details

property	value
status	complete
benchmark	211471.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n102.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	7.66408 seconds
cpu usage	18.7913
user time	17.5697
system time	1.22166
max virtual memory	1.9144776E7
max residence set size	3693964.0

stage attributes

key	value
starexec-result	YES

output

10.65/3.49 YES 17.65/5.33 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 17.65/5.33 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 17.65/5.33 17.65/5.33 17.65/5.33 Termination w.r.t. Q of the given QTRS could be proven: 17.65/5.33 17.65/5.33 (0) QTRS 17.65/5.33 (1) QTRSRRRProof [EQUIVALENT, 110 ms] 17.65/5.33 (2) QTRS 17.65/5.33 (3) Overlay + Local Confluence [EQUIVALENT, 11 ms] 17.65/5.33 (4) QTRS 17.65/5.33 (5) DependencyPairsProof [EQUIVALENT, 24 ms] 17.65/5.33 (6) QDP 17.65/5.33 (7) DependencyGraphProof [EQUIVALENT, 1 ms] 17.65/5.33 (8) TRUE 17.65/5.33 17.65/5.33 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (0) 17.65/5.33 Obligation: 17.65/5.33 Q restricted rewrite system: 17.65/5.33 The TRS R consists of the following rules: 17.65/5.33 17.65/5.33 0(x1) -> 1(x1) 17.65/5.33 0(0(x1)) -> 0(x1) 17.65/5.33 3(4(5(x1))) -> 4(3(5(x1))) 17.65/5.33 2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))) -> 0(0(0(1(0(1(1(1(0(1(1(1(1(0(0(0(0(1(0(0(1(1(1(1(0(0(0(0(0(0(0(0(1(0(0(0(1(1(1(1(1(1(1(1(1(0(0(0(0(1(1(1(1(1(1(1(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(1(1(1(1(0(1(0(0(1(0(0(1(1(0(0(0(1(0(1(0(1(0(0(1(1(1(0(1(0(0(0(0(1(0(1(1(1(1(0(0(0(0(1(0(0(0(0(0(0(0(0(0(1(1(1(1(0(1(0(1(0(0(0(0(1(1(0(0(1(1(1(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 17.65/5.33 1(1(0(0(1(1(0(1(0(0(1(0(1(1(1(1(1(0(0(1(0(1(1(1(0(1(0(0(0(0(1(0(1(1(1(1(1(0(0(1(0(0(1(1(0(0(0(0(1(1(0(0(1(0(1(0(0(0(0(0(0(1(0(0(0(1(0(1(1(0(0(1(1(0(1(1(0(1(1(0(1(0(0(1(1(1(0(1(0(0(1(0(0(0(0(0(0(1(1(1(0(1(1(0(0(1(1(0(1(0(0(1(1(0(0(1(0(1(1(0(1(0(1(1(1(0(1(0(1(1(0(0(0(1(0(1(1(0(1(1(0(1(1(0(0(0(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))) 17.65/5.33 17.65/5.33 Q is empty. 17.65/5.33 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (1) QTRSRRRProof (EQUIVALENT) 17.65/5.33 Used ordering: 17.65/5.33 Polynomial interpretation [POLO]: 17.65/5.33 17.65/5.33 POL(0(x_1)) = 2 + x_1 17.65/5.33 POL(1(x_1)) = 1 + x_1 17.65/5.33 POL(2(x_1)) = 17 + x_1 17.65/5.33 POL(3(x_1)) = x_1 17.65/5.33 POL(4(x_1)) = x_1 17.65/5.33 POL(5(x_1)) = x_1 17.65/5.33 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 17.65/5.33 17.65/5.33 0(x1) -> 1(x1) 17.65/5.33 0(0(x1)) -> 0(x1) 17.65/5.33 2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))) -> 0(0(0(1(0(1(1(1(0(1(1(1(1(0(0(0(0(1(0(0(1(1(1(1(0(0(0(0(0(0(0(0(1(0(0(0(1(1(1(1(1(1(1(1(1(0(0(0(0(1(1(1(1(1(1(1(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(1(1(1(1(0(1(0(0(1(0(0(1(1(0(0(0(1(0(1(0(1(0(0(1(1(1(0(1(0(0(0(0(1(0(1(1(1(1(0(0(0(0(1(0(0(0(0(0(0(0(0(0(1(1(1(1(0(1(0(1(0(0(0(0(1(1(0(0(1(1(1(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 17.65/5.33 1(1(0(0(1(1(0(1(0(0(1(0(1(1(1(1(1(0(0(1(0(1(1(1(0(1(0(0(0(0(1(0(1(1(1(1(1(0(0(1(0(0(1(1(0(0(0(0(1(1(0(0(1(0(1(0(0(0(0(0(0(1(0(0(0(1(0(1(1(0(0(1(1(0(1(1(0(1(1(0(1(0(0(1(1(1(0(1(0(0(1(0(0(0(0(0(0(1(1(1(0(1(1(0(0(1(1(0(1(0(0(1(1(0(0(1(0(1(1(0(1(0(1(1(1(0(1(0(1(1(0(0(0(1(0(1(1(0(1(1(0(1(1(0(0(0(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))) 17.65/5.33 17.65/5.33 17.65/5.33 17.65/5.33 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (2) 17.65/5.33 Obligation: 17.65/5.33 Q restricted rewrite system: 17.65/5.33 The TRS R consists of the following rules: 17.65/5.33 17.65/5.33 3(4(5(x1))) -> 4(3(5(x1))) 17.65/5.33 17.65/5.33 Q is empty. 17.65/5.33 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (3) Overlay + Local Confluence (EQUIVALENT) 17.65/5.33 The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (4) 17.65/5.33 Obligation: 17.65/5.33 Q restricted rewrite system: 17.65/5.33 The TRS R consists of the following rules: 17.65/5.33 17.65/5.33 3(4(5(x1))) -> 4(3(5(x1))) 17.65/5.33 17.65/5.33 The set Q consists of the following terms: 17.65/5.33 17.65/5.33 3(4(5(x0))) 17.65/5.33 17.65/5.33 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (5) DependencyPairsProof (EQUIVALENT) 17.65/5.33 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 17.65/5.33 ---------------------------------------- 17.65/5.33 17.65/5.33 (6) 17.65/5.33 Obligation: 17.65/5.33 Q DP problem: 17.65/5.33 The TRS P consists of the following rules: 17.65/5.33 17.65/5.33 3^1(4(5(x1))) -> 3^1(5(x1)) 17.65/5.33 17.65/5.33 The TRS R consists of the following rules: 17.65/5.33 17.65/5.33 3(4(5(x1))) -> 4(3(5(x1))) popout

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all output return to SRS_Standard 2019-03-29 03.29