Integer_Transition_Systems 2019-03-29 01.54 pair #432274662

details

property	value
status	complete
benchmark	n-15a.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n091.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	3.24385 seconds
cpu usage	3.29638
user time	1.72765
system time	1.56872
max virtual memory	727108.0
max residence set size	8648.0

stage attributes

key	value
starexec-result	MAYBE

output

3.17/3.24	MAYBE
3.17/3.24	
3.17/3.24	DP problem for innermost termination.
3.17/3.24	P =
3.17/3.24	  f10#(x1, x2) -> f1#(x1, x2) 
3.17/3.24	  f9#(I2, I3) -> f2#(I2, I3) 
3.17/3.24	  f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
3.17/3.24	  f6#(I11, I12) -> f7#(I11, I12) [14 <= I12]
3.17/3.24	  f6#(I13, I14) -> f7#(I13, I14) [1 + I14 <= 13]
3.17/3.24	  f2#(I15, I16) -> f6#(I15, -1 + I16) 
3.17/3.24	  f5#(I17, I18) -> f2#(I17, I18) 
3.17/3.24	  f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
3.17/3.24	  f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
3.17/3.24	  f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
3.17/3.24	  f2#(I25, I26) -> f3#(I25, -1 + I26) 
3.17/3.24	  f1#(I27, I28) -> f2#(I27, I28) 
3.17/3.24	R = 
3.17/3.24	  f10(x1, x2) -> f1(x1, x2) 
3.17/3.24	  f2(I0, I1) -> f8(rnd1, rnd2) [y1 = -1 + I1 /\ y1 <= 13 /\ 13 <= y1 /\ rnd2 = rnd2 /\ 0 <= -1 - rnd2 /\ rnd1 = rnd1]
3.17/3.24	  f9(I2, I3) -> f2(I2, I3) 
3.17/3.24	  f2(I4, I5) -> f9(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
3.17/3.24	  f7(I8, I9) -> f8(I10, I9) [I10 = I10 /\ 0 <= -1 - I9]
3.17/3.24	  f6(I11, I12) -> f7(I11, I12) [14 <= I12]
3.17/3.24	  f6(I13, I14) -> f7(I13, I14) [1 + I14 <= 13]
3.17/3.24	  f2(I15, I16) -> f6(I15, -1 + I16) 
3.17/3.24	  f5(I17, I18) -> f2(I17, I18) 
3.17/3.24	  f4(I19, I20) -> f5(I19, I20) [-1 * I20 <= 0]
3.17/3.24	  f3(I21, I22) -> f4(I21, I22) [14 <= I22]
3.17/3.24	  f3(I23, I24) -> f4(I23, I24) [1 + I24 <= 13]
3.17/3.24	  f2(I25, I26) -> f3(I25, -1 + I26) 
3.17/3.24	  f1(I27, I28) -> f2(I27, I28) 
3.17/3.24	
3.17/3.24	The dependency graph for this problem is:
3.17/3.24	  0 -> 11
3.17/3.24	  1 -> 2, 5, 10
3.17/3.24	  2 -> 1
3.17/3.24	  3 -> 
3.17/3.24	  4 -> 
3.17/3.24	  5 -> 3, 4
3.17/3.24	  6 -> 2, 5, 10
3.17/3.24	  7 -> 6
3.17/3.24	  8 -> 7
3.17/3.24	  9 -> 7
3.17/3.24	  10 -> 8, 9
3.17/3.24	  11 -> 2, 5, 10
3.17/3.24	Where:
3.17/3.24	  0) f10#(x1, x2) -> f1#(x1, x2) 
3.17/3.24	  1) f9#(I2, I3) -> f2#(I2, I3) 
3.17/3.24	  2) f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
3.17/3.24	  3) f6#(I11, I12) -> f7#(I11, I12) [14 <= I12]
3.17/3.24	  4) f6#(I13, I14) -> f7#(I13, I14) [1 + I14 <= 13]
3.17/3.24	  5) f2#(I15, I16) -> f6#(I15, -1 + I16) 
3.17/3.24	  6) f5#(I17, I18) -> f2#(I17, I18) 
3.17/3.24	  7) f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
3.17/3.24	  8) f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
3.17/3.24	  9) f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
3.17/3.24	  10) f2#(I25, I26) -> f3#(I25, -1 + I26) 
3.17/3.24	  11) f1#(I27, I28) -> f2#(I27, I28) 
3.17/3.24	
3.17/3.24	We have the following SCCs.
3.17/3.24	  { 1, 2, 6, 7, 8, 9, 10 }
3.17/3.24	
3.17/3.24	DP problem for innermost termination.
3.17/3.24	P =
3.17/3.24	  f9#(I2, I3) -> f2#(I2, I3) 
3.17/3.24	  f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
3.17/3.24	  f5#(I17, I18) -> f2#(I17, I18) 
3.17/3.24	  f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
3.17/3.24	  f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
3.17/3.24	  f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
3.17/3.24	  f2#(I25, I26) -> f3#(I25, -1 + I26) 
3.17/3.24	R = 
3.17/3.24	  f10(x1, x2) -> f1(x1, x2) 
3.17/3.24	  f2(I0, I1) -> f8(rnd1, rnd2) [y1 = -1 + I1 /\ y1 <= 13 /\ 13 <= y1 /\ rnd2 = rnd2 /\ 0 <= -1 - rnd2 /\ rnd1 = rnd1]
3.17/3.24	  f9(I2, I3) -> f2(I2, I3) 
3.17/3.24	  f2(I4, I5) -> f9(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
3.17/3.24	  f7(I8, I9) -> f8(I10, I9) [I10 = I10 /\ 0 <= -1 - I9]
3.17/3.24	  f6(I11, I12) -> f7(I11, I12) [14 <= I12]
3.17/3.24	  f6(I13, I14) -> f7(I13, I14) [1 + I14 <= 13]
3.17/3.24	  f2(I15, I16) -> f6(I15, -1 + I16) 
3.17/3.24	  f5(I17, I18) -> f2(I17, I18) 
3.17/3.24	  f4(I19, I20) -> f5(I19, I20) [-1 * I20 <= 0]
3.17/3.24	  f3(I21, I22) -> f4(I21, I22) [14 <= I22]
3.17/3.24	  f3(I23, I24) -> f4(I23, I24) [1 + I24 <= 13]
3.17/3.24	  f2(I25, I26) -> f3(I25, -1 + I26) 
3.17/3.24	  f1(I27, I28) -> f2(I27, I28) 
3.17/3.24	
3.17/6.21	EOF

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