details

property	value
status	complete
benchmark	java_LeUserDefRec.c.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n181.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	10.2683 seconds
cpu usage	10.1344
user time	4.93493
system time	5.1995
max virtual memory	722644.0
max residence set size	10236.0

stage attributes

key	value
starexec-result	YES

output

10.08/10.26 YES 10.08/10.26 10.08/10.26 DP problem for innermost termination. 10.08/10.26 P = 10.08/10.26 f7#(x1, x2, x3, x4, x5, x6) -> f6#(x1, x2, x3, x4, x5, x6) 10.08/10.26 f6#(I0, I1, I2, I3, I4, I5) -> f3#(I0, I1, I2, I3, I4, I5) 10.08/10.26 f6#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, I8, I9, I10, I11) 10.08/10.26 f6#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) 10.08/10.26 f6#(I18, I19, I20, I21, I22, I23) -> f1#(I18, I19, I20, I21, I22, I23) 10.08/10.26 f3#(I30, I31, I32, I33, I34, I35) -> f5#(I34, I35, I32, I33, I34, I35) 10.08/10.26 f5#(I36, I37, I38, I39, I40, I41) -> f4#(I40, I41, I38, I39, I40, I41) [I40 <= 0] 10.08/10.26 f5#(I42, I43, I44, I45, I46, I47) -> f4#(I46, I47, I44, I45, I46, I47) [I47 <= 0] 10.08/10.26 f5#(I48, I49, I50, I51, I52, I53) -> f1#(I52, I53, I50, I51, I52, I53) [1 <= I53 /\ 1 <= I52] 10.08/10.26 f1#(I80, I81, I82, I83, I84, I85) -> f3#(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 R = 10.08/10.26 f7(x1, x2, x3, x4, x5, x6) -> f6(x1, x2, x3, x4, x5, x6) 10.08/10.26 f6(I0, I1, I2, I3, I4, I5) -> f3(I0, I1, I2, I3, I4, I5) 10.08/10.26 f6(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, I8, I9, I10, I11) 10.08/10.26 f6(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) 10.08/10.26 f6(I18, I19, I20, I21, I22, I23) -> f1(I18, I19, I20, I21, I22, I23) 10.08/10.26 f6(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, I26, I27, I28, I29) 10.08/10.26 f3(I30, I31, I32, I33, I34, I35) -> f5(I34, I35, I32, I33, I34, I35) 10.08/10.26 f5(I36, I37, I38, I39, I40, I41) -> f4(I40, I41, I38, I39, I40, I41) [I40 <= 0] 10.08/10.26 f5(I42, I43, I44, I45, I46, I47) -> f4(I46, I47, I44, I45, I46, I47) [I47 <= 0] 10.08/10.26 f5(I48, I49, I50, I51, I52, I53) -> f1(I52, I53, I50, I51, I52, I53) [1 <= I53 /\ 1 <= I52] 10.08/10.26 f4(I54, I55, I56, I57, I58, I59) -> f2(I58, I59, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ 1 + I58 <= 0 /\ rnd4 = rnd4 /\ rnd3 = rnd3] 10.08/10.26 f4(I60, I61, I62, I63, I64, I65) -> f2(I64, I65, I66, I67, I68, I69) [I69 = I67 /\ I68 = I66 /\ 1 <= I64 /\ I67 = I67 /\ I66 = I66] 10.08/10.26 f4(I70, I71, I72, I73, I74, I75) -> f2(I74, I75, I76, I77, I78, I79) [I79 = I77 /\ I78 = I76 /\ 0 <= I74 /\ I74 <= 0 /\ I77 = I77 /\ I76 = I76] 10.08/10.26 f1(I80, I81, I82, I83, I84, I85) -> f3(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 f1(I86, I87, I88, I89, I90, I91) -> f2(I90, I91, I92, I93, I94, I95) [I95 = I93 /\ I94 = I92 /\ I93 = I93 /\ I92 = I92] 10.08/10.26 10.08/10.26 The dependency graph for this problem is: 10.08/10.26 0 -> 1, 2, 3, 4 10.08/10.26 1 -> 5 10.08/10.26 2 -> 6, 7, 8 10.08/10.26 3 -> 10.08/10.26 4 -> 9 10.08/10.26 5 -> 6, 7, 8 10.08/10.26 6 -> 10.08/10.26 7 -> 10.08/10.26 8 -> 9 10.08/10.26 9 -> 5 10.08/10.26 Where: 10.08/10.26 0) f7#(x1, x2, x3, x4, x5, x6) -> f6#(x1, x2, x3, x4, x5, x6) 10.08/10.26 1) f6#(I0, I1, I2, I3, I4, I5) -> f3#(I0, I1, I2, I3, I4, I5) 10.08/10.26 2) f6#(I6, I7, I8, I9, I10, I11) -> f5#(I6, I7, I8, I9, I10, I11) 10.08/10.26 3) f6#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) 10.08/10.26 4) f6#(I18, I19, I20, I21, I22, I23) -> f1#(I18, I19, I20, I21, I22, I23) 10.08/10.26 5) f3#(I30, I31, I32, I33, I34, I35) -> f5#(I34, I35, I32, I33, I34, I35) 10.08/10.26 6) f5#(I36, I37, I38, I39, I40, I41) -> f4#(I40, I41, I38, I39, I40, I41) [I40 <= 0] 10.08/10.26 7) f5#(I42, I43, I44, I45, I46, I47) -> f4#(I46, I47, I44, I45, I46, I47) [I47 <= 0] 10.08/10.26 8) f5#(I48, I49, I50, I51, I52, I53) -> f1#(I52, I53, I50, I51, I52, I53) [1 <= I53 /\ 1 <= I52] 10.08/10.26 9) f1#(I80, I81, I82, I83, I84, I85) -> f3#(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 10.08/10.26 We have the following SCCs. 10.08/10.26 { 5, 8, 9 } 10.08/10.26 10.08/10.26 DP problem for innermost termination. 10.08/10.26 P = 10.08/10.26 f3#(I30, I31, I32, I33, I34, I35) -> f5#(I34, I35, I32, I33, I34, I35) 10.08/10.26 f5#(I48, I49, I50, I51, I52, I53) -> f1#(I52, I53, I50, I51, I52, I53) [1 <= I53 /\ 1 <= I52] 10.08/10.26 f1#(I80, I81, I82, I83, I84, I85) -> f3#(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 R = 10.08/10.26 f7(x1, x2, x3, x4, x5, x6) -> f6(x1, x2, x3, x4, x5, x6) 10.08/10.26 f6(I0, I1, I2, I3, I4, I5) -> f3(I0, I1, I2, I3, I4, I5) 10.08/10.26 f6(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, I8, I9, I10, I11) 10.08/10.26 f6(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) 10.08/10.26 f6(I18, I19, I20, I21, I22, I23) -> f1(I18, I19, I20, I21, I22, I23) 10.08/10.26 f6(I24, I25, I26, I27, I28, I29) -> f2(I24, I25, I26, I27, I28, I29) 10.08/10.26 f3(I30, I31, I32, I33, I34, I35) -> f5(I34, I35, I32, I33, I34, I35) 10.08/10.26 f5(I36, I37, I38, I39, I40, I41) -> f4(I40, I41, I38, I39, I40, I41) [I40 <= 0] 10.08/10.26 f5(I42, I43, I44, I45, I46, I47) -> f4(I46, I47, I44, I45, I46, I47) [I47 <= 0] 10.08/10.26 f5(I48, I49, I50, I51, I52, I53) -> f1(I52, I53, I50, I51, I52, I53) [1 <= I53 /\ 1 <= I52] 10.08/10.26 f4(I54, I55, I56, I57, I58, I59) -> f2(I58, I59, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ 1 + I58 <= 0 /\ rnd4 = rnd4 /\ rnd3 = rnd3] 10.08/10.26 f4(I60, I61, I62, I63, I64, I65) -> f2(I64, I65, I66, I67, I68, I69) [I69 = I67 /\ I68 = I66 /\ 1 <= I64 /\ I67 = I67 /\ I66 = I66] 10.08/10.26 f4(I70, I71, I72, I73, I74, I75) -> f2(I74, I75, I76, I77, I78, I79) [I79 = I77 /\ I78 = I76 /\ 0 <= I74 /\ I74 <= 0 /\ I77 = I77 /\ I76 = I76] 10.08/10.26 f1(I80, I81, I82, I83, I84, I85) -> f3(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 f1(I86, I87, I88, I89, I90, I91) -> f2(I90, I91, I92, I93, I94, I95) [I95 = I93 /\ I94 = I92 /\ I93 = I93 /\ I92 = I92] 10.08/10.26 10.08/10.26 We use the extended value criterion with the projection function NU: 10.08/10.26 NU[f1#(x0,x1,x2,x3,x4,x5)] = x5 10.08/10.26 NU[f5#(x0,x1,x2,x3,x4,x5)] = x5 + 1 10.08/10.26 NU[f3#(x0,x1,x2,x3,x4,x5)] = x5 + 1 10.08/10.26 10.08/10.26 This gives the following inequalities: 10.08/10.26 ==> I35 + 1 >= I35 + 1 10.08/10.26 1 <= I53 /\ 1 <= I52 ==> I53 + 1 > I53 with I53 + 1 >= 0 10.08/10.26 ==> I85 >= (-1 + I85) + 1 10.08/10.26 10.08/10.26 We remove all the strictly oriented dependency pairs. 10.08/10.26 10.08/10.26 DP problem for innermost termination. 10.08/10.26 P = 10.08/10.26 f3#(I30, I31, I32, I33, I34, I35) -> f5#(I34, I35, I32, I33, I34, I35) 10.08/10.26 f1#(I80, I81, I82, I83, I84, I85) -> f3#(I84, I85, I82, I83, -1 + I84, -1 + I85) 10.08/10.26 R = 10.08/10.26 f7(x1, x2, x3, x4, x5, x6) -> f6(x1, x2, x3, x4, x5, x6) 10.08/10.26 f6(I0, I1, I2, I3, I4, I5) -> f3(I0, I1, I2, I3, I4, I5) 10.08/10.26 f6(I6, I7, I8, I9, I10, I11) -> f5(I6, I7, I8, I9, I10, I11) 10.08/10.26 f6(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54