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Integer_Transition_Systems 2019-03-29 01.54 pair #432275904
details
property
value
status
complete
benchmark
n-7.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n009.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
9.15097 seconds
cpu usage
9.19457
user time
4.73778
system time
4.45679
max virtual memory
714692.0
max residence set size
10968.0
stage attributes
key
value
starexec-result
MAYBE
output
9.12/9.15 MAYBE 9.12/9.15 9.12/9.15 DP problem for innermost termination. 9.12/9.15 P = 9.12/9.15 f7#(x1, x2, x3, x4, x5) -> f6#(x1, x2, x3, x4, x5) 9.12/9.15 f4#(I5, I6, I7, I8, I9) -> f1#(I5, I6, 1, 1 + I8, I9) [0 <= I7 /\ I7 <= 0 /\ 0 <= -1 - I8 + I9] 9.12/9.15 f6#(I10, I11, I12, I13, I14) -> f4#(I10, I11, 0, I13, I14) 9.12/9.15 f3#(I21, I22, I23, I24, I25) -> f4#(I21, I22, 0, I24, 1 + I25) 9.12/9.15 f2#(I26, I27, I28, I29, I30) -> f3#(I26, I27, I28, I29, I30) [I27 = I27] 9.12/9.15 f1#(I31, I32, I33, I34, I35) -> f2#(I31, I32, I33, I34, I35) [0 <= -1 - I34 + I35] 9.12/9.15 R = 9.12/9.15 f7(x1, x2, x3, x4, x5) -> f6(x1, x2, x3, x4, x5) 9.12/9.15 f4(I0, I1, I2, I3, I4) -> f5(rnd1, I1, I2, I3, I4) [rnd1 = rnd1 /\ -1 * I3 + I4 <= 0] 9.12/9.15 f4(I5, I6, I7, I8, I9) -> f1(I5, I6, 1, 1 + I8, I9) [0 <= I7 /\ I7 <= 0 /\ 0 <= -1 - I8 + I9] 9.12/9.15 f6(I10, I11, I12, I13, I14) -> f4(I10, I11, 0, I13, I14) 9.12/9.15 f1(I15, I16, I17, I18, I19) -> f5(I20, I16, I17, I18, I19) [I20 = I20 /\ -1 * I18 + I19 <= 0] 9.12/9.15 f3(I21, I22, I23, I24, I25) -> f4(I21, I22, 0, I24, 1 + I25) 9.12/9.15 f2(I26, I27, I28, I29, I30) -> f3(I26, I27, I28, I29, I30) [I27 = I27] 9.12/9.15 f1(I31, I32, I33, I34, I35) -> f2(I31, I32, I33, I34, I35) [0 <= -1 - I34 + I35] 9.12/9.15 9.12/9.15 The dependency graph for this problem is: 9.12/9.15 0 -> 2 9.12/9.15 1 -> 5 9.12/9.15 2 -> 1 9.12/9.15 3 -> 1 9.12/9.15 4 -> 3 9.12/9.15 5 -> 4 9.12/9.15 Where: 9.12/9.15 0) f7#(x1, x2, x3, x4, x5) -> f6#(x1, x2, x3, x4, x5) 9.12/9.15 1) f4#(I5, I6, I7, I8, I9) -> f1#(I5, I6, 1, 1 + I8, I9) [0 <= I7 /\ I7 <= 0 /\ 0 <= -1 - I8 + I9] 9.12/9.15 2) f6#(I10, I11, I12, I13, I14) -> f4#(I10, I11, 0, I13, I14) 9.12/9.15 3) f3#(I21, I22, I23, I24, I25) -> f4#(I21, I22, 0, I24, 1 + I25) 9.12/9.15 4) f2#(I26, I27, I28, I29, I30) -> f3#(I26, I27, I28, I29, I30) [I27 = I27] 9.12/9.15 5) f1#(I31, I32, I33, I34, I35) -> f2#(I31, I32, I33, I34, I35) [0 <= -1 - I34 + I35] 9.12/9.15 9.12/9.15 We have the following SCCs. 9.12/9.15 { 1, 3, 4, 5 } 9.12/9.15 9.12/9.15 DP problem for innermost termination. 9.12/9.15 P = 9.12/9.15 f4#(I5, I6, I7, I8, I9) -> f1#(I5, I6, 1, 1 + I8, I9) [0 <= I7 /\ I7 <= 0 /\ 0 <= -1 - I8 + I9] 9.12/9.15 f3#(I21, I22, I23, I24, I25) -> f4#(I21, I22, 0, I24, 1 + I25) 9.12/9.15 f2#(I26, I27, I28, I29, I30) -> f3#(I26, I27, I28, I29, I30) [I27 = I27] 9.12/9.15 f1#(I31, I32, I33, I34, I35) -> f2#(I31, I32, I33, I34, I35) [0 <= -1 - I34 + I35] 9.12/9.15 R = 9.12/9.15 f7(x1, x2, x3, x4, x5) -> f6(x1, x2, x3, x4, x5) 9.12/9.15 f4(I0, I1, I2, I3, I4) -> f5(rnd1, I1, I2, I3, I4) [rnd1 = rnd1 /\ -1 * I3 + I4 <= 0] 9.12/9.15 f4(I5, I6, I7, I8, I9) -> f1(I5, I6, 1, 1 + I8, I9) [0 <= I7 /\ I7 <= 0 /\ 0 <= -1 - I8 + I9] 9.12/9.15 f6(I10, I11, I12, I13, I14) -> f4(I10, I11, 0, I13, I14) 9.12/9.15 f1(I15, I16, I17, I18, I19) -> f5(I20, I16, I17, I18, I19) [I20 = I20 /\ -1 * I18 + I19 <= 0] 9.12/9.15 f3(I21, I22, I23, I24, I25) -> f4(I21, I22, 0, I24, 1 + I25) 9.12/9.15 f2(I26, I27, I28, I29, I30) -> f3(I26, I27, I28, I29, I30) [I27 = I27] 9.12/9.15 f1(I31, I32, I33, I34, I35) -> f2(I31, I32, I33, I34, I35) [0 <= -1 - I34 + I35] 9.12/9.15 9.16/12.12 EOF
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