details

property	value
status	complete
benchmark	mc91test.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n132.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	37.3831 seconds
cpu usage	37.9386
user time	19.2857
system time	18.6529
max virtual memory	759912.0
max residence set size	15436.0

stage attributes

key	value
starexec-result	MAYBE

output

37.88/37.38 MAYBE 37.88/37.38 37.88/37.38 DP problem for innermost termination. 37.88/37.38 P = 37.88/37.38 f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 37.88/37.38 f7#(I0, I1, I2, I3, I4) -> f1#(0, 1, rnd3, I3, I4) [rnd3 = rnd3] 37.88/37.38 f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 37.88/37.38 f1#(I10, I11, I12, I13, I14) -> f6#(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 f5#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 37.88/37.38 f1#(I20, I21, I22, I23, I24) -> f5#(I20, 1 + I21, 11 + I22, I23, I24) [I22 <= 100 /\ 1 <= I21] 37.88/37.38 f4#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 37.88/37.38 f1#(I30, I31, I32, I33, I34) -> f4#(1, -1 + I31, -10 + I32, I31, I32) [101 <= I32 /\ 1 <= I31 /\ I30 <= 0] 37.88/37.38 f3#(I35, I36, I37, I38, I39) -> f1#(I35, I36, I37, I38, I39) 37.88/37.38 f1#(I40, I41, I42, I43, I44) -> f3#(1, 1 + I41, 11 + I42, I41, I42) [I42 <= 100 /\ 1 <= I41 /\ I40 <= 0] 37.88/37.38 R = 37.88/37.38 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 37.88/37.38 f7(I0, I1, I2, I3, I4) -> f1(0, 1, rnd3, I3, I4) [rnd3 = rnd3] 37.88/37.38 f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 37.88/37.38 f1(I10, I11, I12, I13, I14) -> f6(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 f5(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I18, I19) 37.88/37.38 f1(I20, I21, I22, I23, I24) -> f5(I20, 1 + I21, 11 + I22, I23, I24) [I22 <= 100 /\ 1 <= I21] 37.88/37.38 f4(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 37.88/37.38 f1(I30, I31, I32, I33, I34) -> f4(1, -1 + I31, -10 + I32, I31, I32) [101 <= I32 /\ 1 <= I31 /\ I30 <= 0] 37.88/37.38 f3(I35, I36, I37, I38, I39) -> f1(I35, I36, I37, I38, I39) 37.88/37.38 f1(I40, I41, I42, I43, I44) -> f3(1, 1 + I41, 11 + I42, I41, I42) [I42 <= 100 /\ 1 <= I41 /\ I40 <= 0] 37.88/37.38 f1(I45, I46, I47, I48, I49) -> f2(I45, I46, I47, I48, I49) [I47 <= I49 /\ I48 <= I46 /\ 1 <= I45] 37.88/37.38 37.88/37.38 The dependency graph for this problem is: 37.88/37.38 0 -> 1 37.88/37.38 1 -> 3, 5, 7, 9 37.88/37.38 2 -> 3, 5, 7, 9 37.88/37.38 3 -> 2 37.88/37.38 4 -> 3, 5, 7, 9 37.88/37.38 5 -> 4 37.88/37.38 6 -> 3, 5, 7, 9 37.88/37.38 7 -> 6 37.88/37.38 8 -> 3, 5, 7, 9 37.88/37.38 9 -> 8 37.88/37.38 Where: 37.88/37.38 0) f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 37.88/37.38 1) f7#(I0, I1, I2, I3, I4) -> f1#(0, 1, rnd3, I3, I4) [rnd3 = rnd3] 37.88/37.38 2) f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 37.88/37.38 3) f1#(I10, I11, I12, I13, I14) -> f6#(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 4) f5#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 37.88/37.38 5) f1#(I20, I21, I22, I23, I24) -> f5#(I20, 1 + I21, 11 + I22, I23, I24) [I22 <= 100 /\ 1 <= I21] 37.88/37.38 6) f4#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 37.88/37.38 7) f1#(I30, I31, I32, I33, I34) -> f4#(1, -1 + I31, -10 + I32, I31, I32) [101 <= I32 /\ 1 <= I31 /\ I30 <= 0] 37.88/37.38 8) f3#(I35, I36, I37, I38, I39) -> f1#(I35, I36, I37, I38, I39) 37.88/37.38 9) f1#(I40, I41, I42, I43, I44) -> f3#(1, 1 + I41, 11 + I42, I41, I42) [I42 <= 100 /\ 1 <= I41 /\ I40 <= 0] 37.88/37.38 37.88/37.38 We have the following SCCs. 37.88/37.38 { 2, 3, 4, 5, 6, 7, 8, 9 } 37.88/37.38 37.88/37.38 DP problem for innermost termination. 37.88/37.38 P = 37.88/37.38 f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 37.88/37.38 f1#(I10, I11, I12, I13, I14) -> f6#(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 f5#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 37.88/37.38 f1#(I20, I21, I22, I23, I24) -> f5#(I20, 1 + I21, 11 + I22, I23, I24) [I22 <= 100 /\ 1 <= I21] 37.88/37.38 f4#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 37.88/37.38 f1#(I30, I31, I32, I33, I34) -> f4#(1, -1 + I31, -10 + I32, I31, I32) [101 <= I32 /\ 1 <= I31 /\ I30 <= 0] 37.88/37.38 f3#(I35, I36, I37, I38, I39) -> f1#(I35, I36, I37, I38, I39) 37.88/37.38 f1#(I40, I41, I42, I43, I44) -> f3#(1, 1 + I41, 11 + I42, I41, I42) [I42 <= 100 /\ 1 <= I41 /\ I40 <= 0] 37.88/37.38 R = 37.88/37.38 f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 37.88/37.38 f7(I0, I1, I2, I3, I4) -> f1(0, 1, rnd3, I3, I4) [rnd3 = rnd3] 37.88/37.38 f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 37.88/37.38 f1(I10, I11, I12, I13, I14) -> f6(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 f5(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I18, I19) 37.88/37.38 f1(I20, I21, I22, I23, I24) -> f5(I20, 1 + I21, 11 + I22, I23, I24) [I22 <= 100 /\ 1 <= I21] 37.88/37.38 f4(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 37.88/37.38 f1(I30, I31, I32, I33, I34) -> f4(1, -1 + I31, -10 + I32, I31, I32) [101 <= I32 /\ 1 <= I31 /\ I30 <= 0] 37.88/37.38 f3(I35, I36, I37, I38, I39) -> f1(I35, I36, I37, I38, I39) 37.88/37.38 f1(I40, I41, I42, I43, I44) -> f3(1, 1 + I41, 11 + I42, I41, I42) [I42 <= 100 /\ 1 <= I41 /\ I40 <= 0] 37.88/37.38 f1(I45, I46, I47, I48, I49) -> f2(I45, I46, I47, I48, I49) [I47 <= I49 /\ I48 <= I46 /\ 1 <= I45] 37.88/37.38 37.88/37.38 We use the reverse value criterion with the projection function NU: 37.88/37.38 NU[f3#(z1,z2,z3,z4,z5)] = 0 + -1 * z1 37.88/37.38 NU[f4#(z1,z2,z3,z4,z5)] = 0 + -1 * z1 37.88/37.38 NU[f5#(z1,z2,z3,z4,z5)] = 0 + -1 * z1 37.88/37.38 NU[f1#(z1,z2,z3,z4,z5)] = 0 + -1 * z1 37.88/37.38 NU[f6#(z1,z2,z3,z4,z5)] = 0 + -1 * z1 37.88/37.38 37.88/37.38 This gives the following inequalities: 37.88/37.38 ==> 0 + -1 * I5 >= 0 + -1 * I5 37.88/37.38 101 <= I12 /\ 1 <= I11 ==> 0 + -1 * I10 >= 0 + -1 * I10 37.88/37.38 ==> 0 + -1 * I15 >= 0 + -1 * I15 37.88/37.38 I22 <= 100 /\ 1 <= I21 ==> 0 + -1 * I20 >= 0 + -1 * I20 37.88/37.38 ==> 0 + -1 * I25 >= 0 + -1 * I25 37.88/37.38 101 <= I32 /\ 1 <= I31 /\ I30 <= 0 ==> 0 + -1 * I30 > 0 + -1 * 1 with 0 + -1 * I30 >= 0 37.88/37.38 ==> 0 + -1 * I35 >= 0 + -1 * I35 37.88/37.38 I42 <= 100 /\ 1 <= I41 /\ I40 <= 0 ==> 0 + -1 * I40 > 0 + -1 * 1 with 0 + -1 * I40 >= 0 37.88/37.38 37.88/37.38 We remove all the strictly oriented dependency pairs. 37.88/37.38 37.88/37.38 DP problem for innermost termination. 37.88/37.38 P = 37.88/37.38 f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 37.88/37.38 f1#(I10, I11, I12, I13, I14) -> f6#(I10, -1 + I11, -10 + I12, I13, I14) [101 <= I12 /\ 1 <= I11] 37.88/37.38 f5#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer_Transition_Systems 2019-03-29 01.54