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SRS_Standard 2019-03-29 03.29 pair #432287131
details
property
value
status
complete
benchmark
264370.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n115.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.89254 seconds
cpu usage
3.61496
user time
3.44589
system time
0.169072
max virtual memory
1.8544872E7
max residence set size
242060.0
stage attributes
key
value
starexec-result
YES
output
3.23/1.78 YES 3.23/1.80 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.23/1.80 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.23/1.80 3.23/1.80 3.23/1.80 Termination w.r.t. Q of the given QTRS could be proven: 3.23/1.80 3.23/1.80 (0) QTRS 3.23/1.80 (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] 3.23/1.80 (2) YES 3.23/1.80 3.23/1.80 3.23/1.80 ---------------------------------------- 3.23/1.80 3.23/1.80 (0) 3.23/1.80 Obligation: 3.23/1.80 Q restricted rewrite system: 3.23/1.80 The TRS R consists of the following rules: 3.23/1.80 3.23/1.80 0(1(2(3(4(x1))))) -> 0(2(1(3(4(x1))))) 3.23/1.80 0(5(1(2(4(3(x1)))))) -> 0(5(2(1(4(3(x1)))))) 3.23/1.80 0(5(2(4(1(3(x1)))))) -> 0(1(5(2(4(3(x1)))))) 3.23/1.80 0(5(3(1(2(4(x1)))))) -> 0(1(5(3(2(4(x1)))))) 3.23/1.80 0(5(4(1(3(2(x1)))))) -> 0(5(4(3(1(2(x1)))))) 3.23/1.80 3.23/1.80 Q is empty. 3.23/1.80 3.23/1.80 ---------------------------------------- 3.23/1.80 3.23/1.80 (1) RFCMatchBoundsTRSProof (EQUIVALENT) 3.23/1.80 Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 0. This implies Q-termination of R. 3.23/1.80 The following rules were used to construct the certificate: 3.23/1.80 3.23/1.80 0(1(2(3(4(x1))))) -> 0(2(1(3(4(x1))))) 3.23/1.80 0(5(1(2(4(3(x1)))))) -> 0(5(2(1(4(3(x1)))))) 3.23/1.80 0(5(2(4(1(3(x1)))))) -> 0(1(5(2(4(3(x1)))))) 3.23/1.80 0(5(3(1(2(4(x1)))))) -> 0(1(5(3(2(4(x1)))))) 3.23/1.80 0(5(4(1(3(2(x1)))))) -> 0(5(4(3(1(2(x1)))))) 3.23/1.80 3.23/1.80 The certificate found is represented by the following graph. 3.23/1.80 The certificate consists of the following enumerated nodes: 3.23/1.80 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26 3.23/1.80 3.23/1.80 Node 1 is start node and node 2 is final node. 3.23/1.80 3.23/1.80 Those nodes are connected through the following edges: 3.23/1.80 3.23/1.80 * 1 to 3 labelled 0_1(0)* 1 to 7 labelled 0_1(0)* 1 to 12 labelled 0_1(0)* 1 to 17 labelled 0_1(0)* 1 to 22 labelled 0_1(0)* 2 to 2 labelled #_1(0)* 3 to 4 labelled 2_1(0)* 4 to 5 labelled 1_1(0)* 5 to 6 labelled 3_1(0)* 6 to 2 labelled 4_1(0)* 7 to 8 labelled 5_1(0)* 8 to 9 labelled 2_1(0)* 9 to 10 labelled 1_1(0)* 10 to 11 labelled 4_1(0)* 11 to 2 labelled 3_1(0)* 12 to 13 labelled 1_1(0)* 13 to 14 labelled 5_1(0)* 14 to 15 labelled 2_1(0)* 15 to 16 labelled 4_1(0)* 16 to 2 labelled 3_1(0)* 17 to 18 labelled 1_1(0)* 18 to 19 labelled 5_1(0)* 19 to 20 labelled 3_1(0)* 20 to 21 labelled 2_1(0)* 21 to 2 labelled 4_1(0)* 22 to 23 labelled 5_1(0)* 23 to 24 labelled 4_1(0)* 24 to 25 labelled 3_1(0)* 25 to 26 labelled 1_1(0)* 26 to 2 labelled 2_1(0) 3.23/1.80 3.23/1.80 3.23/1.80 ---------------------------------------- 3.23/1.80 3.23/1.80 (2) 3.23/1.80 YES 3.60/1.89 EOF
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