Integer_Transition_Systems 2019-03-29 01.54 pair #432275577

details
property	value
status	complete
benchmark	ex26.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n111.star.cs.uiowa.edu
space	From_T2
run statistics
property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	35.9463 seconds
cpu usage	36.5668
user time	18.6575
system time	17.9093
max virtual memory	764132.0
max residence set size	18988.0
stage attributes
key	value
starexec-result	YES
output
36.50/35.94	YES
36.50/35.94	
36.50/35.94	DP problem for innermost termination.
36.50/35.94	P =
36.50/35.94	  f13#(x1, x2, x3, x4, x5, x6, x7) -> f12#(x1, x2, x3, x4, x5, x6, x7) 
36.50/35.94	  f12#(I0, I1, I2, I3, I4, I5, I6) -> f6#(I0, I1, 0, I3, I4, I5, I6) 
36.50/35.94	  f2#(I7, I8, I9, I10, I11, I12, I13) -> f11#(I7, I8, I9, I10, I11, I9, I13) 
36.50/35.94	  f11#(I14, I15, I16, I17, I18, I19, I20) -> f10#(I14, I15, I16, I17, I18, I19, I20) 
36.50/35.94	  f10#(I21, I22, I23, I24, I25, I26, I27) -> f6#(I21, I22, 1 + I23, I24, I25, I26, I27) 
36.50/35.94	  f4#(I28, I29, I30, I31, I32, I33, I34) -> f8#(I28, I29, I30, I31, I32, I33, I34) 
36.50/35.94	  f8#(I35, I36, I37, I38, I39, I40, I41) -> f7#(I35, I36, I37, I38, I39, I40, I38) [1 + I38 <= I36]
36.50/35.94	  f7#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
36.50/35.94	  f6#(I56, I57, I58, I59, I60, I61, I62) -> f3#(I56, I57, I58, I59, I60, I61, I62) 
36.50/35.94	  f5#(I63, I64, I65, I66, I67, I68, I69) -> f4#(I63, I64, I65, 1 + I66, I67, I68, I69) 
36.50/35.94	  f3#(I70, I71, I72, I73, I74, I75, I76) -> f1#(I70, I71, I72, I73, I72, I75, I76) [1 + I72 <= I70]
36.50/35.94	  f3#(I77, I78, I79, I80, I81, I82, I83) -> f4#(I77, I78, I79, I77, I81, I82, I83) [I77 <= I79]
36.50/35.94	  f1#(I84, I85, I86, I87, I88, I89, I90) -> f2#(I84, I85, I86, I87, I88, I89, I90) 
36.50/35.94	R = 
36.50/35.94	  f13(x1, x2, x3, x4, x5, x6, x7) -> f12(x1, x2, x3, x4, x5, x6, x7) 
36.50/35.94	  f12(I0, I1, I2, I3, I4, I5, I6) -> f6(I0, I1, 0, I3, I4, I5, I6) 
36.50/35.94	  f2(I7, I8, I9, I10, I11, I12, I13) -> f11(I7, I8, I9, I10, I11, I9, I13) 
36.50/35.94	  f11(I14, I15, I16, I17, I18, I19, I20) -> f10(I14, I15, I16, I17, I18, I19, I20) 
36.50/35.94	  f10(I21, I22, I23, I24, I25, I26, I27) -> f6(I21, I22, 1 + I23, I24, I25, I26, I27) 
36.50/35.94	  f4(I28, I29, I30, I31, I32, I33, I34) -> f8(I28, I29, I30, I31, I32, I33, I34) 
36.50/35.94	  f8(I35, I36, I37, I38, I39, I40, I41) -> f7(I35, I36, I37, I38, I39, I40, I38) [1 + I38 <= I36]
36.50/35.94	  f8(I42, I43, I44, I45, I46, I47, I48) -> f9(I42, I43, I44, I45, I46, I47, I48) [I43 <= I45]
36.50/35.94	  f7(I49, I50, I51, I52, I53, I54, I55) -> f5(I49, I50, I51, I52, I53, I54, I55) 
36.50/35.94	  f6(I56, I57, I58, I59, I60, I61, I62) -> f3(I56, I57, I58, I59, I60, I61, I62) 
36.50/35.94	  f5(I63, I64, I65, I66, I67, I68, I69) -> f4(I63, I64, I65, 1 + I66, I67, I68, I69) 
36.50/35.94	  f3(I70, I71, I72, I73, I74, I75, I76) -> f1(I70, I71, I72, I73, I72, I75, I76) [1 + I72 <= I70]
36.50/35.94	  f3(I77, I78, I79, I80, I81, I82, I83) -> f4(I77, I78, I79, I77, I81, I82, I83) [I77 <= I79]
36.50/35.94	  f1(I84, I85, I86, I87, I88, I89, I90) -> f2(I84, I85, I86, I87, I88, I89, I90) 
36.50/35.94	
36.50/35.94	The dependency graph for this problem is:
36.50/35.94	  0 -> 1
36.50/35.94	  1 -> 8
36.50/35.94	  2 -> 3
36.50/35.94	  3 -> 4
36.50/35.94	  4 -> 8
36.50/35.94	  5 -> 6
36.50/35.94	  6 -> 7
36.50/35.94	  7 -> 9
36.50/35.94	  8 -> 10, 11
36.50/35.94	  9 -> 5
36.50/35.94	  10 -> 12
36.50/35.94	  11 -> 5
36.50/35.94	  12 -> 2
36.50/35.94	Where:
36.50/35.94	  0) f13#(x1, x2, x3, x4, x5, x6, x7) -> f12#(x1, x2, x3, x4, x5, x6, x7) 
36.50/35.94	  1) f12#(I0, I1, I2, I3, I4, I5, I6) -> f6#(I0, I1, 0, I3, I4, I5, I6) 
36.50/35.94	  2) f2#(I7, I8, I9, I10, I11, I12, I13) -> f11#(I7, I8, I9, I10, I11, I9, I13) 
36.50/35.94	  3) f11#(I14, I15, I16, I17, I18, I19, I20) -> f10#(I14, I15, I16, I17, I18, I19, I20) 
36.50/35.94	  4) f10#(I21, I22, I23, I24, I25, I26, I27) -> f6#(I21, I22, 1 + I23, I24, I25, I26, I27) 
36.50/35.94	  5) f4#(I28, I29, I30, I31, I32, I33, I34) -> f8#(I28, I29, I30, I31, I32, I33, I34) 
36.50/35.94	  6) f8#(I35, I36, I37, I38, I39, I40, I41) -> f7#(I35, I36, I37, I38, I39, I40, I38) [1 + I38 <= I36]
36.50/35.94	  7) f7#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
36.50/35.94	  8) f6#(I56, I57, I58, I59, I60, I61, I62) -> f3#(I56, I57, I58, I59, I60, I61, I62) 
36.50/35.94	  9) f5#(I63, I64, I65, I66, I67, I68, I69) -> f4#(I63, I64, I65, 1 + I66, I67, I68, I69) 
36.50/35.94	  10) f3#(I70, I71, I72, I73, I74, I75, I76) -> f1#(I70, I71, I72, I73, I72, I75, I76) [1 + I72 <= I70]
36.50/35.94	  11) f3#(I77, I78, I79, I80, I81, I82, I83) -> f4#(I77, I78, I79, I77, I81, I82, I83) [I77 <= I79]
36.50/35.94	  12) f1#(I84, I85, I86, I87, I88, I89, I90) -> f2#(I84, I85, I86, I87, I88, I89, I90) 
36.50/35.94	
36.50/35.94	We have the following SCCs.
36.50/35.94	  { 2, 3, 4, 8, 10, 12 }
36.50/35.94	  { 5, 6, 7, 9 }
36.50/35.94	
36.50/35.94	DP problem for innermost termination.
36.50/35.94	P =
36.50/35.94	  f4#(I28, I29, I30, I31, I32, I33, I34) -> f8#(I28, I29, I30, I31, I32, I33, I34) 
36.50/35.94	  f8#(I35, I36, I37, I38, I39, I40, I41) -> f7#(I35, I36, I37, I38, I39, I40, I38) [1 + I38 <= I36]
36.50/35.94	  f7#(I49, I50, I51, I52, I53, I54, I55) -> f5#(I49, I50, I51, I52, I53, I54, I55) 
36.50/35.94	  f5#(I63, I64, I65, I66, I67, I68, I69) -> f4#(I63, I64, I65, 1 + I66, I67, I68, I69) 
36.50/35.94	R = 
36.50/35.94	  f13(x1, x2, x3, x4, x5, x6, x7) -> f12(x1, x2, x3, x4, x5, x6, x7) 
36.50/35.94	  f12(I0, I1, I2, I3, I4, I5, I6) -> f6(I0, I1, 0, I3, I4, I5, I6) 
36.50/35.94	  f2(I7, I8, I9, I10, I11, I12, I13) -> f11(I7, I8, I9, I10, I11, I9, I13) 
36.50/35.94	  f11(I14, I15, I16, I17, I18, I19, I20) -> f10(I14, I15, I16, I17, I18, I19, I20) 
36.50/35.94	  f10(I21, I22, I23, I24, I25, I26, I27) -> f6(I21, I22, 1 + I23, I24, I25, I26, I27) 
36.50/35.94	  f4(I28, I29, I30, I31, I32, I33, I34) -> f8(I28, I29, I30, I31, I32, I33, I34) 
36.50/35.94	  f8(I35, I36, I37, I38, I39, I40, I41) -> f7(I35, I36, I37, I38, I39, I40, I38) [1 + I38 <= I36]
36.50/35.94	  f8(I42, I43, I44, I45, I46, I47, I48) -> f9(I42, I43, I44, I45, I46, I47, I48) [I43 <= I45]
36.50/35.94	  f7(I49, I50, I51, I52, I53, I54, I55) -> f5(I49, I50, I51, I52, I53, I54, I55) 
36.50/35.94	  f6(I56, I57, I58, I59, I60, I61, I62) -> f3(I56, I57, I58, I59, I60, I61, I62) 
36.50/35.94	  f5(I63, I64, I65, I66, I67, I68, I69) -> f4(I63, I64, I65, 1 + I66, I67, I68, I69) 
36.50/35.94	  f3(I70, I71, I72, I73, I74, I75, I76) -> f1(I70, I71, I72, I73, I72, I75, I76) [1 + I72 <= I70]
36.50/35.94	  f3(I77, I78, I79, I80, I81, I82, I83) -> f4(I77, I78, I79, I77, I81, I82, I83) [I77 <= I79]
36.50/35.94	  f1(I84, I85, I86, I87, I88, I89, I90) -> f2(I84, I85, I86, I87, I88, I89, I90) 
36.50/35.94	
36.50/35.94	We use the extended value criterion with the projection function NU:
36.50/35.94	  NU[f5#(x0,x1,x2,x3,x4,x5,x6)] = x1 - x3 - 2
36.50/35.94	  NU[f7#(x0,x1,x2,x3,x4,x5,x6)] = x1 - x3 - 2
36.50/35.94	  NU[f8#(x0,x1,x2,x3,x4,x5,x6)] = x1 - x3 - 1
36.50/35.94	  NU[f4#(x0,x1,x2,x3,x4,x5,x6)] = x1 - x3 - 1
36.50/35.94	
36.50/35.94	This gives the following inequalities:
36.50/35.94	    ==>  I29 - I31 - 1 >= I29 - I31 - 1
36.50/35.94	  1 + I38 <= I36  ==>  I36 - I38 - 1 > I36 - I38 - 2  with  I36 - I38 - 1 >= 0
36.50/35.94	    ==>  I50 - I52 - 2 >= I50 - I52 - 2
36.50/35.94	    ==>  I64 - I66 - 2 >= I64 - (1 + I66) - 1
36.50/35.94
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions all output return to Integer_Transition_Systems 2019-03-29 01.54