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Integer_Transition_Systems 2019-03-29 01.54 pair #432275619
details
property
value
status
complete
benchmark
small15.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n014.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.71914 seconds
cpu usage
2.76926
user time
1.39414
system time
1.37512
max virtual memory
720576.0
max residence set size
8560.0
stage attributes
key
value
starexec-result
MAYBE
output
2.72/2.71 MAYBE 2.72/2.71 2.72/2.71 DP problem for innermost termination. 2.72/2.71 P = 2.72/2.71 f4#(x1, x2, x3) -> f3#(x1, x2, x3) 2.72/2.71 f3#(I0, I1, I2) -> f1#(I0, I1, I2) 2.72/2.71 f2#(I3, I4, I5) -> f1#(-1 + I3, I4, I5) 2.72/2.71 f2#(I6, I7, I8) -> f1#(I8, -1 + I7, I8) 2.72/2.71 f1#(I9, I10, I11) -> f2#(I9, I10, I11) [1 <= I9] 2.72/2.71 R = 2.72/2.71 f4(x1, x2, x3) -> f3(x1, x2, x3) 2.72/2.71 f3(I0, I1, I2) -> f1(I0, I1, I2) 2.72/2.71 f2(I3, I4, I5) -> f1(-1 + I3, I4, I5) 2.72/2.71 f2(I6, I7, I8) -> f1(I8, -1 + I7, I8) 2.72/2.71 f1(I9, I10, I11) -> f2(I9, I10, I11) [1 <= I9] 2.72/2.71 2.72/2.71 The dependency graph for this problem is: 2.72/2.71 0 -> 1 2.72/2.71 1 -> 4 2.72/2.71 2 -> 4 2.72/2.71 3 -> 4 2.72/2.71 4 -> 2, 3 2.72/2.71 Where: 2.72/2.71 0) f4#(x1, x2, x3) -> f3#(x1, x2, x3) 2.72/2.71 1) f3#(I0, I1, I2) -> f1#(I0, I1, I2) 2.72/2.71 2) f2#(I3, I4, I5) -> f1#(-1 + I3, I4, I5) 2.72/2.71 3) f2#(I6, I7, I8) -> f1#(I8, -1 + I7, I8) 2.72/2.71 4) f1#(I9, I10, I11) -> f2#(I9, I10, I11) [1 <= I9] 2.72/2.71 2.72/2.71 We have the following SCCs. 2.72/2.71 { 2, 3, 4 } 2.72/2.71 2.72/2.71 DP problem for innermost termination. 2.72/2.71 P = 2.72/2.71 f2#(I3, I4, I5) -> f1#(-1 + I3, I4, I5) 2.72/2.71 f2#(I6, I7, I8) -> f1#(I8, -1 + I7, I8) 2.72/2.71 f1#(I9, I10, I11) -> f2#(I9, I10, I11) [1 <= I9] 2.72/2.71 R = 2.72/2.71 f4(x1, x2, x3) -> f3(x1, x2, x3) 2.72/2.71 f3(I0, I1, I2) -> f1(I0, I1, I2) 2.72/2.71 f2(I3, I4, I5) -> f1(-1 + I3, I4, I5) 2.72/2.71 f2(I6, I7, I8) -> f1(I8, -1 + I7, I8) 2.72/2.71 f1(I9, I10, I11) -> f2(I9, I10, I11) [1 <= I9] 2.72/2.71 2.72/2.72 EOF
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