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SRS_Standard 2019-03-29 03.29 pair #432288017
details
property
value
status
complete
benchmark
96274.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n018.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
NaTT
configuration
Default
runtime (wallclock)
19.4623 seconds
cpu usage
19.42
user time
19.33
system time
0.09
max virtual memory
237712.0
max residence set size
8784.0
stage attributes
key
value
starexec-result
YES
output
19.42/19.45 YES 19.42/19.46 Input TRS: 19.42/19.46 1: 0(1(2(3(x1)))) -> 4(4(2(3(x1)))) 19.42/19.46 2: 5(3(3(5(4(x1))))) -> 5(1(0(2(x1)))) 19.42/19.46 3: 2(3(1(5(0(5(x1)))))) -> 2(1(3(5(0(5(x1)))))) 19.42/19.46 4: 5(3(3(5(5(4(x1)))))) -> 4(2(4(3(2(x1))))) 19.42/19.46 5: 5(1(4(5(1(1(5(x1))))))) -> 1(4(0(2(3(2(5(x1))))))) 19.42/19.46 6: 3(3(4(3(1(3(0(5(x1)))))))) -> 3(5(2(4(5(0(5(2(x1)))))))) 19.42/19.46 7: 3(1(2(2(2(1(3(1(3(x1))))))))) -> 1(4(3(1(5(0(2(2(x1)))))))) 19.42/19.46 8: 3(4(2(0(5(2(3(5(3(x1))))))))) -> 3(5(4(4(2(2(0(5(1(x1))))))))) 19.42/19.46 9: 5(5(1(3(3(5(4(0(0(x1))))))))) -> 3(1(0(1(4(2(4(3(x1)))))))) 19.42/19.46 10: 3(0(2(5(1(5(0(1(5(0(x1)))))))))) -> 1(2(2(0(0(4(3(4(4(x1))))))))) 19.42/19.46 11: 3(5(5(4(4(4(2(0(0(3(x1)))))))))) -> 1(1(2(3(2(3(4(1(x1)))))))) 19.42/19.46 12: 3(0(4(3(3(5(0(4(4(0(4(2(x1)))))))))))) -> 3(4(5(5(3(2(0(5(1(4(2(x1))))))))))) 19.42/19.46 13: 5(2(0(4(5(0(2(1(1(1(2(0(x1)))))))))))) -> 3(0(0(2(2(4(5(1(3(1(0(x1))))))))))) 19.42/19.46 14: 5(5(4(3(3(4(5(4(5(0(0(4(5(x1))))))))))))) -> 5(0(1(0(3(1(4(1(2(3(1(x1))))))))))) 19.42/19.46 15: 5(2(1(3(0(2(2(4(5(2(2(0(0(1(x1)))))))))))))) -> 3(4(5(1(4(3(3(5(0(3(0(1(x1)))))))))))) 19.42/19.46 16: 3(1(5(2(5(5(3(3(4(4(5(2(3(2(4(x1))))))))))))))) -> 3(0(5(4(4(4(2(0(0(1(4(3(2(4(x1)))))))))))))) 19.42/19.46 17: 4(5(5(4(3(4(4(2(4(2(4(3(3(3(3(x1))))))))))))))) -> 4(5(0(0(4(4(5(4(4(3(4(0(0(0(x1)))))))))))))) 19.42/19.46 18: 0(1(2(4(3(1(1(4(1(5(0(2(5(3(2(4(3(x1))))))))))))))))) -> 4(2(2(1(3(1(3(0(4(5(1(2(2(5(5(4(1(x1))))))))))))))))) 19.42/19.46 19: 2(4(3(0(4(2(0(0(2(5(1(0(2(0(0(4(4(x1))))))))))))))))) -> 5(4(1(2(1(2(1(0(2(0(4(3(1(0(0(2(x1)))))))))))))))) 19.42/19.46 20: 3(3(3(1(0(2(1(1(5(2(4(0(0(4(5(2(2(0(2(x1))))))))))))))))))) -> 3(2(2(3(1(5(5(5(3(0(3(1(4(3(2(3(1(x1))))))))))))))))) 19.42/19.46 21: 5(3(2(2(5(2(1(3(0(2(4(3(2(5(3(3(0(5(4(x1))))))))))))))))))) -> 1(3(0(3(3(4(5(5(0(5(5(4(0(2(1(1(0(0(2(x1))))))))))))))))))) 19.42/19.46 22: 5(4(5(5(5(2(0(1(2(1(0(1(2(1(5(3(1(3(1(x1))))))))))))))))))) -> 0(0(3(5(3(0(2(0(1(4(0(5(4(3(0(2(4(1(x1)))))))))))))))))) 19.42/19.46 23: 4(0(4(0(5(1(0(3(2(5(3(1(3(0(2(5(3(5(0(0(x1)))))))))))))))))))) -> 1(5(3(5(2(0(5(4(4(5(0(1(4(4(3(1(3(2(5(1(x1)))))))))))))))))))) 19.42/19.46 24: 5(4(2(1(3(2(5(4(2(2(0(0(5(5(1(0(5(1(3(0(x1)))))))))))))))))))) -> 4(4(2(4(0(1(3(2(5(1(3(4(4(0(0(1(1(1(2(0(x1)))))))))))))))))))) 19.42/19.46 25: 3(0(4(5(4(1(4(3(5(5(3(5(4(0(1(4(3(5(0(3(2(x1))))))))))))))))))))) -> 1(2(4(1(1(2(5(4(2(4(0(4(2(5(1(4(2(1(3(1(2(x1))))))))))))))))))))) 19.42/19.46 Number of strict rules: 25 19.42/19.46 Direct POLO(bPol) ... removes: 18 4 15 8 1 16 21 19 17 22 5 10 7 20 25 14 12 23 24 11 9 13 6 2 19.42/19.46 1 w: x1 + 3 19.42/19.46 4 w: x1 + 3 19.42/19.46 5 w: x1 + 5 19.42/19.46 3 w: x1 + 5 19.42/19.46 0 w: x1 + 4 19.42/19.46 2 w: x1 + 3 19.42/19.46 Number of strict rules: 1 19.42/19.46 Direct POLO(bPol) ... removes: 3 19.42/19.46 1 w: x1 + 1 19.42/19.46 4 w: x1 + 1 19.42/19.46 5 w: x1 + 3 19.42/19.46 3 w: 2 * x1 + 9 19.42/19.46 0 w: x1 + 1 19.42/19.46 2 w: x1 + 1 19.42/19.46 Number of strict rules: 0 19.42/19.46 EOF
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