details

property	value
status	complete
benchmark	Velroyen08-ex09half.jar-obl-8.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n092.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	4.66468 seconds
cpu usage	4.47494
user time	2.39828
system time	2.07665
max virtual memory	351992.0
max residence set size	8632.0

stage attributes

key	value
starexec-result	MAYBE

output

4.37/4.66 MAYBE 4.37/4.66 4.37/4.66 DP problem for innermost termination. 4.37/4.66 P = 4.37/4.66 init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 4.37/4.66 f3#(I0, I1, I2, I3) -> f2#(I4, I5, I6, I3) [-1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I4 <= I0 /\ 0 <= I0 - 1 /\ 0 <= I4 - 1 /\ I3 - I1 - 2 * y1 <= 1 /\ 0 <= I3 - I1 - 2 * y1 /\ I1 + y1 = I5 /\ I3 - (I1 + y1) = I6] 4.37/4.66 f2#(I7, I8, I9, I10) -> f3#(I7, I8, I9, I10) [-1 <= I10 - 1 /\ 0 <= I9 - 1 /\ I11 <= I7 /\ 0 <= I7 - 1 /\ 0 <= I11 - 1] 4.37/4.66 f1#(I12, I13, I14, I15) -> f2#(I16, 0, I13, I13) [0 <= I16 - 1 /\ 0 <= I12 - 1 /\ -1 <= I13 - 1 /\ I16 <= I12] 4.37/4.66 R = 4.37/4.66 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 4.37/4.66 f3(I0, I1, I2, I3) -> f2(I4, I5, I6, I3) [-1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I4 <= I0 /\ 0 <= I0 - 1 /\ 0 <= I4 - 1 /\ I3 - I1 - 2 * y1 <= 1 /\ 0 <= I3 - I1 - 2 * y1 /\ I1 + y1 = I5 /\ I3 - (I1 + y1) = I6] 4.37/4.66 f2(I7, I8, I9, I10) -> f3(I7, I8, I9, I10) [-1 <= I10 - 1 /\ 0 <= I9 - 1 /\ I11 <= I7 /\ 0 <= I7 - 1 /\ 0 <= I11 - 1] 4.37/4.66 f1(I12, I13, I14, I15) -> f2(I16, 0, I13, I13) [0 <= I16 - 1 /\ 0 <= I12 - 1 /\ -1 <= I13 - 1 /\ I16 <= I12] 4.37/4.66 4.37/4.66 The dependency graph for this problem is: 4.37/4.66 0 -> 3 4.37/4.66 1 -> 2 4.37/4.66 2 -> 1 4.37/4.66 3 -> 2 4.37/4.66 Where: 4.37/4.66 0) init#(x1, x2, x3, x4) -> f1#(rnd1, rnd2, rnd3, rnd4) 4.37/4.66 1) f3#(I0, I1, I2, I3) -> f2#(I4, I5, I6, I3) [-1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I4 <= I0 /\ 0 <= I0 - 1 /\ 0 <= I4 - 1 /\ I3 - I1 - 2 * y1 <= 1 /\ 0 <= I3 - I1 - 2 * y1 /\ I1 + y1 = I5 /\ I3 - (I1 + y1) = I6] 4.37/4.66 2) f2#(I7, I8, I9, I10) -> f3#(I7, I8, I9, I10) [-1 <= I10 - 1 /\ 0 <= I9 - 1 /\ I11 <= I7 /\ 0 <= I7 - 1 /\ 0 <= I11 - 1] 4.37/4.66 3) f1#(I12, I13, I14, I15) -> f2#(I16, 0, I13, I13) [0 <= I16 - 1 /\ 0 <= I12 - 1 /\ -1 <= I13 - 1 /\ I16 <= I12] 4.37/4.66 4.37/4.66 We have the following SCCs. 4.37/4.66 { 1, 2 } 4.37/4.66 4.37/4.66 DP problem for innermost termination. 4.37/4.66 P = 4.37/4.66 f3#(I0, I1, I2, I3) -> f2#(I4, I5, I6, I3) [-1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I4 <= I0 /\ 0 <= I0 - 1 /\ 0 <= I4 - 1 /\ I3 - I1 - 2 * y1 <= 1 /\ 0 <= I3 - I1 - 2 * y1 /\ I1 + y1 = I5 /\ I3 - (I1 + y1) = I6] 4.37/4.66 f2#(I7, I8, I9, I10) -> f3#(I7, I8, I9, I10) [-1 <= I10 - 1 /\ 0 <= I9 - 1 /\ I11 <= I7 /\ 0 <= I7 - 1 /\ 0 <= I11 - 1] 4.37/4.66 R = 4.37/4.66 init(x1, x2, x3, x4) -> f1(rnd1, rnd2, rnd3, rnd4) 4.37/4.66 f3(I0, I1, I2, I3) -> f2(I4, I5, I6, I3) [-1 <= I3 - 1 /\ 0 <= I2 - 1 /\ I4 <= I0 /\ 0 <= I0 - 1 /\ 0 <= I4 - 1 /\ I3 - I1 - 2 * y1 <= 1 /\ 0 <= I3 - I1 - 2 * y1 /\ I1 + y1 = I5 /\ I3 - (I1 + y1) = I6] 4.37/4.66 f2(I7, I8, I9, I10) -> f3(I7, I8, I9, I10) [-1 <= I10 - 1 /\ 0 <= I9 - 1 /\ I11 <= I7 /\ 0 <= I7 - 1 /\ 0 <= I11 - 1] 4.37/4.66 f1(I12, I13, I14, I15) -> f2(I16, 0, I13, I13) [0 <= I16 - 1 /\ 0 <= I12 - 1 /\ -1 <= I13 - 1 /\ I16 <= I12] 4.37/4.66 4.37/7.64 EOF popout

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54