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Integer_Transition_Systems 2019-03-29 01.54 pair #432275055
details
property
value
status
complete
benchmark
p-1a.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n168.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
15.2196 seconds
cpu usage
15.4289
user time
8.15722
system time
7.27166
max virtual memory
729512.0
max residence set size
10576.0
stage attributes
key
value
starexec-result
MAYBE
output
15.37/15.21 MAYBE 15.37/15.21 15.37/15.21 DP problem for innermost termination. 15.37/15.21 P = 15.37/15.21 f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 15.37/15.21 f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 15.37/15.21 f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6] 15.37/15.21 f1#(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2#(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2] 15.37/15.21 R = 15.37/15.21 f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 15.37/15.21 f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 15.37/15.21 f2(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6] 15.37/15.21 f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(rnd1, I21, I22, I23, I24, I25, I30, I31, I28, I29) [I32 = I23 /\ I33 = I24 /\ -1 * I32 + I33 <= 0 /\ I30 = I30 /\ I31 = I31 /\ rnd1 = rnd1] 15.37/15.21 f1(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2] 15.37/15.21 15.37/15.21 The dependency graph for this problem is: 15.37/15.21 0 -> 3 15.37/15.21 1 -> 2 15.37/15.21 2 -> 1 15.37/15.21 3 -> 2 15.37/15.21 Where: 15.37/15.21 0) f5#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 15.37/15.21 1) f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 15.37/15.21 2) f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6] 15.37/15.21 3) f1#(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2#(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2] 15.37/15.21 15.37/15.21 We have the following SCCs. 15.37/15.21 { 1, 2 } 15.37/15.21 15.37/15.21 DP problem for innermost termination. 15.37/15.21 P = 15.37/15.21 f4#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 15.37/15.21 f2#(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4#(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6] 15.37/15.21 R = 15.37/15.21 f5(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) -> f1(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 15.37/15.21 f4(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) -> f2(I0, I1, I2, I3, I4, I5, I6, I7, I8, I9) 15.37/15.21 f2(I10, I11, I12, I13, I14, I15, I16, I17, I18, I19) -> f4(I10, I11, I12, I13, I14, rnd6, rnd7, rnd8, I18, I19) [y2 = I13 /\ y3 = I14 /\ 0 <= -1 - y2 + y3 /\ rnd7 = rnd7 /\ rnd8 = rnd8 /\ y1 = I13 /\ rnd6 = rnd6] 15.37/15.21 f2(I20, I21, I22, I23, I24, I25, I26, I27, I28, I29) -> f3(rnd1, I21, I22, I23, I24, I25, I30, I31, I28, I29) [I32 = I23 /\ I33 = I24 /\ -1 * I32 + I33 <= 0 /\ I30 = I30 /\ I31 = I31 /\ rnd1 = rnd1] 15.37/15.21 f1(I34, I35, I36, I37, I38, I39, I40, I41, I42, I43) -> f2(I34, rnd2, rnd3, I37, I38, I39, I40, I41, rnd9, rnd10) [rnd10 = rnd10 /\ rnd9 = rnd9 /\ B0 = B0 /\ rnd3 = rnd3 /\ B1 = B1 /\ rnd2 = rnd2] 15.37/15.21 15.37/18.19 EOF
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