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Integer_Transition_Systems 2019-03-29 01.54 pair #432275973
details
property
value
status
complete
benchmark
pearl-necklace.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n043.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
12.5533 seconds
cpu usage
12.508
user time
6.79817
system time
5.70984
max virtual memory
700492.0
max residence set size
8732.0
stage attributes
key
value
starexec-result
YES
output
12.44/12.55 YES 12.44/12.55 12.44/12.55 DP problem for innermost termination. 12.44/12.55 P = 12.44/12.55 f10#(x1, x2, x3, x4, x5) -> f9#(x1, x2, x3, x4, x5) 12.44/12.55 f9#(I0, I1, I2, I3, I4) -> f7#(I0, I1, I2, I3, I4) 12.44/12.55 f8#(I5, I6, I7, I8, I9) -> f7#(I5, I6, I7, I8, I9) 12.44/12.55 f7#(I10, I11, I12, I13, I14) -> f8#(1 + I10, I11, I12, I13, I14) [1 + I10 <= I14] 12.44/12.55 f7#(I15, I16, I17, I18, I19) -> f5#(I15, I15, I17, I18, I19) [I19 <= I15] 12.44/12.55 f6#(I20, I21, I22, I23, I24) -> f5#(I20, I21, I22, I23, I24) 12.44/12.55 f5#(I25, I26, I27, I28, I29) -> f6#(I25, -1 + I26, I27, I28, I29) [1 <= I26] 12.44/12.55 f5#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I31, I33, I34) [I31 <= 0] 12.44/12.55 f4#(I35, I36, I37, I38, I39) -> f3#(I35, I36, I37, I38, I39) 12.44/12.55 f3#(I40, I41, I42, I43, I44) -> f4#(I40, I41, 1 + I42, I43, I44) [1 + I42 <= I44] 12.44/12.55 f3#(I45, I46, I47, I48, I49) -> f1#(I45, I46, I47, I47, I49) [I49 <= I47] 12.44/12.55 f2#(I50, I51, I52, I53, I54) -> f1#(I50, I51, I52, I53, I54) 12.44/12.55 f1#(I55, I56, I57, I58, I59) -> f2#(I55, I56, I57, -1 + I58, I59) [1 <= I58] 12.44/12.55 R = 12.44/12.55 f10(x1, x2, x3, x4, x5) -> f9(x1, x2, x3, x4, x5) 12.44/12.55 f9(I0, I1, I2, I3, I4) -> f7(I0, I1, I2, I3, I4) 12.44/12.55 f8(I5, I6, I7, I8, I9) -> f7(I5, I6, I7, I8, I9) 12.44/12.55 f7(I10, I11, I12, I13, I14) -> f8(1 + I10, I11, I12, I13, I14) [1 + I10 <= I14] 12.44/12.55 f7(I15, I16, I17, I18, I19) -> f5(I15, I15, I17, I18, I19) [I19 <= I15] 12.44/12.55 f6(I20, I21, I22, I23, I24) -> f5(I20, I21, I22, I23, I24) 12.44/12.55 f5(I25, I26, I27, I28, I29) -> f6(I25, -1 + I26, I27, I28, I29) [1 <= I26] 12.44/12.55 f5(I30, I31, I32, I33, I34) -> f3(I30, I31, I31, I33, I34) [I31 <= 0] 12.44/12.55 f4(I35, I36, I37, I38, I39) -> f3(I35, I36, I37, I38, I39) 12.44/12.55 f3(I40, I41, I42, I43, I44) -> f4(I40, I41, 1 + I42, I43, I44) [1 + I42 <= I44] 12.44/12.55 f3(I45, I46, I47, I48, I49) -> f1(I45, I46, I47, I47, I49) [I49 <= I47] 12.44/12.55 f2(I50, I51, I52, I53, I54) -> f1(I50, I51, I52, I53, I54) 12.44/12.55 f1(I55, I56, I57, I58, I59) -> f2(I55, I56, I57, -1 + I58, I59) [1 <= I58] 12.44/12.55 12.44/12.55 The dependency graph for this problem is: 12.44/12.55 0 -> 1 12.44/12.55 1 -> 3, 4 12.44/12.55 2 -> 3, 4 12.44/12.55 3 -> 2 12.44/12.55 4 -> 6, 7 12.44/12.55 5 -> 6, 7 12.44/12.55 6 -> 5 12.44/12.55 7 -> 9, 10 12.44/12.55 8 -> 9, 10 12.44/12.55 9 -> 8 12.44/12.55 10 -> 12 12.44/12.55 11 -> 12 12.44/12.55 12 -> 11 12.44/12.55 Where: 12.44/12.55 0) f10#(x1, x2, x3, x4, x5) -> f9#(x1, x2, x3, x4, x5) 12.44/12.55 1) f9#(I0, I1, I2, I3, I4) -> f7#(I0, I1, I2, I3, I4) 12.44/12.55 2) f8#(I5, I6, I7, I8, I9) -> f7#(I5, I6, I7, I8, I9) 12.44/12.55 3) f7#(I10, I11, I12, I13, I14) -> f8#(1 + I10, I11, I12, I13, I14) [1 + I10 <= I14] 12.44/12.55 4) f7#(I15, I16, I17, I18, I19) -> f5#(I15, I15, I17, I18, I19) [I19 <= I15] 12.44/12.55 5) f6#(I20, I21, I22, I23, I24) -> f5#(I20, I21, I22, I23, I24) 12.44/12.55 6) f5#(I25, I26, I27, I28, I29) -> f6#(I25, -1 + I26, I27, I28, I29) [1 <= I26] 12.44/12.55 7) f5#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I31, I33, I34) [I31 <= 0] 12.44/12.55 8) f4#(I35, I36, I37, I38, I39) -> f3#(I35, I36, I37, I38, I39) 12.44/12.55 9) f3#(I40, I41, I42, I43, I44) -> f4#(I40, I41, 1 + I42, I43, I44) [1 + I42 <= I44] 12.44/12.55 10) f3#(I45, I46, I47, I48, I49) -> f1#(I45, I46, I47, I47, I49) [I49 <= I47] 12.44/12.55 11) f2#(I50, I51, I52, I53, I54) -> f1#(I50, I51, I52, I53, I54) 12.44/12.55 12) f1#(I55, I56, I57, I58, I59) -> f2#(I55, I56, I57, -1 + I58, I59) [1 <= I58] 12.44/12.55 12.44/12.55 We have the following SCCs. 12.44/12.55 { 2, 3 } 12.44/12.55 { 5, 6 } 12.44/12.55 { 8, 9 } 12.44/12.55 { 11, 12 } 12.44/12.55 12.44/12.55 DP problem for innermost termination. 12.44/12.55 P = 12.44/12.55 f2#(I50, I51, I52, I53, I54) -> f1#(I50, I51, I52, I53, I54) 12.44/12.55 f1#(I55, I56, I57, I58, I59) -> f2#(I55, I56, I57, -1 + I58, I59) [1 <= I58] 12.44/12.55 R = 12.44/12.55 f10(x1, x2, x3, x4, x5) -> f9(x1, x2, x3, x4, x5) 12.44/12.55 f9(I0, I1, I2, I3, I4) -> f7(I0, I1, I2, I3, I4) 12.44/12.55 f8(I5, I6, I7, I8, I9) -> f7(I5, I6, I7, I8, I9) 12.44/12.55 f7(I10, I11, I12, I13, I14) -> f8(1 + I10, I11, I12, I13, I14) [1 + I10 <= I14] 12.44/12.55 f7(I15, I16, I17, I18, I19) -> f5(I15, I15, I17, I18, I19) [I19 <= I15] 12.44/12.55 f6(I20, I21, I22, I23, I24) -> f5(I20, I21, I22, I23, I24) 12.44/12.55 f5(I25, I26, I27, I28, I29) -> f6(I25, -1 + I26, I27, I28, I29) [1 <= I26] 12.44/12.55 f5(I30, I31, I32, I33, I34) -> f3(I30, I31, I31, I33, I34) [I31 <= 0] 12.44/12.55 f4(I35, I36, I37, I38, I39) -> f3(I35, I36, I37, I38, I39) 12.44/12.55 f3(I40, I41, I42, I43, I44) -> f4(I40, I41, 1 + I42, I43, I44) [1 + I42 <= I44] 12.44/12.55 f3(I45, I46, I47, I48, I49) -> f1(I45, I46, I47, I47, I49) [I49 <= I47] 12.44/12.55 f2(I50, I51, I52, I53, I54) -> f1(I50, I51, I52, I53, I54) 12.44/12.55 f1(I55, I56, I57, I58, I59) -> f2(I55, I56, I57, -1 + I58, I59) [1 <= I58] 12.44/12.55 12.44/12.55 We use the basic value criterion with the projection function NU: 12.44/12.55 NU[f1#(z1,z2,z3,z4,z5)] = z4 12.44/12.55 NU[f2#(z1,z2,z3,z4,z5)] = z4 12.44/12.55 12.44/12.55 This gives the following inequalities: 12.44/12.55 ==> I53 (>! \union =) I53 12.44/12.55 1 <= I58 ==> I58 >! -1 + I58 12.44/12.55 12.44/12.55 We remove all the strictly oriented dependency pairs. 12.44/12.55 12.44/12.55 DP problem for innermost termination. 12.44/12.55 P = 12.44/12.55 f2#(I50, I51, I52, I53, I54) -> f1#(I50, I51, I52, I53, I54) 12.44/12.55 R =
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