details

property	value
status	complete
benchmark	213218.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n041.star.cs.uiowa.edu
space	ICFP_2010

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.0523199 seconds
cpu usage	0.052922
user time	0.036094
system time	0.016828
max virtual memory	113176.0
max residence set size	9468.0

stage attributes

key	value
starexec-result	YES

output

0.00/0.04 YES 0.00/0.04 0.00/0.04 Problem 1: 0.00/0.04 0.00/0.04 (VAR v_NonEmpty:S x1:S) 0.00/0.04 (RULES 0.00/0.04 0(2(0(1(x1:S)))) -> 0(0(2(4(1(x1:S))))) 0.00/0.04 0(2(3(1(3(x1:S))))) -> 0(3(4(2(1(3(x1:S)))))) 0.00/0.04 0(4(1(5(2(x1:S))))) -> 0(4(2(5(1(1(x1:S)))))) 0.00/0.04 0(1(0(2(2(x1:S))))) -> 0(0(2(1(4(2(x1:S)))))) 0.00/0.04 0(1(0(3(1(x1:S))))) -> 0(3(4(0(1(1(x1:S)))))) 0.00/0.04 0(1(2(0(x1:S)))) -> 0(0(2(1(1(x1:S))))) 0.00/0.04 0(1(2(0(x1:S)))) -> 0(2(1(1(0(x1:S))))) 0.00/0.04 0(1(2(4(x1:S)))) -> 4(0(2(1(1(x1:S))))) 0.00/0.04 0(1(2(1(x1:S)))) -> 0(2(1(1(1(x1:S))))) 0.00/0.04 0(1(2(5(x1:S)))) -> 0(2(5(1(1(x1:S))))) 0.00/0.04 0(1(2(5(x1:S)))) -> 0(4(2(1(5(x1:S))))) 0.00/0.04 0(1(2(x1:S))) -> 0(2(1(1(x1:S)))) 0.00/0.04 0(1(3(1(x1:S)))) -> 0(0(3(1(1(x1:S))))) 0.00/0.04 0(1(3(1(x1:S)))) -> 3(0(2(1(1(1(x1:S)))))) 0.00/0.04 0(1(4(1(x1:S)))) -> 4(0(1(1(1(x1:S))))) 0.00/0.04 0(1(4(5(1(x1:S))))) -> 4(0(2(5(1(1(x1:S)))))) 0.00/0.04 0(1(4(5(x1:S)))) -> 0(4(1(1(5(x1:S))))) 0.00/0.04 0(1(5(0(1(x1:S))))) -> 0(0(1(5(5(1(x1:S)))))) 0.00/0.04 0(5(2(0(4(x1:S))))) -> 0(4(2(5(0(4(x1:S)))))) 0.00/0.04 0(5(3(2(5(x1:S))))) -> 0(4(3(5(2(5(x1:S)))))) 0.00/0.04 0(5(3(2(x1:S)))) -> 0(3(4(2(5(x1:S))))) 0.00/0.04 0(5(3(1(5(x1:S))))) -> 5(0(3(4(1(5(x1:S)))))) 0.00/0.04 0(5(3(1(x1:S)))) -> 5(0(3(1(1(1(x1:S)))))) 0.00/0.04 0(5(1(3(2(x1:S))))) -> 3(0(2(1(1(5(x1:S)))))) 0.00/0.04 2(0(1(3(1(x1:S))))) -> 1(1(4(3(0(2(x1:S)))))) 0.00/0.04 2(0(1(3(5(x1:S))))) -> 2(5(1(1(0(3(x1:S)))))) 0.00/0.04 2(0(1(5(3(x1:S))))) -> 2(1(1(3(0(5(x1:S)))))) 0.00/0.04 2(3(2(0(x1:S)))) -> 2(2(1(3(0(x1:S))))) 0.00/0.04 2(3(1(0(1(x1:S))))) -> 0(3(2(1(1(5(x1:S)))))) 0.00/0.04 2(3(1(4(1(x1:S))))) -> 3(4(2(5(1(1(x1:S)))))) 0.00/0.04 2(3(1(x1:S))) -> 3(4(2(1(x1:S)))) 0.00/0.04 2(3(5(1(2(x1:S))))) -> 2(3(2(1(5(1(x1:S)))))) 0.00/0.04 2(4(5(2(x1:S)))) -> 2(1(4(2(5(x1:S))))) 0.00/0.04 3(0(1(2(0(x1:S))))) -> 3(4(0(2(1(0(x1:S)))))) 0.00/0.04 3(0(1(2(x1:S)))) -> 3(4(0(2(1(x1:S))))) 0.00/0.04 3(2(0(1(0(x1:S))))) -> 3(2(1(5(0(0(x1:S)))))) 0.00/0.04 3(2(3(5(1(x1:S))))) -> 3(3(4(2(1(5(x1:S)))))) 0.00/0.04 3(5(3(1(3(x1:S))))) -> 3(5(4(3(1(3(x1:S)))))) 0.00/0.04 4(0(3(3(1(x1:S))))) -> 0(3(4(3(1(1(x1:S)))))) 0.00/0.04 4(4(3(2(5(x1:S))))) -> 3(4(2(4(1(5(x1:S)))))) 0.00/0.04 4(4(3(2(x1:S)))) -> 4(3(4(2(1(x1:S))))) 0.00/0.04 4(5(0(5(2(x1:S))))) -> 0(4(2(1(5(5(x1:S)))))) 0.00/0.04 4(5(2(3(1(x1:S))))) -> 5(3(4(3(2(1(x1:S)))))) 0.00/0.04 4(5(2(5(2(x1:S))))) -> 4(2(5(5(2(1(x1:S)))))) 0.00/0.04 4(5(3(2(x1:S)))) -> 3(4(2(5(4(x1:S))))) 0.00/0.04 4(5(3(2(x1:S)))) -> 3(5(4(2(1(x1:S))))) 0.00/0.04 4(5(3(1(x1:S)))) -> 3(5(4(4(1(x1:S))))) 0.00/0.04 4(5(3(1(x1:S)))) -> 4(3(1(5(1(x1:S))))) 0.00/0.04 4(5(3(5(1(x1:S))))) -> 4(5(5(4(3(1(x1:S)))))) 0.00/0.04 ) 0.00/0.04 0.00/0.04 Problem 1: 0.00/0.04 0.00/0.04 Dependency Pairs Processor: 0.00/0.04 -> Pairs: 0.00/0.04 0#(2(3(1(3(x1:S))))) -> 0#(3(4(2(1(3(x1:S)))))) 0.00/0.04 0#(2(3(1(3(x1:S))))) -> 2#(1(3(x1:S))) 0.00/0.04 0#(2(3(1(3(x1:S))))) -> 3#(4(2(1(3(x1:S))))) 0.00/0.04 0#(2(3(1(3(x1:S))))) -> 4#(2(1(3(x1:S)))) 0.00/0.04 0#(1(0(2(2(x1:S))))) -> 0#(0(2(1(4(2(x1:S)))))) 0.00/0.04 0#(1(0(2(2(x1:S))))) -> 0#(2(1(4(2(x1:S))))) 0.00/0.04 0#(1(0(2(2(x1:S))))) -> 2#(1(4(2(x1:S)))) 0.00/0.04 0#(1(0(2(2(x1:S))))) -> 4#(2(x1:S)) 0.00/0.04 0#(1(2(0(x1:S)))) -> 0#(2(1(1(0(x1:S))))) 0.00/0.04 0#(1(2(0(x1:S)))) -> 2#(1(1(0(x1:S)))) 0.00/0.04 0#(5(2(0(4(x1:S))))) -> 0#(4(2(5(0(4(x1:S)))))) 0.00/0.04 0#(5(2(0(4(x1:S))))) -> 2#(5(0(4(x1:S)))) 0.00/0.04 0#(5(2(0(4(x1:S))))) -> 4#(2(5(0(4(x1:S))))) 0.00/0.04 2#(0(1(3(1(x1:S))))) -> 0#(2(x1:S)) 0.00/0.04 2#(0(1(3(1(x1:S))))) -> 2#(x1:S) 0.00/0.04 2#(0(1(3(1(x1:S))))) -> 3#(0(2(x1:S))) 0.00/0.04 2#(0(1(3(1(x1:S))))) -> 4#(3(0(2(x1:S)))) 0.00/0.04 2#(0(1(3(5(x1:S))))) -> 0#(3(x1:S)) 0.00/0.04 2#(0(1(3(5(x1:S))))) -> 2#(5(1(1(0(3(x1:S)))))) 0.00/0.04 2#(0(1(3(5(x1:S))))) -> 3#(x1:S) 0.00/0.04 2#(0(1(5(3(x1:S))))) -> 0#(5(x1:S)) 0.00/0.04 2#(0(1(5(3(x1:S))))) -> 2#(1(1(3(0(5(x1:S)))))) 0.00/0.04 2#(0(1(5(3(x1:S))))) -> 3#(0(5(x1:S))) 0.00/0.04 2#(3(2(0(x1:S)))) -> 2#(2(1(3(0(x1:S))))) 0.00/0.04 2#(3(2(0(x1:S)))) -> 2#(1(3(0(x1:S)))) 0.00/0.04 2#(3(2(0(x1:S)))) -> 3#(0(x1:S)) 0.00/0.04 3#(0(1(2(0(x1:S))))) -> 0#(2(1(0(x1:S)))) 0.00/0.04 3#(0(1(2(0(x1:S))))) -> 2#(1(0(x1:S))) 0.00/0.04 3#(0(1(2(0(x1:S))))) -> 3#(4(0(2(1(0(x1:S)))))) 0.00/0.04 3#(0(1(2(0(x1:S))))) -> 4#(0(2(1(0(x1:S))))) 0.00/0.04 3#(2(0(1(0(x1:S))))) -> 0#(0(x1:S)) 0.00/0.04 3#(2(0(1(0(x1:S))))) -> 2#(1(5(0(0(x1:S))))) 0.00/0.04 3#(2(0(1(0(x1:S))))) -> 3#(2(1(5(0(0(x1:S)))))) 0.00/0.04 3#(5(3(1(3(x1:S))))) -> 3#(5(4(3(1(3(x1:S)))))) 0.00/0.04 3#(5(3(1(3(x1:S))))) -> 4#(3(1(3(x1:S)))) 0.00/0.04 4#(5(3(2(x1:S)))) -> 2#(5(4(x1:S))) 0.00/0.04 4#(5(3(2(x1:S)))) -> 3#(4(2(5(4(x1:S))))) 0.00/0.04 4#(5(3(2(x1:S)))) -> 4#(2(5(4(x1:S)))) 0.00/0.04 4#(5(3(2(x1:S)))) -> 4#(x1:S) popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS_Standard 2019-03-29 03.29