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SRS_Standard 2019-03-29 03.29 pair #432287659
details
property
value
status
complete
benchmark
96563.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n036.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
3.93766 seconds
cpu usage
12.0233
user time
11.6079
system time
0.415321
max virtual memory
3.7649928E7
max residence set size
1360484.0
stage attributes
key
value
starexec-result
YES
output
11.64/3.83 YES 11.64/3.88 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 11.64/3.88 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 11.64/3.88 11.64/3.88 11.64/3.88 Termination w.r.t. Q of the given QTRS could be proven: 11.64/3.88 11.64/3.88 (0) QTRS 11.64/3.88 (1) QTRSRRRProof [EQUIVALENT, 134 ms] 11.64/3.88 (2) QTRS 11.64/3.88 (3) DependencyPairsProof [EQUIVALENT, 86 ms] 11.64/3.88 (4) QDP 11.64/3.88 (5) DependencyGraphProof [EQUIVALENT, 1 ms] 11.64/3.88 (6) TRUE 11.64/3.88 11.64/3.88 11.64/3.88 ---------------------------------------- 11.64/3.88 11.64/3.88 (0) 11.64/3.88 Obligation: 11.64/3.88 Q restricted rewrite system: 11.64/3.88 The TRS R consists of the following rules: 11.64/3.88 11.64/3.88 0(1(2(3(x1)))) -> 0(2(2(3(x1)))) 11.64/3.88 1(1(4(4(5(x1))))) -> 5(1(0(0(5(x1))))) 11.64/3.88 2(3(3(2(5(x1))))) -> 3(5(4(5(5(x1))))) 11.64/3.88 5(1(1(5(3(x1))))) -> 5(1(4(5(3(x1))))) 11.64/3.88 0(2(5(1(1(4(x1)))))) -> 0(3(2(2(4(5(x1)))))) 11.64/3.88 1(2(1(4(0(3(x1)))))) -> 4(2(5(4(5(3(x1)))))) 11.64/3.88 1(5(2(0(4(3(x1)))))) -> 5(0(1(1(1(x1))))) 11.64/3.88 2(2(1(5(4(0(x1)))))) -> 2(3(5(4(0(3(x1)))))) 11.64/3.88 4(0(2(3(1(4(4(x1))))))) -> 4(1(3(0(5(0(5(x1))))))) 11.64/3.88 4(3(5(4(3(2(2(2(x1)))))))) -> 4(1(2(3(4(1(4(x1))))))) 11.64/3.88 0(2(2(2(3(4(3(3(3(x1))))))))) -> 0(5(4(0(5(3(5(5(3(x1))))))))) 11.64/3.88 4(5(3(4(1(1(0(5(2(x1))))))))) -> 4(4(3(1(3(2(0(5(2(x1))))))))) 11.64/3.88 3(3(4(1(0(4(5(1(5(2(x1)))))))))) -> 3(3(4(1(5(0(3(0(2(4(x1)))))))))) 11.64/3.88 2(4(5(4(0(5(5(1(2(1(4(2(x1)))))))))))) -> 4(1(0(1(1(3(3(0(1(4(2(x1))))))))))) 11.64/3.88 1(0(0(4(5(4(3(4(5(1(5(4(0(x1))))))))))))) -> 5(3(3(1(2(1(1(0(3(1(3(x1))))))))))) 11.64/3.88 1(2(2(1(2(3(2(4(4(0(0(3(2(x1))))))))))))) -> 4(4(4(3(2(0(1(3(1(2(2(4(5(x1))))))))))))) 11.64/3.88 4(1(5(4(5(3(3(3(1(2(0(2(0(x1))))))))))))) -> 4(1(4(3(4(4(0(1(3(1(1(5(x1)))))))))))) 11.64/3.88 2(2(3(3(0(2(0(2(5(0(5(5(5(1(0(3(1(x1))))))))))))))))) -> 5(5(5(2(0(2(5(0(0(4(3(2(1(4(3(3(1(x1))))))))))))))))) 11.64/3.88 1(5(1(1(3(0(3(3(3(3(1(1(5(1(5(2(5(2(x1)))))))))))))))))) -> 3(5(4(2(0(5(1(3(4(1(1(2(5(2(4(1(5(2(x1)))))))))))))))))) 11.64/3.88 2(4(3(3(4(2(3(5(4(0(4(0(2(3(0(3(3(0(x1)))))))))))))))))) -> 2(1(3(0(4(4(1(5(2(1(0(3(0(5(0(1(5(x1))))))))))))))))) 11.64/3.88 2(5(5(1(2(3(5(0(3(0(0(3(3(1(0(1(3(2(x1)))))))))))))))))) -> 2(1(5(0(0(1(5(2(2(2(3(1(0(5(0(4(3(3(x1)))))))))))))))))) 11.64/3.88 2(3(5(1(3(0(0(5(0(2(2(4(5(4(0(3(1(4(2(x1))))))))))))))))))) -> 5(2(0(2(0(3(2(3(5(2(2(4(1(3(5(5(1(2(x1)))))))))))))))))) 11.64/3.88 3(2(3(4(1(2(5(5(0(1(2(3(4(0(5(1(4(4(5(4(x1)))))))))))))))))))) -> 3(2(0(1(5(0(1(5(5(1(2(3(0(2(4(2(5(2(2(4(x1)))))))))))))))))))) 11.64/3.88 3(5(5(2(0(4(4(5(5(0(3(5(2(1(2(1(0(2(2(3(x1)))))))))))))))))))) -> 3(1(3(3(0(5(4(2(4(1(2(3(5(0(3(4(5(2(4(3(x1)))))))))))))))))))) 11.64/3.88 4(5(1(4(5(3(1(5(5(3(5(0(2(1(2(4(4(5(1(0(4(x1))))))))))))))))))))) -> 4(4(0(2(1(5(2(0(4(5(2(2(3(5(5(2(2(0(3(5(4(x1))))))))))))))))))))) 11.64/3.88 11.64/3.88 Q is empty. 11.64/3.88 11.64/3.88 ---------------------------------------- 11.64/3.88 11.64/3.88 (1) QTRSRRRProof (EQUIVALENT) 11.64/3.88 Used ordering: 11.64/3.88 Polynomial interpretation [POLO]: 11.64/3.88 11.64/3.88 POL(0(x_1)) = 5 + x_1 11.64/3.88 POL(1(x_1)) = 6 + x_1 11.64/3.88 POL(2(x_1)) = 5 + x_1 11.64/3.88 POL(3(x_1)) = 5 + x_1 11.64/3.88 POL(4(x_1)) = 5 + x_1 11.64/3.88 POL(5(x_1)) = 5 + x_1 11.64/3.88 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 11.64/3.88 11.64/3.88 0(1(2(3(x1)))) -> 0(2(2(3(x1)))) 11.64/3.88 1(1(4(4(5(x1))))) -> 5(1(0(0(5(x1))))) 11.64/3.88 5(1(1(5(3(x1))))) -> 5(1(4(5(3(x1))))) 11.64/3.88 0(2(5(1(1(4(x1)))))) -> 0(3(2(2(4(5(x1)))))) 11.64/3.88 1(2(1(4(0(3(x1)))))) -> 4(2(5(4(5(3(x1)))))) 11.64/3.88 1(5(2(0(4(3(x1)))))) -> 5(0(1(1(1(x1))))) 11.64/3.88 2(2(1(5(4(0(x1)))))) -> 2(3(5(4(0(3(x1)))))) 11.64/3.88 4(3(5(4(3(2(2(2(x1)))))))) -> 4(1(2(3(4(1(4(x1))))))) 11.64/3.88 4(5(3(4(1(1(0(5(2(x1))))))))) -> 4(4(3(1(3(2(0(5(2(x1))))))))) 11.64/3.88 3(3(4(1(0(4(5(1(5(2(x1)))))))))) -> 3(3(4(1(5(0(3(0(2(4(x1)))))))))) 11.64/3.88 2(4(5(4(0(5(5(1(2(1(4(2(x1)))))))))))) -> 4(1(0(1(1(3(3(0(1(4(2(x1))))))))))) 11.64/3.88 1(0(0(4(5(4(3(4(5(1(5(4(0(x1))))))))))))) -> 5(3(3(1(2(1(1(0(3(1(3(x1))))))))))) 11.64/3.88 4(1(5(4(5(3(3(3(1(2(0(2(0(x1))))))))))))) -> 4(1(4(3(4(4(0(1(3(1(1(5(x1)))))))))))) 11.64/3.88 1(5(1(1(3(0(3(3(3(3(1(1(5(1(5(2(5(2(x1)))))))))))))))))) -> 3(5(4(2(0(5(1(3(4(1(1(2(5(2(4(1(5(2(x1)))))))))))))))))) 11.64/3.88 2(4(3(3(4(2(3(5(4(0(4(0(2(3(0(3(3(0(x1)))))))))))))))))) -> 2(1(3(0(4(4(1(5(2(1(0(3(0(5(0(1(5(x1))))))))))))))))) 11.64/3.88 2(3(5(1(3(0(0(5(0(2(2(4(5(4(0(3(1(4(2(x1))))))))))))))))))) -> 5(2(0(2(0(3(2(3(5(2(2(4(1(3(5(5(1(2(x1)))))))))))))))))) 11.64/3.88 4(5(1(4(5(3(1(5(5(3(5(0(2(1(2(4(4(5(1(0(4(x1))))))))))))))))))))) -> 4(4(0(2(1(5(2(0(4(5(2(2(3(5(5(2(2(0(3(5(4(x1))))))))))))))))))))) 11.64/3.88 11.64/3.88 11.64/3.88 11.64/3.88 11.64/3.88 ---------------------------------------- 11.64/3.88 11.64/3.88 (2) 11.64/3.88 Obligation: 11.64/3.88 Q restricted rewrite system: 11.64/3.88 The TRS R consists of the following rules: 11.64/3.88 11.64/3.88 2(3(3(2(5(x1))))) -> 3(5(4(5(5(x1))))) 11.64/3.88 4(0(2(3(1(4(4(x1))))))) -> 4(1(3(0(5(0(5(x1))))))) 11.64/3.88 0(2(2(2(3(4(3(3(3(x1))))))))) -> 0(5(4(0(5(3(5(5(3(x1))))))))) 11.64/3.88 1(2(2(1(2(3(2(4(4(0(0(3(2(x1))))))))))))) -> 4(4(4(3(2(0(1(3(1(2(2(4(5(x1))))))))))))) 11.64/3.88 2(2(3(3(0(2(0(2(5(0(5(5(5(1(0(3(1(x1))))))))))))))))) -> 5(5(5(2(0(2(5(0(0(4(3(2(1(4(3(3(1(x1))))))))))))))))) 11.64/3.88 2(5(5(1(2(3(5(0(3(0(0(3(3(1(0(1(3(2(x1)))))))))))))))))) -> 2(1(5(0(0(1(5(2(2(2(3(1(0(5(0(4(3(3(x1)))))))))))))))))) 11.64/3.88 3(2(3(4(1(2(5(5(0(1(2(3(4(0(5(1(4(4(5(4(x1)))))))))))))))))))) -> 3(2(0(1(5(0(1(5(5(1(2(3(0(2(4(2(5(2(2(4(x1))))))))))))))))))))
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