details

property	value
status	complete
benchmark	mc91test.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n167.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	83.5393 seconds
cpu usage	84.7617
user time	43.6407
system time	41.121
max virtual memory	760272.0
max residence set size	24228.0

stage attributes

key	value
starexec-result	MAYBE

output

84.70/83.53 MAYBE 84.70/83.53 84.70/83.53 DP problem for innermost termination. 84.70/83.53 P = 84.70/83.53 f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f7#(x1, x2, x3, x4, x5, x6, x7, x8) 84.70/83.53 f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f1#(I0, I1, I2, 0, 1, rnd6, I6, I7) [rnd6 = rnd6] 84.70/83.53 f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f1#(I24, I25, I26, I27, I28, I29, I30, I31) 84.70/83.53 f1#(I32, I33, I34, I35, I36, I37, I38, I39) -> f5#(I32, I33, I34, I35, 1 + I36, I34 + I37, I38, I39) [I37 <= I32 /\ 1 <= I36] 84.70/83.53 f4#(I40, I41, I42, I43, I44, I45, I46, I47) -> f1#(I40, I41, I42, I43, I44, I45, I46, I47) 84.70/83.53 f1#(I48, I49, I50, I51, I52, I53, I54, I55) -> f4#(I48, I49, I50, 1, -1 + I52, -1 * I49 + I53, I52, I53) [1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0] 84.70/83.53 f3#(I56, I57, I58, I59, I60, I61, I62, I63) -> f1#(I56, I57, I58, I59, I60, I61, I62, I63) 84.70/83.53 f1#(I64, I65, I66, I67, I68, I69, I70, I71) -> f3#(I64, I65, I66, 1, 1 + I68, I66 + I69, I68, I69) [I69 <= I64 /\ 1 <= I68 /\ I67 <= 0] 84.70/83.53 R = 84.70/83.53 f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f7(x1, x2, x3, x4, x5, x6, x7, x8) 84.70/83.53 f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f1(I0, I1, I2, 0, 1, rnd6, I6, I7) [rnd6 = rnd6] 84.70/83.53 f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f1(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 f1(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 f5(I24, I25, I26, I27, I28, I29, I30, I31) -> f1(I24, I25, I26, I27, I28, I29, I30, I31) 84.70/83.53 f1(I32, I33, I34, I35, I36, I37, I38, I39) -> f5(I32, I33, I34, I35, 1 + I36, I34 + I37, I38, I39) [I37 <= I32 /\ 1 <= I36] 84.70/83.53 f4(I40, I41, I42, I43, I44, I45, I46, I47) -> f1(I40, I41, I42, I43, I44, I45, I46, I47) 84.70/83.53 f1(I48, I49, I50, I51, I52, I53, I54, I55) -> f4(I48, I49, I50, 1, -1 + I52, -1 * I49 + I53, I52, I53) [1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0] 84.70/83.53 f3(I56, I57, I58, I59, I60, I61, I62, I63) -> f1(I56, I57, I58, I59, I60, I61, I62, I63) 84.70/83.53 f1(I64, I65, I66, I67, I68, I69, I70, I71) -> f3(I64, I65, I66, 1, 1 + I68, I66 + I69, I68, I69) [I69 <= I64 /\ 1 <= I68 /\ I67 <= 0] 84.70/83.53 f1(I72, I73, I74, I75, I76, I77, I78, I79) -> f2(I72, I73, I74, I75, I76, I77, I78, I79) [I77 <= I79 /\ I78 <= I76 /\ 1 <= I75] 84.70/83.53 84.70/83.53 The dependency graph for this problem is: 84.70/83.53 0 -> 1 84.70/83.53 1 -> 3, 5, 7, 9 84.70/83.53 2 -> 3, 5, 7, 9 84.70/83.53 3 -> 2 84.70/83.53 4 -> 3, 5, 7, 9 84.70/83.53 5 -> 4 84.70/83.53 6 -> 3, 5, 7, 9 84.70/83.53 7 -> 6 84.70/83.53 8 -> 3, 5, 7, 9 84.70/83.53 9 -> 8 84.70/83.53 Where: 84.70/83.53 0) f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f7#(x1, x2, x3, x4, x5, x6, x7, x8) 84.70/83.53 1) f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f1#(I0, I1, I2, 0, 1, rnd6, I6, I7) [rnd6 = rnd6] 84.70/83.53 2) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 3) f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 4) f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f1#(I24, I25, I26, I27, I28, I29, I30, I31) 84.70/83.53 5) f1#(I32, I33, I34, I35, I36, I37, I38, I39) -> f5#(I32, I33, I34, I35, 1 + I36, I34 + I37, I38, I39) [I37 <= I32 /\ 1 <= I36] 84.70/83.53 6) f4#(I40, I41, I42, I43, I44, I45, I46, I47) -> f1#(I40, I41, I42, I43, I44, I45, I46, I47) 84.70/83.53 7) f1#(I48, I49, I50, I51, I52, I53, I54, I55) -> f4#(I48, I49, I50, 1, -1 + I52, -1 * I49 + I53, I52, I53) [1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0] 84.70/83.53 8) f3#(I56, I57, I58, I59, I60, I61, I62, I63) -> f1#(I56, I57, I58, I59, I60, I61, I62, I63) 84.70/83.53 9) f1#(I64, I65, I66, I67, I68, I69, I70, I71) -> f3#(I64, I65, I66, 1, 1 + I68, I66 + I69, I68, I69) [I69 <= I64 /\ 1 <= I68 /\ I67 <= 0] 84.70/83.53 84.70/83.53 We have the following SCCs. 84.70/83.53 { 2, 3, 4, 5, 6, 7, 8, 9 } 84.70/83.53 84.70/83.53 DP problem for innermost termination. 84.70/83.53 P = 84.70/83.53 f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f1#(I24, I25, I26, I27, I28, I29, I30, I31) 84.70/83.53 f1#(I32, I33, I34, I35, I36, I37, I38, I39) -> f5#(I32, I33, I34, I35, 1 + I36, I34 + I37, I38, I39) [I37 <= I32 /\ 1 <= I36] 84.70/83.53 f4#(I40, I41, I42, I43, I44, I45, I46, I47) -> f1#(I40, I41, I42, I43, I44, I45, I46, I47) 84.70/83.53 f1#(I48, I49, I50, I51, I52, I53, I54, I55) -> f4#(I48, I49, I50, 1, -1 + I52, -1 * I49 + I53, I52, I53) [1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0] 84.70/83.53 f3#(I56, I57, I58, I59, I60, I61, I62, I63) -> f1#(I56, I57, I58, I59, I60, I61, I62, I63) 84.70/83.53 f1#(I64, I65, I66, I67, I68, I69, I70, I71) -> f3#(I64, I65, I66, 1, 1 + I68, I66 + I69, I68, I69) [I69 <= I64 /\ 1 <= I68 /\ I67 <= 0] 84.70/83.53 R = 84.70/83.53 f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f7(x1, x2, x3, x4, x5, x6, x7, x8) 84.70/83.53 f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f1(I0, I1, I2, 0, 1, rnd6, I6, I7) [rnd6 = rnd6] 84.70/83.53 f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f1(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 f1(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 f5(I24, I25, I26, I27, I28, I29, I30, I31) -> f1(I24, I25, I26, I27, I28, I29, I30, I31) 84.70/83.53 f1(I32, I33, I34, I35, I36, I37, I38, I39) -> f5(I32, I33, I34, I35, 1 + I36, I34 + I37, I38, I39) [I37 <= I32 /\ 1 <= I36] 84.70/83.53 f4(I40, I41, I42, I43, I44, I45, I46, I47) -> f1(I40, I41, I42, I43, I44, I45, I46, I47) 84.70/83.53 f1(I48, I49, I50, I51, I52, I53, I54, I55) -> f4(I48, I49, I50, 1, -1 + I52, -1 * I49 + I53, I52, I53) [1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0] 84.70/83.53 f3(I56, I57, I58, I59, I60, I61, I62, I63) -> f1(I56, I57, I58, I59, I60, I61, I62, I63) 84.70/83.53 f1(I64, I65, I66, I67, I68, I69, I70, I71) -> f3(I64, I65, I66, 1, 1 + I68, I66 + I69, I68, I69) [I69 <= I64 /\ 1 <= I68 /\ I67 <= 0] 84.70/83.53 f1(I72, I73, I74, I75, I76, I77, I78, I79) -> f2(I72, I73, I74, I75, I76, I77, I78, I79) [I77 <= I79 /\ I78 <= I76 /\ 1 <= I75] 84.70/83.53 84.70/83.53 We use the reverse value criterion with the projection function NU: 84.70/83.53 NU[f3#(z1,z2,z3,z4,z5,z6,z7,z8)] = 0 + -1 * z4 84.70/83.53 NU[f4#(z1,z2,z3,z4,z5,z6,z7,z8)] = 0 + -1 * z4 84.70/83.53 NU[f5#(z1,z2,z3,z4,z5,z6,z7,z8)] = 0 + -1 * z4 84.70/83.53 NU[f1#(z1,z2,z3,z4,z5,z6,z7,z8)] = 0 + -1 * z4 84.70/83.53 NU[f6#(z1,z2,z3,z4,z5,z6,z7,z8)] = 0 + -1 * z4 84.70/83.53 84.70/83.53 This gives the following inequalities: 84.70/83.53 ==> 0 + -1 * I11 >= 0 + -1 * I11 84.70/83.53 1 + I16 <= I21 /\ 1 <= I20 ==> 0 + -1 * I19 >= 0 + -1 * I19 84.70/83.53 ==> 0 + -1 * I27 >= 0 + -1 * I27 84.70/83.53 I37 <= I32 /\ 1 <= I36 ==> 0 + -1 * I35 >= 0 + -1 * I35 84.70/83.53 ==> 0 + -1 * I43 >= 0 + -1 * I43 84.70/83.53 1 + I48 <= I53 /\ 1 <= I52 /\ I51 <= 0 ==> 0 + -1 * I51 > 0 + -1 * 1 with 0 + -1 * I51 >= 0 84.70/83.53 ==> 0 + -1 * I59 >= 0 + -1 * I59 84.70/83.53 I69 <= I64 /\ 1 <= I68 /\ I67 <= 0 ==> 0 + -1 * I67 > 0 + -1 * 1 with 0 + -1 * I67 >= 0 84.70/83.53 84.70/83.53 We remove all the strictly oriented dependency pairs. 84.70/83.53 84.70/83.53 DP problem for innermost termination. 84.70/83.53 P = 84.70/83.53 f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f1#(I8, I9, I10, I11, I12, I13, I14, I15) 84.70/83.53 f1#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, -1 + I20, -1 * I17 + I21, I22, I23) [1 + I16 <= I21 /\ 1 <= I20] 84.70/83.53 f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f1#(I24, I25, I26, I27, I28, I29, I30, I31) popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer_Transition_Systems 2019-03-29 01.54