details

property	value
status	complete
benchmark	96086.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n179.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	9.02208 seconds
cpu usage	12.1709
user time	11.7022
system time	0.468744
max virtual memory	1.9220488E7
max residence set size	1456916.0

stage attributes

key	value
starexec-result	YES

output

11.36/3.87 YES 11.71/3.93 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 11.71/3.93 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 11.71/3.93 11.71/3.93 11.71/3.93 Termination w.r.t. Q of the given QTRS could be proven: 11.71/3.93 11.71/3.93 (0) QTRS 11.71/3.93 (1) QTRSRRRProof [EQUIVALENT, 122 ms] 11.71/3.93 (2) QTRS 11.71/3.93 (3) QTRSRRRProof [EQUIVALENT, 2 ms] 11.71/3.93 (4) QTRS 11.71/3.93 (5) DependencyPairsProof [EQUIVALENT, 17 ms] 11.71/3.93 (6) QDP 11.71/3.93 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 11.71/3.93 (8) TRUE 11.71/3.93 11.71/3.93 11.71/3.93 ---------------------------------------- 11.71/3.93 11.71/3.93 (0) 11.71/3.93 Obligation: 11.71/3.93 Q restricted rewrite system: 11.71/3.93 The TRS R consists of the following rules: 11.71/3.93 11.71/3.93 0(0(1(2(x1)))) -> 2(3(0(x1))) 11.71/3.93 4(2(5(2(x1)))) -> 1(4(0(x1))) 11.71/3.93 4(5(3(4(x1)))) -> 4(4(2(4(x1)))) 11.71/3.93 1(3(5(5(2(x1))))) -> 1(3(2(3(x1)))) 11.71/3.93 5(2(2(1(2(x1))))) -> 0(0(2(3(x1)))) 11.71/3.93 2(2(5(3(2(2(x1)))))) -> 5(1(1(0(3(x1))))) 11.71/3.93 2(5(1(2(1(1(x1)))))) -> 5(2(1(2(4(1(x1)))))) 11.71/3.93 3(4(1(4(2(4(x1)))))) -> 1(3(3(3(x1)))) 11.71/3.93 3(5(2(2(4(5(x1)))))) -> 3(2(4(3(0(x1))))) 11.71/3.93 5(2(1(0(1(5(x1)))))) -> 5(4(2(4(5(1(x1)))))) 11.71/3.93 1(3(5(4(1(2(2(x1))))))) -> 3(3(3(4(4(0(x1)))))) 11.71/3.93 4(5(4(3(0(5(1(x1))))))) -> 4(3(3(5(4(1(x1)))))) 11.71/3.93 2(1(5(2(1(3(4(4(x1)))))))) -> 4(0(3(4(0(1(2(x1))))))) 11.71/3.93 5(4(0(2(2(4(0(4(x1)))))))) -> 3(1(5(1(3(0(4(x1))))))) 11.71/3.93 3(4(2(1(1(2(2(5(4(x1))))))))) -> 3(3(3(1(3(3(4(x1))))))) 11.71/3.93 5(4(4(5(0(1(4(5(4(x1))))))))) -> 1(5(5(0(4(1(4(5(4(x1))))))))) 11.71/3.93 5(2(1(3(1(5(2(5(4(4(x1)))))))))) -> 5(3(4(5(0(1(4(0(3(x1))))))))) 11.71/3.93 2(4(1(2(5(2(4(1(3(2(0(3(x1)))))))))))) -> 4(3(0(4(2(3(4(3(4(2(0(x1))))))))))) 11.71/3.93 0(2(3(5(4(2(2(1(0(3(3(5(0(x1))))))))))))) -> 3(3(1(2(3(0(4(0(0(0(2(0(x1)))))))))))) 11.71/3.93 2(1(0(2(1(4(0(0(2(0(0(0(5(2(x1)))))))))))))) -> 2(2(4(2(1(4(3(0(5(1(3(3(0(x1))))))))))))) 11.71/3.93 4(5(0(3(1(3(2(2(5(2(2(4(1(3(2(x1))))))))))))))) -> 4(5(3(2(1(4(5(0(0(0(4(5(4(0(0(x1))))))))))))))) 11.71/3.93 5(2(2(5(2(4(4(1(2(0(1(1(0(1(1(x1))))))))))))))) -> 5(0(5(4(3(2(1(0(3(3(5(0(4(1(x1)))))))))))))) 11.71/3.93 5(4(2(0(3(3(0(0(4(0(3(2(0(5(1(x1))))))))))))))) -> 5(0(1(0(0(2(1(1(0(3(2(2(1(3(x1)))))))))))))) 11.71/3.93 5(4(1(5(1(5(4(4(2(2(0(4(3(1(5(4(4(3(1(x1))))))))))))))))))) -> 3(0(4(5(1(1(3(5(3(4(4(4(5(1(4(3(3(1(x1)))))))))))))))))) 11.71/3.93 2(0(3(0(2(2(2(0(1(4(2(1(0(4(4(3(3(1(4(4(x1)))))))))))))))))))) -> 5(2(4(1(1(4(5(1(0(1(2(0(3(0(1(2(3(4(3(1(x1)))))))))))))))))))) 11.71/3.93 11.71/3.93 Q is empty. 11.71/3.93 11.71/3.93 ---------------------------------------- 11.71/3.93 11.71/3.93 (1) QTRSRRRProof (EQUIVALENT) 11.71/3.93 Used ordering: 11.71/3.93 Polynomial interpretation [POLO]: 11.71/3.93 11.71/3.93 POL(0(x_1)) = 22 + x_1 11.71/3.93 POL(1(x_1)) = 14 + x_1 11.71/3.93 POL(2(x_1)) = 19 + x_1 11.71/3.93 POL(3(x_1)) = 21 + x_1 11.71/3.93 POL(4(x_1)) = 14 + x_1 11.71/3.93 POL(5(x_1)) = 13 + x_1 11.71/3.93 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 11.71/3.93 11.71/3.93 0(0(1(2(x1)))) -> 2(3(0(x1))) 11.71/3.93 4(2(5(2(x1)))) -> 1(4(0(x1))) 11.71/3.93 4(5(3(4(x1)))) -> 4(4(2(4(x1)))) 11.71/3.93 1(3(5(5(2(x1))))) -> 1(3(2(3(x1)))) 11.71/3.93 2(2(5(3(2(2(x1)))))) -> 5(1(1(0(3(x1))))) 11.71/3.93 3(4(1(4(2(4(x1)))))) -> 1(3(3(3(x1)))) 11.71/3.93 3(5(2(2(4(5(x1)))))) -> 3(2(4(3(0(x1))))) 11.71/3.93 5(2(1(0(1(5(x1)))))) -> 5(4(2(4(5(1(x1)))))) 11.71/3.93 1(3(5(4(1(2(2(x1))))))) -> 3(3(3(4(4(0(x1)))))) 11.71/3.93 4(5(4(3(0(5(1(x1))))))) -> 4(3(3(5(4(1(x1)))))) 11.71/3.93 2(1(5(2(1(3(4(4(x1)))))))) -> 4(0(3(4(0(1(2(x1))))))) 11.71/3.93 5(4(0(2(2(4(0(4(x1)))))))) -> 3(1(5(1(3(0(4(x1))))))) 11.71/3.93 3(4(2(1(1(2(2(5(4(x1))))))))) -> 3(3(3(1(3(3(4(x1))))))) 11.71/3.93 2(4(1(2(5(2(4(1(3(2(0(3(x1)))))))))))) -> 4(3(0(4(2(3(4(3(4(2(0(x1))))))))))) 11.71/3.93 0(2(3(5(4(2(2(1(0(3(3(5(0(x1))))))))))))) -> 3(3(1(2(3(0(4(0(0(0(2(0(x1)))))))))))) 11.71/3.93 2(1(0(2(1(4(0(0(2(0(0(0(5(2(x1)))))))))))))) -> 2(2(4(2(1(4(3(0(5(1(3(3(0(x1))))))))))))) 11.71/3.93 4(5(0(3(1(3(2(2(5(2(2(4(1(3(2(x1))))))))))))))) -> 4(5(3(2(1(4(5(0(0(0(4(5(4(0(0(x1))))))))))))))) 11.71/3.93 5(2(2(5(2(4(4(1(2(0(1(1(0(1(1(x1))))))))))))))) -> 5(0(5(4(3(2(1(0(3(3(5(0(4(1(x1)))))))))))))) 11.71/3.93 5(4(2(0(3(3(0(0(4(0(3(2(0(5(1(x1))))))))))))))) -> 5(0(1(0(0(2(1(1(0(3(2(2(1(3(x1)))))))))))))) 11.71/3.93 5(4(1(5(1(5(4(4(2(2(0(4(3(1(5(4(4(3(1(x1))))))))))))))))))) -> 3(0(4(5(1(1(3(5(3(4(4(4(5(1(4(3(3(1(x1)))))))))))))))))) 11.71/3.93 2(0(3(0(2(2(2(0(1(4(2(1(0(4(4(3(3(1(4(4(x1)))))))))))))))))))) -> 5(2(4(1(1(4(5(1(0(1(2(0(3(0(1(2(3(4(3(1(x1)))))))))))))))))))) 11.71/3.93 11.71/3.93 11.71/3.93 11.71/3.93 11.71/3.93 ---------------------------------------- 11.71/3.93 11.71/3.93 (2) 11.71/3.93 Obligation: 11.71/3.93 Q restricted rewrite system: 11.71/3.93 The TRS R consists of the following rules: 11.71/3.93 11.71/3.93 5(2(2(1(2(x1))))) -> 0(0(2(3(x1)))) popout

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all output return to SRS_Standard 2019-03-29 03.29