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SRS_Standard 2019-03-29 03.29 pair #432289597
details
property
value
status
complete
benchmark
size-12-alpha-3-num-194.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n051.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
7.12008 seconds
cpu usage
24.1203
user time
22.9834
system time
1.1369
max virtual memory
1.2027892E8
max residence set size
3452348.0
stage attributes
key
value
starexec-result
YES
output
23.51/6.91 YES 23.78/7.01 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 23.78/7.01 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 23.78/7.01 23.78/7.01 23.78/7.01 Termination w.r.t. Q of the given QTRS could be proven: 23.78/7.01 23.78/7.01 (0) QTRS 23.78/7.01 (1) QTRS Reverse [EQUIVALENT, 0 ms] 23.78/7.01 (2) QTRS 23.78/7.01 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 23.78/7.01 (4) QDP 23.78/7.01 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 23.78/7.01 (6) QDP 23.78/7.01 (7) QDPOrderProof [EQUIVALENT, 126 ms] 23.78/7.01 (8) QDP 23.78/7.01 (9) QDPOrderProof [EQUIVALENT, 0 ms] 23.78/7.01 (10) QDP 23.78/7.01 (11) PisEmptyProof [EQUIVALENT, 0 ms] 23.78/7.01 (12) YES 23.78/7.01 23.78/7.01 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (0) 23.78/7.01 Obligation: 23.78/7.01 Q restricted rewrite system: 23.78/7.01 The TRS R consists of the following rules: 23.78/7.01 23.78/7.01 a(x1) -> x1 23.78/7.01 a(b(x1)) -> b(b(a(a(c(x1))))) 23.78/7.01 b(b(x1)) -> x1 23.78/7.01 c(c(x1)) -> x1 23.78/7.01 23.78/7.01 Q is empty. 23.78/7.01 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (1) QTRS Reverse (EQUIVALENT) 23.78/7.01 We applied the QTRS Reverse Processor [REVERSE]. 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (2) 23.78/7.01 Obligation: 23.78/7.01 Q restricted rewrite system: 23.78/7.01 The TRS R consists of the following rules: 23.78/7.01 23.78/7.01 a(x1) -> x1 23.78/7.01 b(a(x1)) -> c(a(a(b(b(x1))))) 23.78/7.01 b(b(x1)) -> x1 23.78/7.01 c(c(x1)) -> x1 23.78/7.01 23.78/7.01 Q is empty. 23.78/7.01 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (3) DependencyPairsProof (EQUIVALENT) 23.78/7.01 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (4) 23.78/7.01 Obligation: 23.78/7.01 Q DP problem: 23.78/7.01 The TRS P consists of the following rules: 23.78/7.01 23.78/7.01 B(a(x1)) -> C(a(a(b(b(x1))))) 23.78/7.01 B(a(x1)) -> A(a(b(b(x1)))) 23.78/7.01 B(a(x1)) -> A(b(b(x1))) 23.78/7.01 B(a(x1)) -> B(b(x1)) 23.78/7.01 B(a(x1)) -> B(x1) 23.78/7.01 23.78/7.01 The TRS R consists of the following rules: 23.78/7.01 23.78/7.01 a(x1) -> x1 23.78/7.01 b(a(x1)) -> c(a(a(b(b(x1))))) 23.78/7.01 b(b(x1)) -> x1 23.78/7.01 c(c(x1)) -> x1 23.78/7.01 23.78/7.01 Q is empty. 23.78/7.01 We have to consider all minimal (P,Q,R)-chains. 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (5) DependencyGraphProof (EQUIVALENT) 23.78/7.01 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 3 less nodes. 23.78/7.01 ---------------------------------------- 23.78/7.01 23.78/7.01 (6) 23.78/7.01 Obligation: 23.78/7.01 Q DP problem: 23.78/7.01 The TRS P consists of the following rules: 23.78/7.01 23.78/7.01 B(a(x1)) -> B(x1) 23.78/7.01 B(a(x1)) -> B(b(x1)) 23.78/7.01 23.78/7.01 The TRS R consists of the following rules: 23.78/7.01 23.78/7.01 a(x1) -> x1 23.78/7.01 b(a(x1)) -> c(a(a(b(b(x1))))) 23.78/7.01 b(b(x1)) -> x1 23.78/7.01 c(c(x1)) -> x1
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