details

property	value
status	complete
benchmark	florian_sas1.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n014.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	19.3621 seconds
cpu usage	19.2316
user time	10.0228
system time	9.20885
max virtual memory	758268.0
max residence set size	13112.0

stage attributes

key	value
starexec-result	MAYBE

output

19.16/19.36 MAYBE 19.16/19.36 19.16/19.36 DP problem for innermost termination. 19.16/19.36 P = 19.16/19.36 f11#(x1, x2, x3, x4) -> f10#(x1, x2, x3, x4) 19.16/19.36 f10#(I0, I1, I2, I3) -> f7#(0, I1, I2, I3) 19.16/19.36 f3#(I4, I5, I6, I7) -> f9#(I4, I5, I6, I7) [1 + I7 <= 0] 19.16/19.36 f3#(I8, I9, I10, I11) -> f9#(I8, I9, I10, I11) [1 <= I11] 19.16/19.36 f3#(I12, I13, I14, I15) -> f2#(I12, I13, I14, I15) [0 <= I15 /\ I15 <= 0] 19.16/19.36 f9#(I16, I17, I18, I19) -> f6#(1 + I16, 1 + I17, I18, I19) 19.16/19.36 f8#(I20, I21, I22, I23) -> f7#(-1 + I20, I21, I22, I23) [1 <= I21] 19.16/19.36 f8#(I24, I25, I26, I27) -> f7#(I24, I25, I26, I27) [I25 <= 0] 19.16/19.36 f2#(I28, I29, I30, I31) -> f8#(I28, I29, I30, I31) 19.16/19.36 f6#(I32, I33, I34, I35) -> f1#(I32, I33, I34, I35) 19.16/19.36 f7#(I36, I37, I38, I39) -> f4#(I36, I37, I38, I39) 19.16/19.36 f4#(I40, I41, I42, I43) -> f6#(1 + I40, 0, I42, I43) [1 + I40 <= I42] 19.16/19.36 f1#(I48, I49, I50, I51) -> f3#(I48, I49, I50, rnd4) [rnd4 = rnd4 /\ 1 + I48 <= I50] 19.16/19.36 f1#(I52, I53, I54, I55) -> f2#(I52, I53, I54, I55) [I54 <= I52] 19.16/19.36 R = 19.16/19.36 f11(x1, x2, x3, x4) -> f10(x1, x2, x3, x4) 19.16/19.36 f10(I0, I1, I2, I3) -> f7(0, I1, I2, I3) 19.16/19.36 f3(I4, I5, I6, I7) -> f9(I4, I5, I6, I7) [1 + I7 <= 0] 19.16/19.36 f3(I8, I9, I10, I11) -> f9(I8, I9, I10, I11) [1 <= I11] 19.16/19.36 f3(I12, I13, I14, I15) -> f2(I12, I13, I14, I15) [0 <= I15 /\ I15 <= 0] 19.16/19.36 f9(I16, I17, I18, I19) -> f6(1 + I16, 1 + I17, I18, I19) 19.16/19.36 f8(I20, I21, I22, I23) -> f7(-1 + I20, I21, I22, I23) [1 <= I21] 19.16/19.36 f8(I24, I25, I26, I27) -> f7(I24, I25, I26, I27) [I25 <= 0] 19.16/19.36 f2(I28, I29, I30, I31) -> f8(I28, I29, I30, I31) 19.16/19.36 f6(I32, I33, I34, I35) -> f1(I32, I33, I34, I35) 19.16/19.36 f7(I36, I37, I38, I39) -> f4(I36, I37, I38, I39) 19.16/19.36 f4(I40, I41, I42, I43) -> f6(1 + I40, 0, I42, I43) [1 + I40 <= I42] 19.16/19.36 f4(I44, I45, I46, I47) -> f5(I44, I45, I46, I47) [I46 <= I44] 19.16/19.36 f1(I48, I49, I50, I51) -> f3(I48, I49, I50, rnd4) [rnd4 = rnd4 /\ 1 + I48 <= I50] 19.16/19.36 f1(I52, I53, I54, I55) -> f2(I52, I53, I54, I55) [I54 <= I52] 19.16/19.36 19.16/19.36 The dependency graph for this problem is: 19.16/19.36 0 -> 1 19.16/19.36 1 -> 10 19.16/19.36 2 -> 5 19.16/19.36 3 -> 5 19.16/19.36 4 -> 8 19.16/19.36 5 -> 9 19.16/19.36 6 -> 10 19.16/19.36 7 -> 10 19.16/19.36 8 -> 6, 7 19.16/19.36 9 -> 12, 13 19.16/19.36 10 -> 11 19.16/19.36 11 -> 9 19.16/19.36 12 -> 2, 3, 4 19.16/19.36 13 -> 8 19.16/19.36 Where: 19.16/19.36 0) f11#(x1, x2, x3, x4) -> f10#(x1, x2, x3, x4) 19.16/19.36 1) f10#(I0, I1, I2, I3) -> f7#(0, I1, I2, I3) 19.16/19.36 2) f3#(I4, I5, I6, I7) -> f9#(I4, I5, I6, I7) [1 + I7 <= 0] 19.16/19.36 3) f3#(I8, I9, I10, I11) -> f9#(I8, I9, I10, I11) [1 <= I11] 19.16/19.36 4) f3#(I12, I13, I14, I15) -> f2#(I12, I13, I14, I15) [0 <= I15 /\ I15 <= 0] 19.16/19.36 5) f9#(I16, I17, I18, I19) -> f6#(1 + I16, 1 + I17, I18, I19) 19.16/19.36 6) f8#(I20, I21, I22, I23) -> f7#(-1 + I20, I21, I22, I23) [1 <= I21] 19.16/19.36 7) f8#(I24, I25, I26, I27) -> f7#(I24, I25, I26, I27) [I25 <= 0] 19.16/19.36 8) f2#(I28, I29, I30, I31) -> f8#(I28, I29, I30, I31) 19.16/19.36 9) f6#(I32, I33, I34, I35) -> f1#(I32, I33, I34, I35) 19.16/19.36 10) f7#(I36, I37, I38, I39) -> f4#(I36, I37, I38, I39) 19.16/19.36 11) f4#(I40, I41, I42, I43) -> f6#(1 + I40, 0, I42, I43) [1 + I40 <= I42] 19.16/19.36 12) f1#(I48, I49, I50, I51) -> f3#(I48, I49, I50, rnd4) [rnd4 = rnd4 /\ 1 + I48 <= I50] 19.16/19.36 13) f1#(I52, I53, I54, I55) -> f2#(I52, I53, I54, I55) [I54 <= I52] 19.16/19.36 19.16/19.36 We have the following SCCs. 19.16/19.36 { 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13 } 19.16/19.36 19.16/19.36 DP problem for innermost termination. 19.16/19.36 P = 19.16/19.36 f3#(I4, I5, I6, I7) -> f9#(I4, I5, I6, I7) [1 + I7 <= 0] 19.16/19.36 f3#(I8, I9, I10, I11) -> f9#(I8, I9, I10, I11) [1 <= I11] 19.16/19.36 f3#(I12, I13, I14, I15) -> f2#(I12, I13, I14, I15) [0 <= I15 /\ I15 <= 0] 19.16/19.36 f9#(I16, I17, I18, I19) -> f6#(1 + I16, 1 + I17, I18, I19) 19.16/19.36 f8#(I20, I21, I22, I23) -> f7#(-1 + I20, I21, I22, I23) [1 <= I21] 19.16/19.36 f8#(I24, I25, I26, I27) -> f7#(I24, I25, I26, I27) [I25 <= 0] 19.16/19.36 f2#(I28, I29, I30, I31) -> f8#(I28, I29, I30, I31) 19.16/19.36 f6#(I32, I33, I34, I35) -> f1#(I32, I33, I34, I35) 19.16/19.36 f7#(I36, I37, I38, I39) -> f4#(I36, I37, I38, I39) 19.16/19.36 f4#(I40, I41, I42, I43) -> f6#(1 + I40, 0, I42, I43) [1 + I40 <= I42] 19.16/19.36 f1#(I48, I49, I50, I51) -> f3#(I48, I49, I50, rnd4) [rnd4 = rnd4 /\ 1 + I48 <= I50] 19.16/19.36 f1#(I52, I53, I54, I55) -> f2#(I52, I53, I54, I55) [I54 <= I52] 19.16/19.36 R = 19.16/19.36 f11(x1, x2, x3, x4) -> f10(x1, x2, x3, x4) 19.16/19.36 f10(I0, I1, I2, I3) -> f7(0, I1, I2, I3) 19.16/19.36 f3(I4, I5, I6, I7) -> f9(I4, I5, I6, I7) [1 + I7 <= 0] 19.16/19.36 f3(I8, I9, I10, I11) -> f9(I8, I9, I10, I11) [1 <= I11] 19.16/19.36 f3(I12, I13, I14, I15) -> f2(I12, I13, I14, I15) [0 <= I15 /\ I15 <= 0] 19.16/19.36 f9(I16, I17, I18, I19) -> f6(1 + I16, 1 + I17, I18, I19) 19.16/19.36 f8(I20, I21, I22, I23) -> f7(-1 + I20, I21, I22, I23) [1 <= I21] 19.16/19.36 f8(I24, I25, I26, I27) -> f7(I24, I25, I26, I27) [I25 <= 0] 19.16/19.36 f2(I28, I29, I30, I31) -> f8(I28, I29, I30, I31) 19.16/19.36 f6(I32, I33, I34, I35) -> f1(I32, I33, I34, I35) 19.16/19.36 f7(I36, I37, I38, I39) -> f4(I36, I37, I38, I39) 19.16/19.36 f4(I40, I41, I42, I43) -> f6(1 + I40, 0, I42, I43) [1 + I40 <= I42] 19.16/19.36 f4(I44, I45, I46, I47) -> f5(I44, I45, I46, I47) [I46 <= I44] 19.16/19.36 f1(I48, I49, I50, I51) -> f3(I48, I49, I50, rnd4) [rnd4 = rnd4 /\ 1 + I48 <= I50] 19.16/19.36 f1(I52, I53, I54, I55) -> f2(I52, I53, I54, I55) [I54 <= I52] 19.16/19.36 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to Integer_Transition_Systems 2019-03-29 01.54