details

property	value
status	complete
benchmark	st88b-succeed.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n031.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	12.7022 seconds
cpu usage	12.6136
user time	6.58159
system time	6.032
max virtual memory	720140.0
max residence set size	9508.0

stage attributes

key	value
starexec-result	MAYBE

output

12.55/12.70 MAYBE 12.55/12.70 12.55/12.70 DP problem for innermost termination. 12.55/12.70 P = 12.55/12.70 f14#(x1, x2, x3) -> f13#(x1, x2, x3) 12.55/12.70 f13#(I0, I1, I2) -> f1#(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] 12.55/12.70 f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] 12.55/12.70 f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] 12.55/12.70 f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] 12.55/12.70 f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] 12.55/12.70 f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] 12.55/12.70 f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] 12.55/12.70 f10#(I21, I22, I23) -> f9#(I21, I22, I23) 12.55/12.70 f9#(I24, I25, I26) -> f10#(I24, I25, I26) 12.55/12.70 f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] 12.55/12.70 f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] 12.55/12.70 f8#(I33, I34, I35) -> f9#(I33, I34, I35) 12.55/12.70 f6#(I36, I37, I38) -> f7#(I36, I37, I38) 12.55/12.70 f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] 12.55/12.70 f1#(I45, I46, I47) -> f2#(I45, I46, I47) 12.55/12.70 R = 12.55/12.70 f14(x1, x2, x3) -> f13(x1, x2, x3) 12.55/12.70 f13(I0, I1, I2) -> f1(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] 12.55/12.70 f3(I3, I4, I5) -> f12(I3, I4, I5) [I3 <= 5] 12.55/12.70 f3(I6, I7, I8) -> f11(I6, I7, I8) [6 <= I6] 12.55/12.70 f12(I9, I10, I11) -> f6(I9, I10, I11) [1 <= I11] 12.55/12.70 f12(I12, I13, I14) -> f11(I12, I13, I14) [I14 <= 0] 12.55/12.70 f11(I15, I16, I17) -> f2(1 + I15, I16, I17) [I15 <= 5] 12.55/12.70 f11(I18, I19, I20) -> f2(1 + I18, I19, I20) [6 <= I18] 12.55/12.70 f10(I21, I22, I23) -> f9(I21, I22, I23) 12.55/12.70 f9(I24, I25, I26) -> f10(I24, I25, I26) 12.55/12.70 f7(I27, I28, I29) -> f1(1, I28, I29) [I27 <= 2] 12.55/12.70 f7(I30, I31, I32) -> f6(-1 + I30, I31, I32) [3 <= I30] 12.55/12.70 f8(I33, I34, I35) -> f9(I33, I34, I35) 12.55/12.70 f6(I36, I37, I38) -> f7(I36, I37, I38) 12.55/12.70 f4(I39, I40, I41) -> f5(I39, I40, I41) 12.55/12.70 f2(I42, I43, I44) -> f3(I42, I43, rnd3) [rnd3 = rnd3] 12.55/12.70 f1(I45, I46, I47) -> f2(I45, I46, I47) 12.55/12.70 12.55/12.70 The dependency graph for this problem is: 12.55/12.70 0 -> 1 12.55/12.70 1 -> 15 12.55/12.70 2 -> 4, 5 12.55/12.70 3 -> 7 12.55/12.70 4 -> 13 12.55/12.70 5 -> 6, 7 12.55/12.70 6 -> 14 12.55/12.70 7 -> 14 12.55/12.70 8 -> 9 12.55/12.70 9 -> 8 12.55/12.70 10 -> 15 12.55/12.70 11 -> 13 12.55/12.70 12 -> 9 12.55/12.70 13 -> 10, 11 12.55/12.70 14 -> 2, 3 12.55/12.70 15 -> 14 12.55/12.70 Where: 12.55/12.70 0) f14#(x1, x2, x3) -> f13#(x1, x2, x3) 12.55/12.70 1) f13#(I0, I1, I2) -> f1#(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] 12.55/12.70 2) f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] 12.55/12.70 3) f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] 12.55/12.70 4) f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] 12.55/12.70 5) f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] 12.55/12.70 6) f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] 12.55/12.70 7) f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] 12.55/12.70 8) f10#(I21, I22, I23) -> f9#(I21, I22, I23) 12.55/12.70 9) f9#(I24, I25, I26) -> f10#(I24, I25, I26) 12.55/12.70 10) f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] 12.55/12.70 11) f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] 12.55/12.70 12) f8#(I33, I34, I35) -> f9#(I33, I34, I35) 12.55/12.70 13) f6#(I36, I37, I38) -> f7#(I36, I37, I38) 12.55/12.70 14) f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] 12.55/12.70 15) f1#(I45, I46, I47) -> f2#(I45, I46, I47) 12.55/12.70 12.55/12.70 We have the following SCCs. 12.55/12.70 { 8, 9 } 12.55/12.70 { 2, 3, 4, 5, 6, 7, 10, 11, 13, 14, 15 } 12.55/12.70 12.55/12.70 DP problem for innermost termination. 12.55/12.70 P = 12.55/12.70 f3#(I3, I4, I5) -> f12#(I3, I4, I5) [I3 <= 5] 12.55/12.70 f3#(I6, I7, I8) -> f11#(I6, I7, I8) [6 <= I6] 12.55/12.70 f12#(I9, I10, I11) -> f6#(I9, I10, I11) [1 <= I11] 12.55/12.70 f12#(I12, I13, I14) -> f11#(I12, I13, I14) [I14 <= 0] 12.55/12.70 f11#(I15, I16, I17) -> f2#(1 + I15, I16, I17) [I15 <= 5] 12.55/12.70 f11#(I18, I19, I20) -> f2#(1 + I18, I19, I20) [6 <= I18] 12.55/12.70 f7#(I27, I28, I29) -> f1#(1, I28, I29) [I27 <= 2] 12.55/12.70 f7#(I30, I31, I32) -> f6#(-1 + I30, I31, I32) [3 <= I30] 12.55/12.70 f6#(I36, I37, I38) -> f7#(I36, I37, I38) 12.55/12.70 f2#(I42, I43, I44) -> f3#(I42, I43, rnd3) [rnd3 = rnd3] 12.55/12.70 f1#(I45, I46, I47) -> f2#(I45, I46, I47) 12.55/12.70 R = 12.55/12.70 f14(x1, x2, x3) -> f13(x1, x2, x3) 12.55/12.70 f13(I0, I1, I2) -> f1(rnd1, rnd2, I2) [y1 = y1 /\ rnd2 = rnd2 /\ rnd1 = rnd2] 12.55/12.70 f3(I3, I4, I5) -> f12(I3, I4, I5) [I3 <= 5] 12.55/12.70 f3(I6, I7, I8) -> f11(I6, I7, I8) [6 <= I6] 12.55/12.70 f12(I9, I10, I11) -> f6(I9, I10, I11) [1 <= I11] 12.55/12.70 f12(I12, I13, I14) -> f11(I12, I13, I14) [I14 <= 0] 12.55/12.70 f11(I15, I16, I17) -> f2(1 + I15, I16, I17) [I15 <= 5] 12.55/12.70 f11(I18, I19, I20) -> f2(1 + I18, I19, I20) [6 <= I18] popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer_Transition_Systems 2019-03-29 01.54