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Integer_Transition_Systems 2019-03-29 01.54 pair #432273738
details
property
value
status
complete
benchmark
DivMinus2.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n031.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
7.81427 seconds
cpu usage
7.62642
user time
3.86609
system time
3.76033
max virtual memory
744164.0
max residence set size
8692.0
stage attributes
key
value
starexec-result
YES
output
7.59/7.81 YES 7.59/7.81 7.59/7.81 DP problem for innermost termination. 7.59/7.81 P = 7.59/7.81 init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 f3#(I0, I1, I2, I3, I4) -> f2#(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f3#(I12, I13, I14, I15, I16) -> f3#(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 f3#(I17, I18, I19, I20, I21) -> f3#(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 f2#(I22, I23, I24, I25, I26) -> f3#(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 f1#(I27, I28, I29, I30, I31) -> f2#(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1] 7.59/7.81 R = 7.59/7.81 init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 f3(I0, I1, I2, I3, I4) -> f2(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3(I7, I8, I9, I10, I11) -> f3(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f3(I12, I13, I14, I15, I16) -> f3(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 f3(I17, I18, I19, I20, I21) -> f3(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 f2(I22, I23, I24, I25, I26) -> f3(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 f1(I27, I28, I29, I30, I31) -> f2(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1] 7.59/7.81 7.59/7.81 The dependency graph for this problem is: 7.59/7.81 0 -> 6 7.59/7.81 1 -> 5 7.59/7.81 2 -> 1, 2 7.59/7.81 3 -> 7.59/7.81 4 -> 1, 4 7.59/7.81 5 -> 2 7.59/7.81 6 -> 5 7.59/7.81 Where: 7.59/7.81 0) init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 1) f3#(I0, I1, I2, I3, I4) -> f2#(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 2) f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 3) f3#(I12, I13, I14, I15, I16) -> f3#(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 4) f3#(I17, I18, I19, I20, I21) -> f3#(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 5) f2#(I22, I23, I24, I25, I26) -> f3#(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 6) f1#(I27, I28, I29, I30, I31) -> f2#(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1] 7.59/7.81 7.59/7.81 We have the following SCCs. 7.59/7.81 { 4 } 7.59/7.81 { 1, 2, 5 } 7.59/7.81 7.59/7.81 DP problem for innermost termination. 7.59/7.81 P = 7.59/7.81 f3#(I0, I1, I2, I3, I4) -> f2#(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f2#(I22, I23, I24, I25, I26) -> f3#(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 R = 7.59/7.81 init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 f3(I0, I1, I2, I3, I4) -> f2(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3(I7, I8, I9, I10, I11) -> f3(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f3(I12, I13, I14, I15, I16) -> f3(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 f3(I17, I18, I19, I20, I21) -> f3(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 f2(I22, I23, I24, I25, I26) -> f3(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 f1(I27, I28, I29, I30, I31) -> f2(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1] 7.59/7.81 7.59/7.81 We use the extended value criterion with the projection function NU: 7.59/7.81 NU[f2#(x0,x1,x2,x3,x4)] = x1 - x2 7.59/7.81 NU[f3#(x0,x1,x2,x3,x4)] = -x0 + x2 - x3 7.59/7.81 7.59/7.81 This gives the following inequalities: 7.59/7.81 0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1 ==> -I0 + I2 - I3 >= I2 - I0 7.59/7.81 I10 = I11 /\ 0 <= I10 - 1 ==> -I7 + I9 - I10 >= -I7 + (I9 - 1) - (I10 - 1) 7.59/7.81 0 <= I24 - 1 /\ I24 <= I23 ==> I23 - I24 > -I24 + I23 - I24 with I23 - I24 >= 0 7.59/7.81 7.59/7.81 We remove all the strictly oriented dependency pairs. 7.59/7.81 7.59/7.81 DP problem for innermost termination. 7.59/7.81 P = 7.59/7.81 f3#(I0, I1, I2, I3, I4) -> f2#(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 R = 7.59/7.81 init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 f3(I0, I1, I2, I3, I4) -> f2(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3(I7, I8, I9, I10, I11) -> f3(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f3(I12, I13, I14, I15, I16) -> f3(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 f3(I17, I18, I19, I20, I21) -> f3(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 f2(I22, I23, I24, I25, I26) -> f3(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 f1(I27, I28, I29, I30, I31) -> f2(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1] 7.59/7.81 7.59/7.81 The dependency graph for this problem is: 7.59/7.81 1 -> 7.59/7.81 2 -> 1, 2 7.59/7.81 Where: 7.59/7.81 1) f3#(I0, I1, I2, I3, I4) -> f2#(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 2) f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 7.59/7.81 We have the following SCCs. 7.59/7.81 { 2 } 7.59/7.81 7.59/7.81 DP problem for innermost termination. 7.59/7.81 P = 7.59/7.81 f3#(I7, I8, I9, I10, I11) -> f3#(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 R = 7.59/7.81 init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 7.59/7.81 f3(I0, I1, I2, I3, I4) -> f2(I1 + 1, I2, I0, I5, I6) [0 = I4 /\ 0 = I3 /\ -1 <= I1 - 1] 7.59/7.81 f3(I7, I8, I9, I10, I11) -> f3(I7, I8, I9 - 1, I10 - 1, I10 - 1) [I10 = I11 /\ 0 <= I10 - 1] 7.59/7.81 f3(I12, I13, I14, I15, I16) -> f3(I12, I13, I14 + 1, I15 + 1, I15 + 1) [I15 = I16 /\ I15 <= 0 /\ 0 <= I15 - 1] 7.59/7.81 f3(I17, I18, I19, I20, I21) -> f3(I17, I18, I19 + 1, I20 + 1, I20 + 1) [I20 = I21 /\ I20 <= 0 /\ I20 <= -1] 7.59/7.81 f2(I22, I23, I24, I25, I26) -> f3(I24, I22, I23, I24, I24) [0 <= I24 - 1 /\ I24 <= I23] 7.59/7.81 f1(I27, I28, I29, I30, I31) -> f2(0, I32, I33, I34, I35) [0 <= I27 - 1 /\ -1 <= I32 - 1 /\ -1 <= I28 - 1 /\ -1 <= I33 - 1]
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