I2] 3.55/3.93 f7#(I3, I4, I5) -> f6#(0, I4 + 1, I3) [1 = I5] 3.55/3.93 f6#(I6, I7, I8) -> f6#(0, I7 + 1, I8) [0 = I6 /\ I7 <= I8 - 1] 3.55/3.93 f6#(I9, I10, I11) -> f7#(I11, I10, 0) [0 <= I11 - 1 /\ 0 <= y1 - 1 /\ 0 <= I9 - 1 /\ I10 <= y1 - 1 /\ I10 <= I11 - 1] 3.55/3.93 f6#(I12, I13, I14) -> f7#(I14, I13, 1) [0 <= I14 - 1 /\ 0 <= I15 - 1 /\ 0 <= I12 - 1 /\ I13 <= I15 - 1 /\ I13 <= I14 - 1] 3.55/3.93 f3#(I16, I17, I18) -> f6#(1, 0, I16) [I17 <= I19 - 1 /\ 0 <= I19 - 1] 3.55/3.93 f5#(I20, I21, I22) -> f5#(I20, I21 + 1, I23) [I21 <= I24 - 1 /\ I20 <= I24 - 1] 3.55/3.93 f5#(I25, I26, I27) -> f5#(I25, I26 + 1, I28) [I26 <= I29 - 1 /\ I26 <= y2 - 1 /\ I25 <= y2 - 1] 3.55/3.93 f5#(I30, I31, I32) -> f5#(I30, I31 + 1, I33) [I34 <= I31 - 1 /\ I31 <= I35 - 1 /\ I30 <= I35 - 1] 3.55/3.93 f5#(I36, I37, I38) -> f4#(I36 + 1, I39, I40) [I41 <= I37] 3.55/3.93 f4#(I42, I43, I44) -> f5#(I42, 0, I45) [I42 <= I46 - 1] 3.55/3.93 f2#(I47, I48, I49) -> f4#(0, I50, I51) [I52 <= I47] 3.55/3.93 f3#(I53, I54, I55) -> f3#(I53, I54 + 1, I56) [0 <= I57 - 1 /\ I54 <= I57 - 1 /\ 0 <= I58 - 1 /\ -1 <= I53 - 1 /\ I53 <= I57 - 1 /\ I53 <= I53 + 1 - 1] 3.55/3.93 f3#(I59, I60, I61) -> f2#(I59 + 1, I62, I63) [0 <= I64 - 1 /\ I60 <= I64 - 1 /\ 0 <= I65 - 1 /\ -1 <= I59 - 1 /\ I59 <= I64 - 1 /\ I59 <= I59 + 1 - 1] 3.55/3.93 f3#(I66, I67, I68) -> f3#(I66, I67 + 1, I69) [I67 <= I70 - 1 /\ 0 <= I70 - 1] 3.55/3.93 f2#(I71, I72, I73) -> f3#(I71, 0, I74) [I71 <= I75 - 1] 3.55/3.93 f1#(I76, I77, I78) -> f2#(0, I79, I80) [-1 <= I77 - 1 /\ 0 <= I76 - 1] 3.55/3.93 R = 3.55/3.93 init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 3.55/3.93 f7(I0, I1, I2) -> f6(1, I1 + 1, I0) [0 = I2] 3.55/3.93 f7(I3, I4, I5) -> f6(0, I4 + 1, I3) [1 = I5] 3.55/3.93 f6(I6, I7, I8) -> f6(0, I7 + 1, I8) [0 = I6 /\ I7 <= I8 - 1] 3.55/3.93 f6(I9, I10, I11) -> f7(I11, I10, 0) [0 <= I11 - 1 /\ 0 <= y1 - 1 /\ 0 <= I9 - 1 /\ I10 <= y1 - 1 /\ I10 <= I11 - 1] 3.55/3.93 f6(I12, I13, I14) -> f7(I14, I13, 1) [0 <= I14 - 1 /\ 0 <= I15 - 1 /\ 0 <= I12 - 1 /\ I13 <= I15 - 1 /\ I13 <= I14 - 1] 3.55/3.93 f3(I16, I17, I18) -> f6(1, 0, I16) [I17 <= I19 - 1 /\ 0 <= I19 - 1] 3.55/3.93 f5(I20, I21, I22) -> f5(I20, I21 + 1, I23) [I21 <= I24 - 1 /\ I20 <= I24 - 1] 3.55/3.93 f5(I25, I26, I27) -> f5(I25, I26 + 1, I28) [I26 <= I29 - 1 /\ I26 <= y2 - 1 /\ I25 <= y2 - 1] 3.55/3.93 f5(I30, I31, I32) -> f5(I30, I31 + 1, I33) [I34 <= I31 - 1 /\ I31 <= I35 - 1 /\ I30 <= I35 - 1] 3.55/3.93 f5(I36, I37, I38) -> f4(I36 + 1, I39, I40) [I41 <= I37] 3.55/3.93 f4(I42, I43, I44) -> f5(I42, 0, I45) [I42 <= I46 - 1] 3.55/3.93 f2(I47, I48, I49) -> f4(0, I50, I51) [I52 <= I47] 3.55/3.93 f3(I53, I54, I55) -> f3(I53, I54 + 1, I56) [0 <= I57 - 1 /\ I54 <= I57 - 1 /\ 0 <= I58 - 1 /\ -1 <= I53 - 1 /\ I53 <= I57 - 1 /\ I53 <= I53 + 1 - 1] 3.55/3.93 f3(I59, I60, I61) -> f2(I59 + 1, I62, I63) [0 <= I64 - 1 /\ I60 <= I64 - 1 /\ 0 <= I65 - 1 /\ -1 <= I59 - 1 /\ I59 <= I64 - 1 /\ I59 <= I59 + 1 - 1] 3.55/3.93 f3(I66, I67, I68) -> f3(I66, I67 + 1, I69) [I67 <= I70 - 1 /\ 0 <= I70 - 1] 3.55/3.93 f2(I71, I72, I73) -> f3(I71, 0, I74) [I71 <= I75 - 1] 3.55/3.93 f1(I76, I77, I78) -> f2(0, I79, I80) [-1 <= I77 - 1 /\ 0 <= I76 - 1] 3.55/3.93 3.55/3.93 The dependency graph for this problem is: 3.55/3.93 0 -> 17 3.55/3.93 1 -> 4, 5 3.55/3.93 2 -> 3 3.55/3.93 3 -> 3 3.55/3.93 4 -> 1 3.55/3.93 5 -> 2 3.55/3.93 6 -> 4, 5 3.55/3.93 7 -> 7, 8, 9, 10 3.55/3.93 8 -> 7, 8, 9, 10 3.55/3.93 9 -> 7, 8, 9, 10 3.55/3.93 10 -> 11 3.55/3.93 11 -> 7, 8, 9, 10 3.55/3.93 12 -> 11 3.55/3.93 13 -> 6, 13, 14, 15 3.55/3.93 14 -> 12, 16 3.55/3.93 15 -> 6, 13, 14, 15 3.55/3.93 16 -> 6, 13, 14, 15 3.55/3.93 17 -> 12, 16 3.55/3.93 Where: 3.55/3.93 0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 3.55/3.93 1) f7#(I0, I1, I2) -> f6#(1, I1 + 1, I0) [0 = I2] 3.55/3.93 2) f7#(I3, I4, I5) -> f6#(0, I4 + 1, I3) [1 = I5] 3.55/3.93 3) f6#(I6, I7, I8) -> f6#(0, I7 + 1, I8) [0 = I6 /\ I7 <= I8 - 1] 3.55/3.93 4) f6#(I9, I10, I11) -> f7#(I11, I10, 0) [0 <= I11 - 1 /\ 0 <= y1 - 1 /\ 0 <= I9 - 1 /\ I10 <= y1 - 1 /\ I10 <= I11 - 1] 3.55/3.93 5) f6#(I12, I13, I14) -> f7#(I14, I13, 1) [0 <= I14 - 1 /\ 0 <= I15 - 1 /\ 0 <= I12 - 1 /\ I13 <= I15 - 1 /\ I13 <= I14 - 1] 3.55/3.93 6) f3#(I16, I17, I18) -> f6#(1, 0, I16) [I17 <= I19 - 1 /\ 0 <= I19 - 1] 3.55/3.93 7) f5#(I20, I21, I22) -> f5#(I20, I21 + 1, I23) [I21 <= I24 - 1 /\ I20 <= I24 - 1] 3.55/3.93 8) f5#(I25, I26, I27) -> f5#(I25, I26 + 1, I28) [I26 <= I29 - 1 /\ I26 <= y2 - 1 /\ I25 <= y2 - 1] 3.55/3.93 9) f5#(I30, I31, I32) -> f5#(I30, I31 + 1, I33) [I34 <= I31 - 1 /\ I31 <= I35 - 1 /\ I30 <= I35 - 1] 3.55/3.93 10) f5#(I36, I37, I38) -> f4#(I36 + 1, I39, I40) [I41 <= I37] 3.55/3.93 11) f4#(I42, I43, I44) -> f5#(I42, 0, I45) [I42 <= I46 - 1] 3.55/3.93 12) f2#(I47, I48, I49) -> f4#(0, I50, I51) [I52 <= I47] 3.55/3.93 13) f3#(I53, I54, I55) -> f3#(I53, I54 + 1, I56) [0 <= I57 - 1 /\ I54 <= I57 - 1 /\ 0 <= I58 - 1 /\ -1 <= I53 - 1 /\ I53 <= I57 - 1 /\ I53 <= I53 + 1 - 1] 3.55/3.93 14) f3#(I59, I60, I61) -> f2#(I59 + 1, I62, I63) [0 <= I64 - 1 /\ I60 <= I64 - 1 /\ 0 <= I65 - 1 /\ -1 <= I59 - 1 /\ I59 <= I64 - 1 /\ I59 <= I59 + 1 - 1] 3.55/3.93 15) f3#(I66, I67, I68) -> f3#(I66, I67 + 1, I69) [I67 <= I70 - 1 /\ 0 <= I70 - 1] 3.55/3.93 16) f2#(I71, I72, I73) -> f3#(I71, 0, I74) [I71 <= I75 - 1] 3.55/3.93 17) f1#(I76, I77, I78) -> f2#(0, I79, I80) [-1 <= I77 - 1 /\ 0 <= I76 - 1] 3.55/3.93 3.55/3.93 We have the following SCCs. 3.55/3.93 { 13, 14, 15, 16 } 3.55/3.93 { 1, 4 } 3.55/3.93 { 3 } 3.55/3.93 { 7, 8, 9, 10, 11 } 3.55/3.93 3.55/3.93 DP problem for innermost termination. 3.55/3.93 P = 3.55/3.93 f5#(I20, I21, I22) -> f5#(I20, I21 + 1, I23) [I21 <= I24 - 1 /\ I20 <= I24 - 1] 3.55/3.93 f5#(I25, I26, I27) -> f5#(I25, I26 + 1, I28) [I26 <= I29 - 1 /\ I26 <= y2 - 1 /\ I25 <= y2 - 1] 3.55/3.93 f5#(I30, I31, I32) -> f5#(I30, I31 + 1, I33) [I34 <= I31 - 1 /\ I31 <= I35 - 1 /\ I30 <= I35 - 1] 3.55/3.93 f5#(I36, I37, I38) -> f4#(I36 + 1, I39, I40) [I41 <= I37] 3.55/3.93 f4#(I42, I43, I44) -> f5#(I42, 0, I45) [I42 <= I46 - 1] 3.55/3.93 R = 3.55/3.93 init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 3.55/3.93 f7(I0, I1, I2) -> f6(1, I1 + 1, I0) [0 = I2] 3.55/3.93 f7(I3, I4, I5) -> f6(0, I4 + 1, I3) [1 = I5] 3.55/3.93 f6(I6, I7, I8) -> f6(0, I7 + 1, I8) [0 = I6 /\ I7 <= I8 - 1] 3.55/3.93 f6(I9, I10, I11) -> f7(I11, I10, 0) [0 <= I11 - 1 /\ 0 <= y1 - 1 /\ 0 <= I9 - 1 /\ I10 <= y1 - 1 /\ I10 <= I11 - 1] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54