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SRS_Standard 2019-03-29 03.29 pair #432286140
details
property
value
status
complete
benchmark
211857.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n115.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
8.55937 seconds
cpu usage
32.0009
user time
29.4999
system time
2.50103
max virtual memory
4378468.0
max residence set size
139516.0
stage attributes
key
value
starexec-result
YES
output
31.89/8.53 YES 31.89/8.54 31.89/8.54 Problem: 31.89/8.54 0(0(1(x1))) -> 0(1(2(0(x1)))) 31.89/8.54 0(0(1(x1))) -> 0(3(1(0(x1)))) 31.89/8.54 0(0(1(x1))) -> 1(0(4(0(x1)))) 31.89/8.54 0(0(1(x1))) -> 0(1(3(0(2(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(1(3(0(4(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(2(0(1(2(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(3(0(1(2(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(3(0(3(1(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(4(0(4(1(x1))))) 31.89/8.54 0(0(1(x1))) -> 1(2(0(2(0(x1))))) 31.89/8.54 0(0(1(x1))) -> 1(2(2(0(0(x1))))) 31.89/8.54 0(0(1(x1))) -> 0(0(2(2(1(2(x1)))))) 31.89/8.54 0(0(1(x1))) -> 0(1(2(4(2(0(x1)))))) 31.89/8.54 0(0(1(x1))) -> 1(2(0(3(0(4(x1)))))) 31.89/8.54 0(1(1(x1))) -> 0(2(1(1(x1)))) 31.89/8.54 0(1(1(x1))) -> 0(3(1(1(x1)))) 31.89/8.54 0(1(1(x1))) -> 1(1(3(0(4(x1))))) 31.89/8.54 0(1(1(x1))) -> 1(2(0(2(1(x1))))) 31.89/8.54 0(1(1(x1))) -> 1(0(3(1(2(4(x1)))))) 31.89/8.54 0(1(1(x1))) -> 1(0(4(2(1(2(x1)))))) 31.89/8.54 0(1(1(x1))) -> 1(1(2(4(3(0(x1)))))) 31.89/8.54 0(1(1(x1))) -> 1(2(1(0(4(4(x1)))))) 31.89/8.54 0(1(1(x1))) -> 1(2(2(1(3(0(x1)))))) 31.89/8.54 0(5(1(x1))) -> 0(3(1(5(x1)))) 31.89/8.54 0(5(1(x1))) -> 0(4(5(1(x1)))) 31.89/8.54 0(5(1(x1))) -> 0(2(3(1(5(x1))))) 31.89/8.54 0(5(1(x1))) -> 0(3(1(5(2(x1))))) 31.89/8.54 0(5(1(x1))) -> 0(3(1(2(5(2(x1)))))) 31.89/8.54 5(0(1(x1))) -> 5(1(2(4(0(x1))))) 31.89/8.54 5(0(1(x1))) -> 5(0(2(1(2(4(x1)))))) 31.89/8.54 5(0(1(x1))) -> 5(1(2(3(0(4(x1)))))) 31.89/8.54 0(0(1(5(x1)))) -> 0(4(1(0(5(x1))))) 31.89/8.54 0(0(2(1(x1)))) -> 2(0(3(0(2(1(x1)))))) 31.89/8.54 0(0(2(1(x1)))) -> 2(3(0(2(0(1(x1)))))) 31.89/8.54 0(1(0(1(x1)))) -> 1(0(2(0(1(x1))))) 31.89/8.54 0(1(1(1(x1)))) -> 1(1(3(1(0(x1))))) 31.89/8.54 5(0(1(1(x1)))) -> 1(5(1(2(0(x1))))) 31.89/8.54 5(3(0(1(x1)))) -> 5(1(2(3(0(x1))))) 31.89/8.54 5(3(1(5(x1)))) -> 5(3(1(2(5(x1))))) 31.89/8.54 5(3(2(1(x1)))) -> 1(2(3(5(2(x1))))) 31.89/8.54 5(4(0(1(x1)))) -> 1(2(5(0(4(x1))))) 31.89/8.54 0(0(5(1(5(x1))))) -> 1(2(5(5(0(0(x1)))))) 31.89/8.54 0(5(3(0(1(x1))))) -> 1(0(5(3(0(4(x1)))))) 31.89/8.54 0(5(3(4(1(x1))))) -> 1(0(3(5(4(5(x1)))))) 31.89/8.54 0(5(4(0(1(x1))))) -> 0(1(3(0(4(5(x1)))))) 31.89/8.54 5(4(2(1(1(x1))))) -> 5(4(1(2(1(2(x1)))))) 31.89/8.54 31.89/8.54 Proof: 31.89/8.54 Matrix Interpretation Processor: dim=1 31.89/8.54 31.89/8.54 interpretation: 31.89/8.54 [5](x0) = x0, 31.89/8.54 31.89/8.54 [4](x0) = x0, 31.89/8.54 31.89/8.54 [3](x0) = x0, 31.89/8.54 31.89/8.54 [2](x0) = x0, 31.89/8.54 31.89/8.54 [0](x0) = 2x0, 31.89/8.54 31.89/8.54 [1](x0) = 2x0 + 2 31.89/8.54 orientation: 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 4 = 0(1(2(0(x1)))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 4 = 0(3(1(0(x1)))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 2 = 1(0(4(0(x1)))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 4 = 0(1(3(0(2(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 4 = 0(1(3(0(4(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 8 = 0(2(0(1(2(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 8 = 0(3(0(1(2(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 8 = 0(3(0(3(1(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 8 = 0(4(0(4(1(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 2 = 1(2(0(2(0(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 2 = 1(2(2(0(0(x1))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 8 = 0(0(2(2(1(2(x1)))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 4 = 0(1(2(4(2(0(x1)))))) 31.89/8.54 31.89/8.54 0(0(1(x1))) = 8x1 + 8 >= 8x1 + 2 = 1(2(0(3(0(4(x1)))))) 31.89/8.54 31.89/8.54 0(1(1(x1))) = 8x1 + 12 >= 8x1 + 12 = 0(2(1(1(x1)))) 31.89/8.54 31.89/8.54 0(1(1(x1))) = 8x1 + 12 >= 8x1 + 12 = 0(3(1(1(x1)))) 31.89/8.54 31.89/8.54 0(1(1(x1))) = 8x1 + 12 >= 8x1 + 6 = 1(1(3(0(4(x1))))) 31.89/8.54
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