details

property	value
status	complete
benchmark	java_MinusBuiltIn.c.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n070.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	14.3219 seconds
cpu usage	14.0743
user time	6.95013
system time	7.12415
max virtual memory	755604.0
max residence set size	11420.0

stage attributes

key	value
starexec-result	YES

output

14.00/14.32 YES 14.00/14.32 14.00/14.32 DP problem for innermost termination. 14.00/14.32 P = 14.00/14.32 f7#(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f6#(x1, x2, x3, x4, x5, x6, x7, x8, x9) 14.00/14.32 f6#(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f5#(I0, I1, I2, I3, I4, I5, I6, I7, I8) 14.00/14.32 f6#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, I15, I16, I17) 14.00/14.32 f6#(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f3#(I18, I19, I20, I21, I22, I23, I24, I25, I26) 14.00/14.32 f6#(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f1#(I27, I28, I29, I30, I31, I32, I33, I34, I35) 14.00/14.32 f6#(I45, I46, I47, I48, I49, I50, I51, I52, I53) -> f5#(I51, I52, I53, rnd4, rnd5, rnd6, rnd7, rnd8, rnd9) [rnd9 = rnd6 /\ rnd8 = rnd5 /\ rnd7 = rnd4 /\ rnd6 = rnd6 /\ rnd5 = rnd5 /\ rnd4 = rnd4] 14.00/14.32 f5#(I54, I55, I56, I57, I58, I59, I60, I61, I62) -> f4#(I60, I61, I62, I63, I64, I59, I65, I66, 0) [I66 = I64 /\ I65 = I63 /\ I64 = I64 /\ I63 = I63] 14.00/14.32 f4#(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3#(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 f4#(I76, I77, I78, I79, I80, I81, I82, I83, I84) -> f1#(I82, I83, I84, I79, I80, I81, I82, I83, I84) [I82 <= I83] 14.00/14.32 f3#(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4#(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 R = 14.00/14.32 f7(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9) 14.00/14.32 f6(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f5(I0, I1, I2, I3, I4, I5, I6, I7, I8) 14.00/14.32 f6(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, I15, I16, I17) 14.00/14.32 f6(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f3(I18, I19, I20, I21, I22, I23, I24, I25, I26) 14.00/14.32 f6(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f1(I27, I28, I29, I30, I31, I32, I33, I34, I35) 14.00/14.32 f6(I36, I37, I38, I39, I40, I41, I42, I43, I44) -> f2(I36, I37, I38, I39, I40, I41, I42, I43, I44) 14.00/14.32 f6(I45, I46, I47, I48, I49, I50, I51, I52, I53) -> f5(I51, I52, I53, rnd4, rnd5, rnd6, rnd7, rnd8, rnd9) [rnd9 = rnd6 /\ rnd8 = rnd5 /\ rnd7 = rnd4 /\ rnd6 = rnd6 /\ rnd5 = rnd5 /\ rnd4 = rnd4] 14.00/14.32 f5(I54, I55, I56, I57, I58, I59, I60, I61, I62) -> f4(I60, I61, I62, I63, I64, I59, I65, I66, 0) [I66 = I64 /\ I65 = I63 /\ I64 = I64 /\ I63 = I63] 14.00/14.32 f4(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 f4(I76, I77, I78, I79, I80, I81, I82, I83, I84) -> f1(I82, I83, I84, I79, I80, I81, I82, I83, I84) [I82 <= I83] 14.00/14.32 f3(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 f1(I94, I95, I96, I97, I98, I99, I100, I101, I102) -> f2(I100, I101, I102, I103, I104, I105, I106, I107, I108) [I108 = I105 /\ I107 = I104 /\ I106 = I103 /\ I105 = I105 /\ I104 = I104 /\ I103 = I103] 14.00/14.32 14.00/14.32 The dependency graph for this problem is: 14.00/14.32 0 -> 1, 2, 3, 4, 5 14.00/14.32 1 -> 6 14.00/14.32 2 -> 7, 8 14.00/14.32 3 -> 9 14.00/14.32 4 -> 14.00/14.32 5 -> 6 14.00/14.32 6 -> 7, 8 14.00/14.32 7 -> 9 14.00/14.32 8 -> 14.00/14.32 9 -> 7, 8 14.00/14.32 Where: 14.00/14.32 0) f7#(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f6#(x1, x2, x3, x4, x5, x6, x7, x8, x9) 14.00/14.32 1) f6#(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f5#(I0, I1, I2, I3, I4, I5, I6, I7, I8) 14.00/14.32 2) f6#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, I15, I16, I17) 14.00/14.32 3) f6#(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f3#(I18, I19, I20, I21, I22, I23, I24, I25, I26) 14.00/14.32 4) f6#(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f1#(I27, I28, I29, I30, I31, I32, I33, I34, I35) 14.00/14.32 5) f6#(I45, I46, I47, I48, I49, I50, I51, I52, I53) -> f5#(I51, I52, I53, rnd4, rnd5, rnd6, rnd7, rnd8, rnd9) [rnd9 = rnd6 /\ rnd8 = rnd5 /\ rnd7 = rnd4 /\ rnd6 = rnd6 /\ rnd5 = rnd5 /\ rnd4 = rnd4] 14.00/14.32 6) f5#(I54, I55, I56, I57, I58, I59, I60, I61, I62) -> f4#(I60, I61, I62, I63, I64, I59, I65, I66, 0) [I66 = I64 /\ I65 = I63 /\ I64 = I64 /\ I63 = I63] 14.00/14.32 7) f4#(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3#(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 8) f4#(I76, I77, I78, I79, I80, I81, I82, I83, I84) -> f1#(I82, I83, I84, I79, I80, I81, I82, I83, I84) [I82 <= I83] 14.00/14.32 9) f3#(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4#(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 14.00/14.32 We have the following SCCs. 14.00/14.32 { 7, 9 } 14.00/14.32 14.00/14.32 DP problem for innermost termination. 14.00/14.32 P = 14.00/14.32 f4#(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3#(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 f3#(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4#(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 R = 14.00/14.32 f7(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9) 14.00/14.32 f6(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f5(I0, I1, I2, I3, I4, I5, I6, I7, I8) 14.00/14.32 f6(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, I15, I16, I17) 14.00/14.32 f6(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f3(I18, I19, I20, I21, I22, I23, I24, I25, I26) 14.00/14.32 f6(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f1(I27, I28, I29, I30, I31, I32, I33, I34, I35) 14.00/14.32 f6(I36, I37, I38, I39, I40, I41, I42, I43, I44) -> f2(I36, I37, I38, I39, I40, I41, I42, I43, I44) 14.00/14.32 f6(I45, I46, I47, I48, I49, I50, I51, I52, I53) -> f5(I51, I52, I53, rnd4, rnd5, rnd6, rnd7, rnd8, rnd9) [rnd9 = rnd6 /\ rnd8 = rnd5 /\ rnd7 = rnd4 /\ rnd6 = rnd6 /\ rnd5 = rnd5 /\ rnd4 = rnd4] 14.00/14.32 f5(I54, I55, I56, I57, I58, I59, I60, I61, I62) -> f4(I60, I61, I62, I63, I64, I59, I65, I66, 0) [I66 = I64 /\ I65 = I63 /\ I64 = I64 /\ I63 = I63] 14.00/14.32 f4(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 f4(I76, I77, I78, I79, I80, I81, I82, I83, I84) -> f1(I82, I83, I84, I79, I80, I81, I82, I83, I84) [I82 <= I83] 14.00/14.32 f3(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 f1(I94, I95, I96, I97, I98, I99, I100, I101, I102) -> f2(I100, I101, I102, I103, I104, I105, I106, I107, I108) [I108 = I105 /\ I107 = I104 /\ I106 = I103 /\ I105 = I105 /\ I104 = I104 /\ I103 = I103] 14.00/14.32 14.00/14.32 We use the reverse value criterion with the projection function NU: 14.00/14.32 NU[f3#(z1,z2,z3,z4,z5,z6,z7,z8,z9)] = z7 + -1 * (1 + (1 + z8)) 14.00/14.32 NU[f4#(z1,z2,z3,z4,z5,z6,z7,z8,z9)] = z7 + -1 * (1 + z8) 14.00/14.32 14.00/14.32 This gives the following inequalities: 14.00/14.32 1 + I74 <= I73 ==> I73 + -1 * (1 + I74) > I73 + -1 * (1 + (1 + I74)) with I73 + -1 * (1 + I74) >= 0 14.00/14.32 ==> I91 + -1 * (1 + (1 + I92)) >= I91 + -1 * (1 + (1 + I92)) 14.00/14.32 14.00/14.32 We remove all the strictly oriented dependency pairs. 14.00/14.32 14.00/14.32 DP problem for innermost termination. 14.00/14.32 P = 14.00/14.32 f3#(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4#(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 R = 14.00/14.32 f7(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f6(x1, x2, x3, x4, x5, x6, x7, x8, x9) 14.00/14.32 f6(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f5(I0, I1, I2, I3, I4, I5, I6, I7, I8) 14.00/14.32 f6(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, I15, I16, I17) 14.00/14.32 f6(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f3(I18, I19, I20, I21, I22, I23, I24, I25, I26) 14.00/14.32 f6(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f1(I27, I28, I29, I30, I31, I32, I33, I34, I35) 14.00/14.32 f6(I36, I37, I38, I39, I40, I41, I42, I43, I44) -> f2(I36, I37, I38, I39, I40, I41, I42, I43, I44) 14.00/14.32 f6(I45, I46, I47, I48, I49, I50, I51, I52, I53) -> f5(I51, I52, I53, rnd4, rnd5, rnd6, rnd7, rnd8, rnd9) [rnd9 = rnd6 /\ rnd8 = rnd5 /\ rnd7 = rnd4 /\ rnd6 = rnd6 /\ rnd5 = rnd5 /\ rnd4 = rnd4] 14.00/14.32 f5(I54, I55, I56, I57, I58, I59, I60, I61, I62) -> f4(I60, I61, I62, I63, I64, I59, I65, I66, 0) [I66 = I64 /\ I65 = I63 /\ I64 = I64 /\ I63 = I63] 14.00/14.32 f4(I67, I68, I69, I70, I71, I72, I73, I74, I75) -> f3(I73, I74, I75, I70, I71, I72, I73, I74, I75) [1 + I74 <= I73] 14.00/14.32 f4(I76, I77, I78, I79, I80, I81, I82, I83, I84) -> f1(I82, I83, I84, I79, I80, I81, I82, I83, I84) [I82 <= I83] 14.00/14.32 f3(I85, I86, I87, I88, I89, I90, I91, I92, I93) -> f4(I91, I92, I93, I88, I89, I90, I91, 1 + I92, 1 + I93) 14.00/14.32 f1(I94, I95, I96, I97, I98, I99, I100, I101, I102) -> f2(I100, I101, I102, I103, I104, I105, I106, I107, I108) [I108 = I105 /\ I107 = I104 /\ I106 = I103 /\ I105 = I105 /\ I104 = I104 /\ I103 = I103] 14.00/14.32 14.00/14.32 The dependency graph for this problem is: 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job log

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actions

all output return to Integer_Transition_Systems 2019-03-29 01.54