details

property	value
status	complete
benchmark	nested.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n004.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	29.0313 seconds
cpu usage	29.1968
user time	15.5209
system time	13.676
max virtual memory	739520.0
max residence set size	16440.0

stage attributes

key	value
starexec-result	YES

output

29.09/29.02 YES 29.09/29.02 29.09/29.02 DP problem for innermost termination. 29.09/29.02 P = 29.09/29.02 f7#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 29.09/29.02 f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.02 f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.02 f3#(I16, I17, I18, I19, I20, I21, I22, I23) -> f2#(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.02 f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f3#(I24, I25, -1 + I26, rnd4, I28, -1 + I29, rnd7, I31) [1 <= rnd7 /\ 1 <= rnd4 /\ -1 + rnd7 <= -1 + I29 /\ -1 + I29 <= -1 + rnd7 /\ -1 + rnd4 <= -1 + I26 /\ -1 + I26 <= -1 + rnd4 /\ 1 <= I29 /\ rnd7 = rnd7 /\ rnd4 = rnd4] 29.09/29.02 f2#(I40, I41, I42, I43, I44, I45, I46, I47) -> f3#(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.02 f1#(I48, I49, I50, I51, I52, I53, I54, I55) -> f2#(I48, I49, rnd3, I51, I52, I56, I54, I55) [I56 = I56 /\ rnd3 = rnd3] 29.09/29.02 R = 29.09/29.02 f7(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 29.09/29.02 f6(I0, I1, I2, I3, I4, I5, I6, I7) -> f3(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.02 f3(I8, I9, I10, I11, I12, I13, I14, I15) -> f6(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.02 f3(I16, I17, I18, I19, I20, I21, I22, I23) -> f2(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.02 f5(I24, I25, I26, I27, I28, I29, I30, I31) -> f3(I24, I25, -1 + I26, rnd4, I28, -1 + I29, rnd7, I31) [1 <= rnd7 /\ 1 <= rnd4 /\ -1 + rnd7 <= -1 + I29 /\ -1 + I29 <= -1 + rnd7 /\ -1 + rnd4 <= -1 + I26 /\ -1 + I26 <= -1 + rnd4 /\ 1 <= I29 /\ rnd7 = rnd7 /\ rnd4 = rnd4] 29.09/29.02 f2(I32, I33, I34, I35, I36, I37, I38, I39) -> f4(I33, I33, I34, I35, I36, I37, I38, I39) [I34 <= 0] 29.09/29.02 f2(I40, I41, I42, I43, I44, I45, I46, I47) -> f3(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.02 f1(I48, I49, I50, I51, I52, I53, I54, I55) -> f2(I48, I49, rnd3, I51, I52, I56, I54, I55) [I56 = I56 /\ rnd3 = rnd3] 29.09/29.02 29.09/29.02 The dependency graph for this problem is: 29.09/29.02 0 -> 6 29.09/29.02 1 -> 2, 3 29.09/29.02 2 -> 1 29.09/29.02 3 -> 5 29.09/29.02 4 -> 2, 3 29.09/29.02 5 -> 2 29.09/29.02 6 -> 5 29.09/29.02 Where: 29.09/29.02 0) f7#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 29.09/29.02 1) f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.02 2) f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.02 3) f3#(I16, I17, I18, I19, I20, I21, I22, I23) -> f2#(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.02 4) f5#(I24, I25, I26, I27, I28, I29, I30, I31) -> f3#(I24, I25, -1 + I26, rnd4, I28, -1 + I29, rnd7, I31) [1 <= rnd7 /\ 1 <= rnd4 /\ -1 + rnd7 <= -1 + I29 /\ -1 + I29 <= -1 + rnd7 /\ -1 + rnd4 <= -1 + I26 /\ -1 + I26 <= -1 + rnd4 /\ 1 <= I29 /\ rnd7 = rnd7 /\ rnd4 = rnd4] 29.09/29.03 5) f2#(I40, I41, I42, I43, I44, I45, I46, I47) -> f3#(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.03 6) f1#(I48, I49, I50, I51, I52, I53, I54, I55) -> f2#(I48, I49, rnd3, I51, I52, I56, I54, I55) [I56 = I56 /\ rnd3 = rnd3] 29.09/29.03 29.09/29.03 We have the following SCCs. 29.09/29.03 { 1, 2, 3, 5 } 29.09/29.03 29.09/29.03 DP problem for innermost termination. 29.09/29.03 P = 29.09/29.03 f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.03 f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.03 f3#(I16, I17, I18, I19, I20, I21, I22, I23) -> f2#(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.03 f2#(I40, I41, I42, I43, I44, I45, I46, I47) -> f3#(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.03 R = 29.09/29.03 f7(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 29.09/29.03 f6(I0, I1, I2, I3, I4, I5, I6, I7) -> f3(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.03 f3(I8, I9, I10, I11, I12, I13, I14, I15) -> f6(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.03 f3(I16, I17, I18, I19, I20, I21, I22, I23) -> f2(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.03 f5(I24, I25, I26, I27, I28, I29, I30, I31) -> f3(I24, I25, -1 + I26, rnd4, I28, -1 + I29, rnd7, I31) [1 <= rnd7 /\ 1 <= rnd4 /\ -1 + rnd7 <= -1 + I29 /\ -1 + I29 <= -1 + rnd7 /\ -1 + rnd4 <= -1 + I26 /\ -1 + I26 <= -1 + rnd4 /\ 1 <= I29 /\ rnd7 = rnd7 /\ rnd4 = rnd4] 29.09/29.03 f2(I32, I33, I34, I35, I36, I37, I38, I39) -> f4(I33, I33, I34, I35, I36, I37, I38, I39) [I34 <= 0] 29.09/29.03 f2(I40, I41, I42, I43, I44, I45, I46, I47) -> f3(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.03 f1(I48, I49, I50, I51, I52, I53, I54, I55) -> f2(I48, I49, rnd3, I51, I52, I56, I54, I55) [I56 = I56 /\ rnd3 = rnd3] 29.09/29.03 29.09/29.03 We use the extended value criterion with the projection function NU: 29.09/29.03 NU[f2#(x0,x1,x2,x3,x4,x5,x6,x7)] = x2 - 1 29.09/29.03 NU[f3#(x0,x1,x2,x3,x4,x5,x6,x7)] = x2 - x5 - 1 29.09/29.03 NU[f6#(x0,x1,x2,x3,x4,x5,x6,x7)] = x2 - x5 - 1 29.09/29.03 29.09/29.03 This gives the following inequalities: 29.09/29.03 ==> I2 - I5 - 1 >= I2 - I5 - 1 29.09/29.03 1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5 ==> I10 - I13 - 1 >= (-1 + I10) - (-1 + I13) - 1 29.09/29.03 I21 <= 0 /\ I21 <= 0 ==> I18 - I21 - 1 >= I18 - 1 29.09/29.03 1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42 ==> I42 - 1 > I42 - rnd6 - 1 with I42 - 1 >= 0 29.09/29.03 29.09/29.03 We remove all the strictly oriented dependency pairs. 29.09/29.03 29.09/29.03 DP problem for innermost termination. 29.09/29.03 P = 29.09/29.03 f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.03 f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.03 f3#(I16, I17, I18, I19, I20, I21, I22, I23) -> f2#(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.03 R = 29.09/29.03 f7(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 29.09/29.03 f6(I0, I1, I2, I3, I4, I5, I6, I7) -> f3(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.03 f3(I8, I9, I10, I11, I12, I13, I14, I15) -> f6(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.03 f3(I16, I17, I18, I19, I20, I21, I22, I23) -> f2(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.03 f5(I24, I25, I26, I27, I28, I29, I30, I31) -> f3(I24, I25, -1 + I26, rnd4, I28, -1 + I29, rnd7, I31) [1 <= rnd7 /\ 1 <= rnd4 /\ -1 + rnd7 <= -1 + I29 /\ -1 + I29 <= -1 + rnd7 /\ -1 + rnd4 <= -1 + I26 /\ -1 + I26 <= -1 + rnd4 /\ 1 <= I29 /\ rnd7 = rnd7 /\ rnd4 = rnd4] 29.09/29.03 f2(I32, I33, I34, I35, I36, I37, I38, I39) -> f4(I33, I33, I34, I35, I36, I37, I38, I39) [I34 <= 0] 29.09/29.03 f2(I40, I41, I42, I43, I44, I45, I46, I47) -> f3(I40, I41, I42, I43, I44, rnd6, I46, I47) [1 <= I42 /\ 1 <= rnd6 /\ rnd6 = rnd6 /\ 1 <= I42] 29.09/29.03 f1(I48, I49, I50, I51, I52, I53, I54, I55) -> f2(I48, I49, rnd3, I51, I52, I56, I54, I55) [I56 = I56 /\ rnd3 = rnd3] 29.09/29.03 29.09/29.03 The dependency graph for this problem is: 29.09/29.03 1 -> 2, 3 29.09/29.03 2 -> 1 29.09/29.03 3 -> 29.09/29.03 Where: 29.09/29.03 1) f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) 29.09/29.03 2) f3#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, -1 + I10, I11, rnd5, -1 + I13, I14, rnd8) [1 <= rnd8 /\ -1 + rnd8 <= -1 + I13 /\ -1 + I13 <= -1 + rnd8 /\ -1 + rnd5 <= -1 + I10 /\ -1 + I10 <= -1 + rnd5 /\ 1 <= I13 /\ rnd8 = rnd8 /\ rnd5 = rnd5] 29.09/29.03 3) f3#(I16, I17, I18, I19, I20, I21, I22, I23) -> f2#(I16, I17, I18, I19, I20, I21, I22, I23) [I21 <= 0 /\ I21 <= 0] 29.09/29.03 29.09/29.03 We have the following SCCs. 29.09/29.03 { 1, 2 } 29.09/29.03 29.09/29.03 DP problem for innermost termination. 29.09/29.03 P = 29.09/29.03 f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f3#(I0, I1, I2, I3, I4, I5, I6, I7) popout

output may be truncated. 'popout' for the full output.

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all output return to Integer_Transition_Systems 2019-03-29 01.54