details

property	value
status	complete
benchmark	complxStruc_rec.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n158.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	23.8247 seconds
cpu usage	23.7493
user time	11.9163
system time	11.833
max virtual memory	740716.0
max residence set size	12756.0

stage attributes

key	value
starexec-result	MAYBE

output

23.70/23.82 MAYBE 23.70/23.82 23.70/23.82 DP problem for innermost termination. 23.70/23.82 P = 23.70/23.82 init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 23.70/23.82 f2#(I0, I1, I2, I3) -> f2#(I0, I1 + 1, I0, I4) [I0 = I2 /\ -1 <= I1 - 1 /\ 2 <= I0 - 1 - (I1 + 1) - 1 /\ I1 <= 4 /\ I1 <= I0 /\ 0 <= I0 - 1] 23.70/23.82 f2#(I5, I6, I7, I8) -> f2#(I5 - 1, I6 + 2, I5 - 1, I9) [I5 = I7 /\ -1 <= I6 - 1 /\ I5 - 1 - (I6 + 1) <= 2 /\ I6 <= 4 /\ I6 <= I5 /\ 0 <= I5 - 1] 23.70/23.82 f3#(I10, I11, I12, I13) -> f2#(I12, I13, I12, I14) [I10 <= I13 /\ I12 <= I11 /\ I10 <= I11 - 1 /\ 0 <= I13 - 1 /\ 1 <= I12 - 1 /\ 1 <= I11 - 1 /\ 0 <= I10 - 1] 23.70/23.82 f2#(I15, I16, I17, I18) -> f3#(I15, I16, I15 + 1, I16 - 1) [I15 = I17 /\ 0 <= I15 - 1 /\ I15 + 1 <= 2 * I16 - 1 /\ 1 <= I16 - 1 /\ I15 <= I16 - 1] 23.70/23.82 f2#(I19, I20, I21, I22) -> f3#(I19, I20, I19 + 1, I20 + 1) [I19 = I21 /\ 0 <= I19 - 1 /\ 2 * I20 <= I19 + 1 /\ 1 <= I20 - 1 /\ I19 <= I20 - 1] 23.70/23.82 f2#(I23, I24, I25, I26) -> f2#(I23 - 1, I24 - 1, I23 - 1, I27) [I23 = I25 /\ 4 <= I24 - 1 /\ 1 <= I23 - 1 /\ I24 <= I23] 23.70/23.82 f1#(I28, I29, I30, I31) -> f2#(I29, I29, I29, I32) [-1 <= I29 - 1 /\ 0 <= I28 - 1] 23.70/23.82 R = 23.70/23.82 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 23.70/23.82 f2(I0, I1, I2, I3) -> f2(I0, I1 + 1, I0, I4) [I0 = I2 /\ -1 <= I1 - 1 /\ 2 <= I0 - 1 - (I1 + 1) - 1 /\ I1 <= 4 /\ I1 <= I0 /\ 0 <= I0 - 1] 23.70/23.82 f2(I5, I6, I7, I8) -> f2(I5 - 1, I6 + 2, I5 - 1, I9) [I5 = I7 /\ -1 <= I6 - 1 /\ I5 - 1 - (I6 + 1) <= 2 /\ I6 <= 4 /\ I6 <= I5 /\ 0 <= I5 - 1] 23.70/23.82 f3(I10, I11, I12, I13) -> f2(I12, I13, I12, I14) [I10 <= I13 /\ I12 <= I11 /\ I10 <= I11 - 1 /\ 0 <= I13 - 1 /\ 1 <= I12 - 1 /\ 1 <= I11 - 1 /\ 0 <= I10 - 1] 23.70/23.82 f2(I15, I16, I17, I18) -> f3(I15, I16, I15 + 1, I16 - 1) [I15 = I17 /\ 0 <= I15 - 1 /\ I15 + 1 <= 2 * I16 - 1 /\ 1 <= I16 - 1 /\ I15 <= I16 - 1] 23.70/23.82 f2(I19, I20, I21, I22) -> f3(I19, I20, I19 + 1, I20 + 1) [I19 = I21 /\ 0 <= I19 - 1 /\ 2 * I20 <= I19 + 1 /\ 1 <= I20 - 1 /\ I19 <= I20 - 1] 23.70/23.82 f2(I23, I24, I25, I26) -> f2(I23 - 1, I24 - 1, I23 - 1, I27) [I23 = I25 /\ 4 <= I24 - 1 /\ 1 <= I23 - 1 /\ I24 <= I23] 23.70/23.82 f1(I28, I29, I30, I31) -> f2(I29, I29, I29, I32) [-1 <= I29 - 1 /\ 0 <= I28 - 1] 23.70/23.82 23.70/23.82 The dependency graph for this problem is: 23.70/23.82 0 -> 7 23.70/23.82 1 -> 1, 2, 6 23.70/23.82 2 -> 2, 4, 6 23.70/23.82 3 -> 1, 2, 4, 6 23.70/23.82 4 -> 3 23.70/23.82 5 -> 23.70/23.82 6 -> 1, 2, 6 23.70/23.82 7 -> 2, 6 23.70/23.82 Where: 23.70/23.82 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 23.70/23.82 1) f2#(I0, I1, I2, I3) -> f2#(I0, I1 + 1, I0, I4) [I0 = I2 /\ -1 <= I1 - 1 /\ 2 <= I0 - 1 - (I1 + 1) - 1 /\ I1 <= 4 /\ I1 <= I0 /\ 0 <= I0 - 1] 23.70/23.82 2) f2#(I5, I6, I7, I8) -> f2#(I5 - 1, I6 + 2, I5 - 1, I9) [I5 = I7 /\ -1 <= I6 - 1 /\ I5 - 1 - (I6 + 1) <= 2 /\ I6 <= 4 /\ I6 <= I5 /\ 0 <= I5 - 1] 23.70/23.82 3) f3#(I10, I11, I12, I13) -> f2#(I12, I13, I12, I14) [I10 <= I13 /\ I12 <= I11 /\ I10 <= I11 - 1 /\ 0 <= I13 - 1 /\ 1 <= I12 - 1 /\ 1 <= I11 - 1 /\ 0 <= I10 - 1] 23.70/23.82 4) f2#(I15, I16, I17, I18) -> f3#(I15, I16, I15 + 1, I16 - 1) [I15 = I17 /\ 0 <= I15 - 1 /\ I15 + 1 <= 2 * I16 - 1 /\ 1 <= I16 - 1 /\ I15 <= I16 - 1] 23.70/23.82 5) f2#(I19, I20, I21, I22) -> f3#(I19, I20, I19 + 1, I20 + 1) [I19 = I21 /\ 0 <= I19 - 1 /\ 2 * I20 <= I19 + 1 /\ 1 <= I20 - 1 /\ I19 <= I20 - 1] 23.70/23.82 6) f2#(I23, I24, I25, I26) -> f2#(I23 - 1, I24 - 1, I23 - 1, I27) [I23 = I25 /\ 4 <= I24 - 1 /\ 1 <= I23 - 1 /\ I24 <= I23] 23.70/23.82 7) f1#(I28, I29, I30, I31) -> f2#(I29, I29, I29, I32) [-1 <= I29 - 1 /\ 0 <= I28 - 1] 23.70/23.82 23.70/23.82 We have the following SCCs. 23.70/23.82 { 1, 2, 3, 4, 6 } 23.70/23.82 23.70/23.82 DP problem for innermost termination. 23.70/23.82 P = 23.70/23.82 f2#(I0, I1, I2, I3) -> f2#(I0, I1 + 1, I0, I4) [I0 = I2 /\ -1 <= I1 - 1 /\ 2 <= I0 - 1 - (I1 + 1) - 1 /\ I1 <= 4 /\ I1 <= I0 /\ 0 <= I0 - 1] 23.70/23.82 f2#(I5, I6, I7, I8) -> f2#(I5 - 1, I6 + 2, I5 - 1, I9) [I5 = I7 /\ -1 <= I6 - 1 /\ I5 - 1 - (I6 + 1) <= 2 /\ I6 <= 4 /\ I6 <= I5 /\ 0 <= I5 - 1] 23.70/23.82 f3#(I10, I11, I12, I13) -> f2#(I12, I13, I12, I14) [I10 <= I13 /\ I12 <= I11 /\ I10 <= I11 - 1 /\ 0 <= I13 - 1 /\ 1 <= I12 - 1 /\ 1 <= I11 - 1 /\ 0 <= I10 - 1] 23.70/23.82 f2#(I15, I16, I17, I18) -> f3#(I15, I16, I15 + 1, I16 - 1) [I15 = I17 /\ 0 <= I15 - 1 /\ I15 + 1 <= 2 * I16 - 1 /\ 1 <= I16 - 1 /\ I15 <= I16 - 1] 23.70/23.82 f2#(I23, I24, I25, I26) -> f2#(I23 - 1, I24 - 1, I23 - 1, I27) [I23 = I25 /\ 4 <= I24 - 1 /\ 1 <= I23 - 1 /\ I24 <= I23] 23.70/23.82 R = 23.70/23.82 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 23.70/23.82 f2(I0, I1, I2, I3) -> f2(I0, I1 + 1, I0, I4) [I0 = I2 /\ -1 <= I1 - 1 /\ 2 <= I0 - 1 - (I1 + 1) - 1 /\ I1 <= 4 /\ I1 <= I0 /\ 0 <= I0 - 1] 23.70/23.82 f2(I5, I6, I7, I8) -> f2(I5 - 1, I6 + 2, I5 - 1, I9) [I5 = I7 /\ -1 <= I6 - 1 /\ I5 - 1 - (I6 + 1) <= 2 /\ I6 <= 4 /\ I6 <= I5 /\ 0 <= I5 - 1] 23.70/23.82 f3(I10, I11, I12, I13) -> f2(I12, I13, I12, I14) [I10 <= I13 /\ I12 <= I11 /\ I10 <= I11 - 1 /\ 0 <= I13 - 1 /\ 1 <= I12 - 1 /\ 1 <= I11 - 1 /\ 0 <= I10 - 1] 23.70/23.82 f2(I15, I16, I17, I18) -> f3(I15, I16, I15 + 1, I16 - 1) [I15 = I17 /\ 0 <= I15 - 1 /\ I15 + 1 <= 2 * I16 - 1 /\ 1 <= I16 - 1 /\ I15 <= I16 - 1] 23.70/23.82 f2(I19, I20, I21, I22) -> f3(I19, I20, I19 + 1, I20 + 1) [I19 = I21 /\ 0 <= I19 - 1 /\ 2 * I20 <= I19 + 1 /\ 1 <= I20 - 1 /\ I19 <= I20 - 1] 23.70/23.82 f2(I23, I24, I25, I26) -> f2(I23 - 1, I24 - 1, I23 - 1, I27) [I23 = I25 /\ 4 <= I24 - 1 /\ 1 <= I23 - 1 /\ I24 <= I23] 23.70/23.82 f1(I28, I29, I30, I31) -> f2(I29, I29, I29, I32) [-1 <= I29 - 1 /\ 0 <= I28 - 1] 23.70/23.82 23.70/23.82 EOF popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer_Transition_Systems 2019-03-29 01.54