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SRS_Standard 2019-03-29 03.29 pair #432287899
details
property
value
status
complete
benchmark
213281.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n086.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
10.7684 seconds
cpu usage
38.3783
user time
37.1127
system time
1.26559
max virtual memory
3.9258872E7
max residence set size
3897432.0
stage attributes
key
value
starexec-result
YES
output
36.83/10.37 YES 38.05/10.67 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 38.05/10.67 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 38.05/10.67 38.05/10.67 38.05/10.67 Termination w.r.t. Q of the given QTRS could be proven: 38.05/10.67 38.05/10.67 (0) QTRS 38.05/10.67 (1) DependencyPairsProof [EQUIVALENT, 166 ms] 38.05/10.67 (2) QDP 38.05/10.67 (3) DependencyGraphProof [EQUIVALENT, 1 ms] 38.05/10.67 (4) QDP 38.05/10.67 (5) QDPOrderProof [EQUIVALENT, 258 ms] 38.05/10.67 (6) QDP 38.05/10.67 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 38.05/10.67 (8) QDP 38.05/10.67 (9) UsableRulesProof [EQUIVALENT, 0 ms] 38.05/10.67 (10) QDP 38.05/10.67 (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] 38.05/10.67 (12) YES 38.05/10.67 38.05/10.67 38.05/10.67 ---------------------------------------- 38.05/10.67 38.05/10.67 (0) 38.05/10.67 Obligation: 38.05/10.67 Q restricted rewrite system: 38.05/10.67 The TRS R consists of the following rules: 38.05/10.67 38.05/10.67 0(1(0(2(x1)))) -> 0(0(3(1(2(x1))))) 38.05/10.67 0(1(3(4(x1)))) -> 0(4(1(0(3(x1))))) 38.05/10.67 0(1(3(4(x1)))) -> 0(4(1(1(3(x1))))) 38.05/10.67 0(1(3(4(x1)))) -> 0(4(1(3(1(x1))))) 38.05/10.67 0(2(1(4(x1)))) -> 0(4(1(2(3(x1))))) 38.05/10.67 0(2(1(4(x1)))) -> 0(4(1(3(2(x1))))) 38.05/10.67 0(2(1(4(x1)))) -> 2(0(4(1(4(x1))))) 38.05/10.67 0(2(1(4(x1)))) -> 5(5(0(4(1(2(x1)))))) 38.05/10.67 0(2(1(5(x1)))) -> 5(0(4(1(2(x1))))) 38.05/10.67 0(2(2(4(x1)))) -> 0(4(2(2(5(x1))))) 38.05/10.67 0(2(2(4(x1)))) -> 0(4(2(5(2(x1))))) 38.05/10.67 3(4(0(2(x1)))) -> 3(0(4(5(2(x1))))) 38.05/10.67 3(4(0(2(x1)))) -> 3(5(0(4(2(x1))))) 38.05/10.67 0(0(1(4(5(x1))))) -> 0(4(1(0(3(5(x1)))))) 38.05/10.67 0(1(0(2(4(x1))))) -> 2(0(0(4(1(1(x1)))))) 38.05/10.67 0(1(2(3(4(x1))))) -> 2(0(4(1(0(3(x1)))))) 38.05/10.67 0(1(3(3(4(x1))))) -> 0(0(3(1(3(4(x1)))))) 38.05/10.67 0(1(4(0(2(x1))))) -> 0(4(1(5(0(2(x1)))))) 38.05/10.67 0(1(4(1(5(x1))))) -> 2(5(0(4(1(1(x1)))))) 38.05/10.67 0(1(4(3(4(x1))))) -> 0(4(0(3(1(4(x1)))))) 38.05/10.67 0(1(4(3(4(x1))))) -> 3(0(4(1(5(4(x1)))))) 38.05/10.67 0(1(4(3(5(x1))))) -> 5(4(5(0(3(1(x1)))))) 38.05/10.67 0(1(5(0(2(x1))))) -> 0(0(4(1(2(5(x1)))))) 38.05/10.67 0(1(5(1(4(x1))))) -> 4(5(0(3(1(1(x1)))))) 38.05/10.67 0(2(1(4(4(x1))))) -> 0(4(1(2(4(3(x1)))))) 38.05/10.67 0(2(1(4(5(x1))))) -> 0(4(1(2(5(2(x1)))))) 38.05/10.67 0(2(1(5(4(x1))))) -> 5(0(2(0(4(1(x1)))))) 38.05/10.67 0(2(4(1(5(x1))))) -> 5(0(4(1(5(2(x1)))))) 38.05/10.67 0(2(4(3(5(x1))))) -> 0(4(5(2(5(3(x1)))))) 38.05/10.67 0(2(5(1(4(x1))))) -> 0(0(5(4(1(2(x1)))))) 38.05/10.67 3(0(1(3(2(x1))))) -> 0(3(1(0(3(2(x1)))))) 38.05/10.67 3(0(2(1(4(x1))))) -> 4(0(4(1(3(2(x1)))))) 38.05/10.67 3(0(2(1(5(x1))))) -> 5(3(2(0(4(1(x1)))))) 38.05/10.67 3(0(4(0(2(x1))))) -> 0(3(4(0(4(2(x1)))))) 38.05/10.67 3(0(4(0(2(x1))))) -> 0(4(1(2(0(3(x1)))))) 38.05/10.67 3(0(5(1(4(x1))))) -> 3(0(4(1(1(5(x1)))))) 38.05/10.67 3(0(5(1(5(x1))))) -> 0(4(1(3(5(5(x1)))))) 38.05/10.67 3(2(4(1(2(x1))))) -> 3(1(2(2(5(4(x1)))))) 38.05/10.67 3(2(4(1(5(x1))))) -> 3(1(4(5(2(5(x1)))))) 38.05/10.67 3(4(0(1(2(x1))))) -> 0(4(2(0(3(1(x1)))))) 38.05/10.67 3(4(0(1(4(x1))))) -> 0(4(1(5(3(4(x1)))))) 38.05/10.67 3(4(0(1(5(x1))))) -> 0(4(1(5(5(3(x1)))))) 38.05/10.67 3(4(0(2(4(x1))))) -> 0(3(4(0(4(2(x1)))))) 38.05/10.67 3(4(1(2(4(x1))))) -> 0(4(1(2(4(3(x1)))))) 38.05/10.67 3(4(1(3(5(x1))))) -> 4(3(0(3(1(5(x1)))))) 38.05/10.67 3(4(3(0(2(x1))))) -> 3(3(0(4(1(2(x1)))))) 38.05/10.67 3(4(5(0(2(x1))))) -> 0(3(0(4(2(5(x1)))))) 38.05/10.67 3(5(0(2(2(x1))))) -> 0(3(2(5(2(5(x1)))))) 38.05/10.67 3(5(2(1(4(x1))))) -> 3(5(1(0(4(2(x1)))))) 38.05/10.67 38.05/10.67 Q is empty. 38.05/10.67 38.05/10.67 ---------------------------------------- 38.05/10.67 38.05/10.67 (1) DependencyPairsProof (EQUIVALENT) 38.05/10.67 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 38.05/10.67 ---------------------------------------- 38.05/10.67 38.05/10.67 (2) 38.05/10.67 Obligation: 38.05/10.67 Q DP problem: 38.05/10.67 The TRS P consists of the following rules: 38.05/10.67 38.05/10.67 0^1(1(0(2(x1)))) -> 0^1(0(3(1(2(x1))))) 38.05/10.67 0^1(1(0(2(x1)))) -> 0^1(3(1(2(x1)))) 38.05/10.67 0^1(1(0(2(x1)))) -> 3^1(1(2(x1))) 38.05/10.67 0^1(1(3(4(x1)))) -> 0^1(4(1(0(3(x1))))) 38.05/10.67 0^1(1(3(4(x1)))) -> 0^1(3(x1)) 38.05/10.67 0^1(1(3(4(x1)))) -> 3^1(x1) 38.05/10.67 0^1(1(3(4(x1)))) -> 0^1(4(1(1(3(x1))))) 38.05/10.67 0^1(1(3(4(x1)))) -> 0^1(4(1(3(1(x1)))))
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