details

property	value
status	complete
benchmark	n-6a.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n165.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	14.5152 seconds
cpu usage	14.4957
user time	7.47822
system time	7.01748
max virtual memory	713216.0
max residence set size	10156.0

stage attributes

key	value
starexec-result	MAYBE

output

14.40/14.51 MAYBE 14.40/14.51 14.40/14.51 DP problem for innermost termination. 14.40/14.51 P = 14.40/14.51 f7#(x1, x2, x3, x4) -> f6#(x1, x2, x3, x4) 14.40/14.51 f6#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) 14.40/14.51 f5#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 14.40/14.51 f4#(I8, I9, I10, I11) -> f5#(I8, I9, I10, I11) [1 <= I9] 14.40/14.51 f4#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) [1 + I13 <= 0] 14.40/14.51 f1#(I16, I17, I18, I19) -> f4#(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.40/14.51 f3#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) 14.40/14.51 f1#(I24, I25, I26, I27) -> f3#(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.40/14.51 R = 14.40/14.51 f7(x1, x2, x3, x4) -> f6(x1, x2, x3, x4) 14.40/14.51 f6(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) 14.40/14.51 f5(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) 14.40/14.51 f4(I8, I9, I10, I11) -> f5(I8, I9, I10, I11) [1 <= I9] 14.40/14.51 f4(I12, I13, I14, I15) -> f5(I12, I13, I14, I15) [1 + I13 <= 0] 14.40/14.51 f1(I16, I17, I18, I19) -> f4(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.40/14.51 f3(I20, I21, I22, I23) -> f1(I20, I21, I22, I23) 14.40/14.51 f1(I24, I25, I26, I27) -> f3(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.48/14.51 f1(I29, I30, I31, I32) -> f2(rnd1, I30, I31, I32) [rnd1 = rnd1 /\ -1 * I31 + I32 <= 0] 14.48/14.51 14.48/14.51 The dependency graph for this problem is: 14.48/14.51 0 -> 1 14.48/14.51 1 -> 5, 7 14.48/14.51 2 -> 5, 7 14.48/14.51 3 -> 2 14.48/14.51 4 -> 2 14.48/14.51 5 -> 3, 4 14.48/14.51 6 -> 5, 7 14.48/14.51 7 -> 6 14.48/14.51 Where: 14.48/14.51 0) f7#(x1, x2, x3, x4) -> f6#(x1, x2, x3, x4) 14.48/14.51 1) f6#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) 14.48/14.51 2) f5#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 14.48/14.51 3) f4#(I8, I9, I10, I11) -> f5#(I8, I9, I10, I11) [1 <= I9] 14.48/14.51 4) f4#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) [1 + I13 <= 0] 14.48/14.51 5) f1#(I16, I17, I18, I19) -> f4#(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.48/14.51 6) f3#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) 14.48/14.51 7) f1#(I24, I25, I26, I27) -> f3#(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.48/14.51 14.48/14.51 We have the following SCCs. 14.48/14.51 { 2, 3, 4, 5, 6, 7 } 14.48/14.51 14.48/14.51 DP problem for innermost termination. 14.48/14.51 P = 14.48/14.51 f5#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 14.48/14.51 f4#(I8, I9, I10, I11) -> f5#(I8, I9, I10, I11) [1 <= I9] 14.48/14.51 f4#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) [1 + I13 <= 0] 14.48/14.51 f1#(I16, I17, I18, I19) -> f4#(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.48/14.51 f3#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) 14.48/14.51 f1#(I24, I25, I26, I27) -> f3#(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.48/14.51 R = 14.48/14.51 f7(x1, x2, x3, x4) -> f6(x1, x2, x3, x4) 14.48/14.51 f6(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) 14.48/14.51 f5(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) 14.48/14.51 f4(I8, I9, I10, I11) -> f5(I8, I9, I10, I11) [1 <= I9] 14.48/14.51 f4(I12, I13, I14, I15) -> f5(I12, I13, I14, I15) [1 + I13 <= 0] 14.48/14.51 f1(I16, I17, I18, I19) -> f4(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.48/14.51 f3(I20, I21, I22, I23) -> f1(I20, I21, I22, I23) 14.48/14.51 f1(I24, I25, I26, I27) -> f3(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.48/14.51 f1(I29, I30, I31, I32) -> f2(rnd1, I30, I31, I32) [rnd1 = rnd1 /\ -1 * I31 + I32 <= 0] 14.48/14.51 14.48/14.51 We use the extended value criterion with the projection function NU: 14.48/14.51 NU[f3#(x0,x1,x2,x3)] = -x2 + x3 - 1 14.48/14.51 NU[f4#(x0,x1,x2,x3)] = -x2 + x3 - 1 14.48/14.51 NU[f1#(x0,x1,x2,x3)] = -x2 + x3 - 1 14.48/14.51 NU[f5#(x0,x1,x2,x3)] = -x2 + x3 - 1 14.48/14.51 14.48/14.51 This gives the following inequalities: 14.48/14.51 ==> -I6 + I7 - 1 >= -I6 + I7 - 1 14.48/14.51 1 <= I9 ==> -I10 + I11 - 1 >= -I10 + I11 - 1 14.48/14.51 1 + I13 <= 0 ==> -I14 + I15 - 1 >= -I14 + I15 - 1 14.48/14.51 rnd2 = rnd2 /\ 0 <= -1 - I18 + I19 ==> -I18 + I19 - 1 >= -I18 + I19 - 1 14.48/14.51 ==> -I22 + I23 - 1 >= -I22 + I23 - 1 14.48/14.51 0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27 ==> -I26 + I27 - 1 > -I26 + (-1 + I27) - 1 with -I26 + I27 - 1 >= 0 14.48/14.51 14.48/14.51 We remove all the strictly oriented dependency pairs. 14.48/14.51 14.48/14.51 DP problem for innermost termination. 14.48/14.51 P = 14.48/14.51 f5#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 14.48/14.51 f4#(I8, I9, I10, I11) -> f5#(I8, I9, I10, I11) [1 <= I9] 14.48/14.51 f4#(I12, I13, I14, I15) -> f5#(I12, I13, I14, I15) [1 + I13 <= 0] 14.48/14.51 f1#(I16, I17, I18, I19) -> f4#(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.48/14.51 f3#(I20, I21, I22, I23) -> f1#(I20, I21, I22, I23) 14.48/14.51 R = 14.48/14.51 f7(x1, x2, x3, x4) -> f6(x1, x2, x3, x4) 14.48/14.51 f6(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) 14.48/14.51 f5(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) 14.48/14.51 f4(I8, I9, I10, I11) -> f5(I8, I9, I10, I11) [1 <= I9] 14.48/14.51 f4(I12, I13, I14, I15) -> f5(I12, I13, I14, I15) [1 + I13 <= 0] 14.48/14.51 f1(I16, I17, I18, I19) -> f4(I16, rnd2, I18, I19) [rnd2 = rnd2 /\ 0 <= -1 - I18 + I19] 14.48/14.51 f3(I20, I21, I22, I23) -> f1(I20, I21, I22, I23) 14.48/14.51 f1(I24, I25, I26, I27) -> f3(I24, I28, I26, -1 + I27) [0 <= I28 /\ I28 <= 0 /\ I28 = I28 /\ 0 <= -1 - I26 + I27] 14.48/14.51 f1(I29, I30, I31, I32) -> f2(rnd1, I30, I31, I32) [rnd1 = rnd1 /\ -1 * I31 + I32 <= 0] 14.48/14.51 14.48/14.51 The dependency graph for this problem is: 14.48/14.51 2 -> 5 popout

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job log

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54