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SRS_Standard 2019-03-29 03.29 pair #432289435
details
property
value
status
complete
benchmark
18.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n046.star.cs.uiowa.edu
space
Bouchare_06
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
6.73287 seconds
cpu usage
22.9526
user time
21.8157
system time
1.13688
max virtual memory
3.9686192E7
max residence set size
3560928.0
stage attributes
key
value
starexec-result
YES
output
22.58/6.61 YES 22.64/6.63 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 22.64/6.63 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 22.64/6.63 22.64/6.63 22.64/6.63 Termination w.r.t. Q of the given QTRS could be proven: 22.64/6.63 22.64/6.63 (0) QTRS 22.64/6.63 (1) DependencyPairsProof [EQUIVALENT, 31 ms] 22.64/6.63 (2) QDP 22.64/6.63 (3) QDPOrderProof [EQUIVALENT, 137 ms] 22.64/6.63 (4) QDP 22.64/6.63 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 22.64/6.63 (6) QDP 22.64/6.63 (7) QDPOrderProof [EQUIVALENT, 0 ms] 22.64/6.63 (8) QDP 22.64/6.63 (9) PisEmptyProof [EQUIVALENT, 0 ms] 22.64/6.63 (10) YES 22.64/6.63 22.64/6.63 22.64/6.63 ---------------------------------------- 22.64/6.63 22.64/6.63 (0) 22.64/6.63 Obligation: 22.64/6.63 Q restricted rewrite system: 22.64/6.63 The TRS R consists of the following rules: 22.64/6.63 22.64/6.63 a(b(a(x1))) -> b(b(a(x1))) 22.64/6.63 b(b(b(x1))) -> b(a(x1)) 22.64/6.63 b(b(x1)) -> a(a(a(x1))) 22.64/6.63 22.64/6.63 Q is empty. 22.64/6.63 22.64/6.63 ---------------------------------------- 22.64/6.63 22.64/6.63 (1) DependencyPairsProof (EQUIVALENT) 22.64/6.63 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 22.64/6.63 ---------------------------------------- 22.64/6.63 22.64/6.63 (2) 22.64/6.63 Obligation: 22.64/6.63 Q DP problem: 22.64/6.63 The TRS P consists of the following rules: 22.64/6.63 22.64/6.63 A(b(a(x1))) -> B(b(a(x1))) 22.64/6.63 B(b(b(x1))) -> B(a(x1)) 22.64/6.63 B(b(b(x1))) -> A(x1) 22.64/6.63 B(b(x1)) -> A(a(a(x1))) 22.64/6.63 B(b(x1)) -> A(a(x1)) 22.64/6.63 B(b(x1)) -> A(x1) 22.64/6.63 22.64/6.63 The TRS R consists of the following rules: 22.64/6.63 22.64/6.63 a(b(a(x1))) -> b(b(a(x1))) 22.64/6.63 b(b(b(x1))) -> b(a(x1)) 22.64/6.63 b(b(x1)) -> a(a(a(x1))) 22.64/6.63 22.64/6.63 Q is empty. 22.64/6.63 We have to consider all minimal (P,Q,R)-chains. 22.64/6.63 ---------------------------------------- 22.64/6.63 22.64/6.63 (3) QDPOrderProof (EQUIVALENT) 22.64/6.63 We use the reduction pair processor [LPAR04,JAR06]. 22.64/6.63 22.64/6.63 22.64/6.63 The following pairs can be oriented strictly and are deleted. 22.64/6.63 22.64/6.63 A(b(a(x1))) -> B(b(a(x1))) 22.64/6.63 The remaining pairs can at least be oriented weakly. 22.64/6.63 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 22.64/6.63 22.64/6.63 <<< 22.64/6.63 POL(A(x_1)) = [[0A]] + [[0A, -I, 1A]] * x_1 22.64/6.63 >>> 22.64/6.63 22.64/6.63 <<< 22.64/6.63 POL(b(x_1)) = [[-I], [0A], [-I]] + [[0A, -I, 1A], [-I, 0A, -I], [0A, 0A, 0A]] * x_1 22.64/6.63 >>> 22.64/6.63 22.64/6.63 <<< 22.64/6.63 POL(a(x_1)) = [[-I], [0A], [-I]] + [[0A, -I, 1A], [-I, -I, -I], [-I, -I, 0A]] * x_1 22.64/6.63 >>> 22.64/6.63 22.64/6.63 <<< 22.64/6.63 POL(B(x_1)) = [[0A]] + [[0A, -I, -I]] * x_1 22.64/6.63 >>> 22.64/6.63 22.64/6.63 22.64/6.63 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 22.64/6.63 22.64/6.63 b(b(b(x1))) -> b(a(x1)) 22.64/6.63 b(b(x1)) -> a(a(a(x1))) 22.64/6.63 a(b(a(x1))) -> b(b(a(x1))) 22.64/6.63 22.64/6.63 22.64/6.63 ---------------------------------------- 22.64/6.63 22.64/6.63 (4) 22.64/6.63 Obligation: 22.64/6.63 Q DP problem:
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