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Integer_Transition_Systems 2019-03-29 01.54 pair #432276003
details
property
value
status
complete
benchmark
refine_disj_problem.t2_fixed.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n149.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.63536 seconds
cpu usage
2.38597
user time
1.26949
system time
1.11647
max virtual memory
689496.0
max residence set size
8564.0
stage attributes
key
value
starexec-result
MAYBE
output
2.33/2.63 MAYBE 2.33/2.63 2.33/2.63 DP problem for innermost termination. 2.33/2.63 P = 2.33/2.63 f6#(x1, x2) -> f1#(x1, x2) 2.33/2.63 f5#(I0, I1) -> f2#(I0, I1) 2.33/2.63 f4#(I2, I3) -> f5#(I2 + I3, I3) 2.33/2.63 f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] 2.33/2.63 f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] 2.33/2.63 f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] 2.33/2.63 f1#(I10, I11) -> f2#(I10, I11) 2.33/2.63 R = 2.33/2.63 f6(x1, x2) -> f1(x1, x2) 2.33/2.63 f5(I0, I1) -> f2(I0, I1) 2.33/2.63 f4(I2, I3) -> f5(I2 + I3, I3) 2.33/2.63 f3(I4, I5) -> f4(I4, I5) [1 <= I5] 2.33/2.63 f3(I6, I7) -> f4(I6, I7) [1 + I7 <= 0] 2.33/2.63 f2(I8, I9) -> f3(I8, I9) [1 <= I8] 2.33/2.63 f1(I10, I11) -> f2(I10, I11) 2.33/2.63 2.33/2.63 The dependency graph for this problem is: 2.33/2.63 0 -> 6 2.33/2.63 1 -> 5 2.33/2.63 2 -> 1 2.33/2.63 3 -> 2 2.33/2.63 4 -> 2 2.33/2.63 5 -> 3, 4 2.33/2.63 6 -> 5 2.33/2.63 Where: 2.33/2.63 0) f6#(x1, x2) -> f1#(x1, x2) 2.33/2.63 1) f5#(I0, I1) -> f2#(I0, I1) 2.33/2.63 2) f4#(I2, I3) -> f5#(I2 + I3, I3) 2.33/2.63 3) f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] 2.33/2.63 4) f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] 2.33/2.63 5) f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] 2.33/2.63 6) f1#(I10, I11) -> f2#(I10, I11) 2.33/2.63 2.33/2.63 We have the following SCCs. 2.33/2.63 { 1, 2, 3, 4, 5 } 2.33/2.63 2.33/2.63 DP problem for innermost termination. 2.33/2.63 P = 2.33/2.63 f5#(I0, I1) -> f2#(I0, I1) 2.33/2.63 f4#(I2, I3) -> f5#(I2 + I3, I3) 2.33/2.63 f3#(I4, I5) -> f4#(I4, I5) [1 <= I5] 2.33/2.63 f3#(I6, I7) -> f4#(I6, I7) [1 + I7 <= 0] 2.33/2.63 f2#(I8, I9) -> f3#(I8, I9) [1 <= I8] 2.33/2.63 R = 2.33/2.63 f6(x1, x2) -> f1(x1, x2) 2.33/2.63 f5(I0, I1) -> f2(I0, I1) 2.33/2.63 f4(I2, I3) -> f5(I2 + I3, I3) 2.33/2.63 f3(I4, I5) -> f4(I4, I5) [1 <= I5] 2.33/2.63 f3(I6, I7) -> f4(I6, I7) [1 + I7 <= 0] 2.33/2.63 f2(I8, I9) -> f3(I8, I9) [1 <= I8] 2.33/2.63 f1(I10, I11) -> f2(I10, I11) 2.33/2.63 2.33/5.61 EOF
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