details

property	value
status	complete
benchmark	264370.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n113.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.0178 seconds
cpu usage	0.01824
user time	0.006985
system time	0.011255
max virtual memory	113176.0
max residence set size	5208.0

stage attributes

key	value
starexec-result	YES

output

0.00/0.01 YES 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 (VAR v_NonEmpty:S x1:S) 0.00/0.01 (RULES 0.00/0.01 0(1(2(3(4(x1:S))))) -> 0(2(1(3(4(x1:S))))) 0.00/0.01 0(5(1(2(4(3(x1:S)))))) -> 0(5(2(1(4(3(x1:S)))))) 0.00/0.01 0(5(2(4(1(3(x1:S)))))) -> 0(1(5(2(4(3(x1:S)))))) 0.00/0.01 0(5(3(1(2(4(x1:S)))))) -> 0(1(5(3(2(4(x1:S)))))) 0.00/0.01 0(5(4(1(3(2(x1:S)))))) -> 0(5(4(3(1(2(x1:S)))))) 0.00/0.01 ) 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Innermost Equivalent Processor: 0.00/0.01 -> Rules: 0.00/0.01 0(1(2(3(4(x1:S))))) -> 0(2(1(3(4(x1:S))))) 0.00/0.01 0(5(1(2(4(3(x1:S)))))) -> 0(5(2(1(4(3(x1:S)))))) 0.00/0.01 0(5(2(4(1(3(x1:S)))))) -> 0(1(5(2(4(3(x1:S)))))) 0.00/0.01 0(5(3(1(2(4(x1:S)))))) -> 0(1(5(3(2(4(x1:S)))))) 0.00/0.01 0(5(4(1(3(2(x1:S)))))) -> 0(5(4(3(1(2(x1:S)))))) 0.00/0.01 -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. 0.00/0.01 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 Dependency Pairs Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 0(1(2(3(4(x1:S))))) -> 0(2(1(3(4(x1:S))))) 0.00/0.01 0(5(1(2(4(3(x1:S)))))) -> 0(5(2(1(4(3(x1:S)))))) 0.00/0.01 0(5(2(4(1(3(x1:S)))))) -> 0(1(5(2(4(3(x1:S)))))) 0.00/0.01 0(5(3(1(2(4(x1:S)))))) -> 0(1(5(3(2(4(x1:S)))))) 0.00/0.01 0(5(4(1(3(2(x1:S)))))) -> 0(5(4(3(1(2(x1:S)))))) 0.00/0.01 0.00/0.01 Problem 1: 0.00/0.01 0.00/0.01 SCC Processor: 0.00/0.01 -> Pairs: 0.00/0.01 Empty 0.00/0.01 -> Rules: 0.00/0.01 0(1(2(3(4(x1:S))))) -> 0(2(1(3(4(x1:S))))) 0.00/0.01 0(5(1(2(4(3(x1:S)))))) -> 0(5(2(1(4(3(x1:S)))))) 0.00/0.01 0(5(2(4(1(3(x1:S)))))) -> 0(1(5(2(4(3(x1:S)))))) 0.00/0.01 0(5(3(1(2(4(x1:S)))))) -> 0(1(5(3(2(4(x1:S)))))) 0.00/0.01 0(5(4(1(3(2(x1:S)))))) -> 0(5(4(3(1(2(x1:S)))))) 0.00/0.01 ->Strongly Connected Components: 0.00/0.01 There is no strongly connected component 0.00/0.01 0.00/0.01 The problem is finite. 0.00/0.01 EOF popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS_Standard 2019-03-29 03.29